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The question is from CAT Ratio, Mixtures and Averages. Another question on possible values. We need to find out the minimum and maximum average based on the given details. CAT exam is known to test on basics rather than high funda ideas. A range of CAT questions can be asked from Ratios and Proportions, Mixtures, Alligations and Averages. Make sure you master the topics. 2IIMs CAT questions bank provides you with CAT questions that can help you gear for CAT Exam CAT 2020.

A: Highest score: 25 Lowest score: 15
B: Highest score: 32 Lowest score: 24

  1. 25 and 25
  2. 22.5 and 25
  3. 23.33 and 26
  4. 23.33 and 25

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Explanatory Answer

Method of solving this CAT Question from Ratio, Mixtures and Averages: How the individual data points affect the average?

For minimum, teams with minimum score would be transferred from A to B
So, total score transferred = 15 * 5 = 75
B (Minimum Average) = \\frac{(25*25 + 75)}{30}\\) = 23.33
For maximum, teams with maximum score would be transferred from A to B
So, total score transferred = 25 * 5 = 125
B (Maximum Average) = \\frac{(25*25 + 125)}{30}\\) = 25

The question is "What can be the minimum and maximum value of B’s average if 5 teams are transferred from A to B?"

Hence, the answer is "23.33 and 25".

Choice D is the correct answer.


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