PRIORITY 
       [0001]    This application claims priority under 35 U.S.C. §119(a) to a Chinese application filed in the State Intellectual Property Office of China on Aug. 15, 2008 and assigned Serial No. 200810213230.0, and is a continuation application of U.S. patent application Ser. No. 12/542,310, filed Aug. 17, 2009, the contents of each of which are incorporated herein by reference. 
     
    
     BACKGROUND OF THE INVENTION 
       [0002]    1. Field of the Invention 
         [0003]    The present invention relates generally to a wireless communication system, and more particularly, to a device and method for transmitting uplink sounding reference signals for a wireless communication system. 
         [0004]    2. Description of the Related Art 
         [0005]    An objective of the Third Generation Partnership Project (3GPP) standardization organization is to establish a new generation of communication standard, known as the Long Term Evolution (LTE) standard. The downlink transmission technique of LTE is based on Orthogonal Frequency Division Multiplexing (OFDM), while the uplink transmission technique is based on a Single Carrier Frequency Division Multiple Access (SCFDMA) scheme. There are two types of frame structures in the LTE system, wherein type 1 applies Frequency Division Duplex (FDD) and type 2 applies Time Division Duplex (TDD). 
         [0006]      FIG. 2  illustrates a frame structure in the LTE FDD system where time duration of a radio frame is 307200×T s =10 ms and each frame is divided into 20 time slots 15360 T s =0.5 ms long which cover the index ranging from 0 to 19. Each time slot includes several OFDM symbols and use a Cyclic Prefix (CP) of one of two types, i.e., normal CP and extended CP. Time slots using normal CP include seven OFDM symbols while the time slots using extended CP have six OFDM symbols. Each sub-frame consists of two continuous time slots, i.e., the k th  sub-frame includes the 2k th  and (2k+1) th  time slots. 
         [0007]      FIG. 3  illustrates a frame structure in the LTE TDD system. A radio frame having a length of 307200×T s =10 ms is divided into two equal half-frames 153600×T s =5 ms long. Each half-frame includes eight 15360T s =0.5 ms long slots and three special domains, i.e., a Downlink Pilot Time Slot (DwPTS), a Guard Period (GP) and an Uplink Pilot Time Slot (UpPTS), and has a total length of 30720T s =1 ms. Each time slot includes several OFDM symbols and use either the normal CP or the extended CP. Time slots using normal CP include 7 OFDM symbols while the time slots using extended CP have 6 OFDM symbols. 
         [0008]    Each sub-frame consists of two continuous time slots, i.e., the k th  sub-frame includes the 2k th  and (2k+1) th  time slots. Sub-frame 1 and 6 include the aforementioned three domains. To this point, sub-frames 0, 5 and DwPTS are constantly assigned for downlink transmission. If the conversion period is 5 ms, UpPTS, sub-frames two and seven are constantly assigned for uplink transmission. If the conversion period is 10 ms, UpPTS and sub-frame 2 are constantly assigned for uplink transmission. 
         [0009]      FIG. 4  illustrates a configuration diagram of an LTE TDD frame structure. In  FIG. 4 , it can be clearly seen that in configuration 0, each radio frame contains ten radio sub-frames that are circularly indexed from 0. Both sub-frames 0 and 5 are adopted to transmit downlink data, i.e., both sub-frames 0 and 5 are adopted by evolved Node B (eNB) to transmit information to UEs, Sub-frames 2, 3, 7, 8 and 9 are adopted by UEs to transmit uplink data, i.e., to transmit information to the eNB, and Sub-frames 1 and 6, also known as special sub-frames, are composed of three special time slots defined as DwPTS, GP and UpPTS respectively. Here, the time length of DwPTS, GP and UpPTS is variable depending on the system configuration. 
         [0010]      FIG. 5  illustrates a distribution diagram of the time-frequency grid of a single uplink sub-frame and a possible location of the time-frequency resource for the Sounding Reference Signal (SRS) transmission under the condition that the normal CP and the extended CP are configured in an LTE system. When the system is configured with normal CPs, each uplink sub-frame within a Resource Block (RB) contains two time slots with each containing 7 Single Carrier Frequency Division Multiple Access (SC-FDMA) symbols (the time domain) and 12 sub-carriers (the frequency domain). When the system is configured with extended CPs, each uplink sub-frame within each RB contains two continuous time slots containing 6 SC-FDMA symbols and 12 sub-carriers. The minimum uplink sub-frame resource is called the Resource Element (RE). 
         [0011]    According to present discussion on LTE, in each radio frame, the last symbol in some sub-frame is adopted to transmit the SRS. 
         [0012]    An objective of LTE on an uplink SRS is for the SRS frequency-hop scheme to guarantee that the SRS signal from the UE for the entire system bandwidth is as loudly as possible. At present, with the provision of SRS for four different system bandwidth configurations, eNB adopts 8-bit Radio Resource Control (RRC) signaling to assign the UE with different frequency-hop schemes. Among the 8-bit RRC signaling, four bits are adopted to indicate the configuration of SRS bandwidth, two bits are adopted to indicate the UE&#39;s SRS bandwidth in current configuration, and the remaining two bits are adopted to indicate SRS frequency-hop bandwidth. 
         [0013]    To avoid collision among SRSs of different UEs within the same frequency-hop period (T), the same transmission sub-frame offset and the same Comb location, when a UE configures the SRS frequency hop, the SRS&#39;s logic IDentifier (ID) (n SRS ) is calculated according to a current radio frame number (n f ), an index (n s ) of the time slot for transmitting the SRS and the SRS period (T), by Equation (1) as follows: 
         [0000]        n   SRS =└( n   f ×10 +└n   s /2┘)/ T┘   (1)
 
         [0014]    The physical resource for each transmission of SRS is then determined based on n SRS . When n SRS  is a continuous value, according to the present SRS frequency-hop scheme, the UE can be guaranteed to sound the entire system bandwidth as loudly as possible. In an FDD system, since frequency division multiplex is applied in both uplink and downlink, it can be guaranteed that in each SRS period at least one uplink sub-frame is allocated by eNB. Therefore, n SRS  obtained by Equation (1) is a continuous value. This guarantees that the SRS could sound the entire system bandwidth. 
         [0015]    However, in a TDD system&#39;s frame structure, it cannot be guaranteed that at least one uplink sub-frame is allocated in every two continuous sub-frames. Thus, when a UE is configured with a 2 ms period, n SRS  obtained by Equation (1) is not continuous in a TDD system, which results in that the UE is not able to sound the entire system bandwidth or that the frequency-hop pattern is not uniform within the sounding frequency-hop bandwidth. 
         [0016]      FIGS. 9A and 9B  illustrate the values of n SRS  obtained by Equation (1) when T=2 (in  FIG. 9A ) and 5 respectively.  FIG. 10  illustrates the problems in the current system when the system bandwidth=25RB, the SRS frequency-hop index=3, the SRS bandwidth=4 and the SRS frequency-hop bandwidth=20. Since seven different uplink and downlink configurations can be applied in a TDD system, the new frequency-hop scheme should guarantee that within any SRS configuration period in either TDD or FDD system, the UE could periodically sound the entire SRS frequency-hop bandwidth with a fixed period, and the frequency-hop pattern should be uniformly distributed over the frequency-hop bandwidth, i.e., the sounding frequency for each SRS bandwidth should be as consistent as possible. As indicated in  FIGS. 9A and 9B , the SRS only sounds a part of the bandwidth or the numbers of sounding for the bandwidths are not equal, regardless of the value of T. 
         [0017]    At present, there is no LTE discussion underway on how to solve the complicated problem of all-around consideration on the seven different uplink and downlink configurations. 
       SUMMARY OF THE INVENTION 
       [0018]    An object of the invention is to provide a frequency-hop method for transmitting uplink signal, particularly for transmitting an uplink sounding signal. 
         [0019]    According to an aspect of the present invention, a method for transmitting an uplink Sounding Reference Signal (SRS) is provided, with the method including identifying a number of downlink and uplink switch points within a radio frame, N sp , and a system frame number n f ; calculating a value of n SRS  according to the number of downlink and uplink switch points within a radio frame N sp , and the system frame number n f  for transmitting the SRS; determining a frequency-domain starting position of the SRS with n SRS ; and transmitting the SRS at the determined frequency-domain starting position. 
         [0020]    According to another aspect of the present invention, a User Equipment (UE) for transmitting an uplink Sounding Reference Signal (SRS) is provided, with the UE including an SRS sequence generator for generating SRS sequence; a physical resource mapper for transmitting the SRS; and a transmitter for transmitting the SRS at the determined frequency-domain starting position, wherein the physical resource mapper is sequentially performs: identifying a number of downlink and uplink switch points within a radio frame, N sp , and a system frame number n f ; calculating a value of n SRS  according to the number of downlink and uplink switch points within a radio frame N sp , and the system frame number n f  for transmitting the SRS; and determining a frequency-domain starting position of the SRS with n SRS . 
         [0021]    According to yet another aspect of the present invention, a method for receiving an uplink Sounding Reference Signal (SRS) is provided, the method including identifying a number of downlink and uplink switch points within a radio frame, N sp , and a system frame number n f ; calculating a value of n SRS  according to the number of downlink and uplink switch points within a radio frame N sp , and the system frame number n f  for transmitting the SRS; determining a frequency-domain starting position of the SRS with n SRS ; and receiving the SRS at the determined frequency-domain starting position. 
         [0022]    According to a further aspect of the present invention, a base station is provided for receiving an uplink Sounding Reference Signal (SRS), the base station including an SRS sequence generator for generating SRS sequence; a physical resource mapper for transmitting the SRS; and a receiver for receiving the SRS at the determined frequency-domain starting position, wherein the physical resource mapper is sequentially performs steps of identifying a number of downlink and uplink switch points within a radio frame, N sp , and a system frame number n f ; calculating a value of n SRS  according to the number of downlink and uplink switch points within a radio frame N sp , and the system frame number n f  for transmitting the SRS; and determining a frequency-domain starting position of the SRS with n SRS . 
     
    
     
       BRIEF DESCRIPTION OF THE DRAWINGS 
         [0023]      FIG. 1  illustrates a block diagram of a structure according to the present invention; 
           [0024]      FIG. 2  illustrates a conventional LTE FDD frame structure; 
           [0025]      FIG. 3  illustrates a conventional LTE TDD frame structure; 
           [0026]      FIG. 4  illustrates conventional uplink and downlink configurations for the LTE TDD system; 
           [0027]      FIG. 5  illustrates a conventional structure of an LTE uplink sub-frame for transmitting the SRS; 
           [0028]      FIG. 6  illustrates a UE SRS configuration table in an FDD system; 
           [0029]      FIG. 7  illustrates a first embodiment of a UE SRS configuration table in a TDD system; 
           [0030]      FIG. 8  illustrates a second embodiment of a UE SRS configuration table in a TDD system; 
           [0031]      FIGS. 9A and 9B  illustrate a problem to be solved; 
           [0032]      FIG. 10  illustrates an ideal SRS frequency-hop pattern; 
           [0033]      FIG. 11  illustrates an SRS frequency-hop pattern when T=2; 
           [0034]      FIG. 12  illustrates an SRS frequency-hop pattern when T=5; 
           [0035]      FIGS. 13A through 13D  illustrate an SRS bandwidth configuration for different uplink bandwidths; 
           [0036]      FIGS. 14A and 14B  illustrate a frequency-hop method applied in a TDD system when the UE&#39;s SRS configuration table of  FIG. 7  is adopted; 
           [0037]      FIGS. 15A and 15B  illustrate a frequency-hop method applied in a TDD system when the UE&#39;s SRS configuration table of  FIG. 8  is adopted; 
           [0038]      FIGS. 16A and 16B  illustrate a frequency-hop method when using an RRC incremental indication; 
           [0039]      FIG. 17  illustrates an SRS signal resource mapping diagram; and 
           [0040]      FIG. 18  illustrates a mapping relationship between SRS index k when different uplink and downlink configurations are applied in a TDD system. 
       
    
    
     DETAILED DESCRIPTION OF THE PREFERRED EMBODIMENTS 
       [0041]    Hereinafter, preferred embodiments of the present invention are described in detail with reference to the accompanying drawings. The same reference numbers are used throughout the drawings to refer to the same or similar parts. Detailed descriptions of well-known functions and structures incorporated herein may be omitted for the sake of clarity and conciseness. 
         [0042]      FIG. 1  illustrates a system block diagram according to the present invention. The system includes an SRS sequence generator  101  which generates a Zadoff-chu sequence to be transmitted according to the SRS bandwidth indicator transmitted with RRC signaling from an eNB, a physical resource mapper  102  which determines the SRS frequency-hop pattern according to the SRS parameters (transmitted with the 11-bit RRC signaling from eNB) such as an SRS period T, a sub-frame offset (as shown in  FIGS. 7 and 8 ) and an index number n f  of the current radio frame, and maps the SRS sequence to corresponding physical Resource Elements (REs) according to the generated frequency-hop pattern, and generates SC-FDMA symbols to be transmitted through Inverse Fast Fourier Transform (IFFT). Further included in the system are antennas which transmit the RF (Radio Frequency) signal output from the radio transmitter in a form of electro-magnetic waves. 
         [0043]    The system according to the present invention relates to the physical resource mapper  102  shown in  FIG. 1 . 
         [0044]      FIGS. 14A and 14D  illustrate an SRS frequency-hopping method according to present invention, which is suitable for the UE SRS configuration table for the TDD system shown in  FIG. 7 . According to this method, in step  1400  the UE generates the SRS reference symbol sequence according to the SRS bandwidth parameter (allocated by the eNB through RRC signaling) and the cyclic shift parameter. 
         [0045]    In step  1401  the UE determines whether the SRS period (allocated by eNB for UE) is 2, i.e., the UE reads out a value of I SRS  (the SRS period, which is transmitted from the eNB through RRC signaling). If 0≦I SRS ≦9, the method proceeds to step  1402 ; otherwise, the method proceeds to step  1403 . 
         [0046]    In step  1402  the UE determines the frequency-hop pattern parameter n SRS  according to the index number n f  of the radio frame for transmitting the SRS signal, and the index number k of the SRS in the SRS sequence within the radio frame. The requirements for determining the parameter are to avoid collision between SRSs from different UEs but with the same SRS period, the same sub-frame offset and the same Comb index number, and for n SRS  to be continuous with the index number k of the SRS in the SRS sequence within the radio frame and the different uplink and downlink sub-frame configurations (as shown in  FIG. 4 ) in a TDD system so that the UE can sound the entire SRS frequency-hop bandwidth allocated by the eNB. 
         [0047]    By these requirements, it can be concluded that n SRS =f(n f ,k). Here, the implementation mode cannot be confined within the mapping method of Equation (2): 
         [0000]        n   SRS   =n   f   ×L+k   (2)
 
         [0048]    By Equation 2, if the configurations for the uplink and downlink in the TDD system are 0, 1, 2 and 6, then k=0, 1, 2 and 3, L=4, and if the configurations for the uplink and downlink in the TDD system are 3, 4 and 5, then k=0, 1; L=2. k is indexed in ascending order, i.e., the first SC-FDMA symbol in each radio frame for transmitting the SRS corresponds to k=0, the second SC-FDMA symbol in each radio frame for transmitting the SRS corresponds to k=1, the third SC-FDMA symbol in each radio frame for transmitting the SRS corresponds to k=2, the fourth SC-FDMA symbol in each radio frame for transmitting the SRS corresponds to k=3, and n f  denotes the index number of radio frame and n f &gt;0. 
         [0049]    Other methods for deriving a continuous n SRS  according to different values of k may be used as long as the same principles as the foregoing are applied. 
         [0050]    In step  1403  the UE determines the frequency-hop parameter n SRS  according to the index number n f  of the radio frame for transmitting the SRS, and the index number n s  of time slot in the radio frame for transmitting the SRS, i.e., by Equation (3) as follows: 
         [0000]        n   SRS =└( n   f ×10+└ n   s /2┘)/ T┘   (3)
 
         [0051]    In Equation (3), n f ≧0 denotes the index number of radio frame, n s  denotes the index number of the time slot in the radio frame for transmitting the SRS, 0≦n s ≦19, and according to the RRC signaling from the eNB, the UE determines T and n s  based on the contents in  FIG. 7 , and 5≦T≦320. 
         [0052]    In step  1404  the frequency-domain increment is calculated and updated by the SRS within the frame according to the obtained n SRS , i.e., by Equation (4) as follows: 
         [0000]    
       
         
           
             
               
                 
                   
                     
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         [0053]    In Equation (4), N b  is obtained according to the RRC signaling from the eNB and with reference to  FIGS. 13A through 13D , and b hop  denotes SRS frequency-hop bandwidth parameter, 0≦b hop ≦3, which the UE obtains by reading the RRC signaling from the eNB. 
         [0054]    In step  1405 , the index number n b  frequency-domain location is calculated for transmitting the SRS according to the obtained F b (n SRS ), by Equation (5) as follows: 
         [0000]    
       
         
           
             
               
                 
                   
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         [0055]    In Equation (5), m SRS,b , b hop , n RRC  are the parameters that the UE obtains by reading the RRC signaling from the eNB. 
         [0056]    In step  1406  the start frequency-domain position k 0  is calculated for transmitting the SRS, by Equation (6) as follows: 
         [0000]    
       
         
           
             
               
                 
                   
                     
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         [0057]    In Equation (6), m SRS,0  is obtained from the 3-bit cell-specific SRS parameter broadcast by the eNB, m SRS,b  is allocated by the eNB through RRC signaling and with reference to the lookup table in  FIGS. 13A through 13D , N sc   RB =12 denotes the number of sub-carriers in each RB), k TC ε{0,1} denotes the Comb number, and N RB   UL  denotes the number of frequency-domain RBs in the uplink sub-frame. 
         [0058]    In step  1407  the SRS sequence is mapped to sub-carriers numbered starting from k 0 . The detailed mapping approach is shown in  FIG. 17 . 
         [0059]    In step  1408  the frequency-domain symbols obtained by using IFFT are mapped to time-domain symbols, and then are transmitted through antennas. 
         [0060]      FIGS. 15A and 15B  illustrate another SRS frequency-hop method of the present invention, which is suitable for the UE SRS configuration table for the TDD system in  FIG. 8 . In the method, in step  1500  the UE generates the SRS reference symbol sequence according to the SRS bandwidth parameter (allocated by the eNB through RRC signaling) and the cyclic shift parameter. 
         [0061]    In step  1501  the UE determines whether the SRS period (allocated by eNB for UE) is 5, i.e., the UE reads out the value of I SRS  (the SRS period, which is transmitted from the eNB through RRC signaling). If 0≦I SRS ≦14, the method proceeds to step  1502 ; otherwise, the method proceeds to step  1504 . 
         [0062]    In step  1502  the UE reads out the parameter I SRS  on SRS period that is transmitted from the eNB through RRC signaling. If 0≦I SRS ≦9, the method proceeds to step  1503 ; otherwise, the method proceeds to step  1504 ; 
         [0063]    In step  1503  the UE determines the frequency-hop pattern parameter n SRS  according to the index number n f  of the radio frame for transmitting the SRS signal, the index number n s  of the time slot in the radio frame for transmitting the SRS, and the index number k of the SRS in the SRS sequence within the radio frame (refer to  FIG. 18 ). The requirements for determining the parameter are to avoid a collision between SRSs from different UEs but with the same SRS period, the same sub-frame offset and the same Comb index number, and to guarantee that n SRS  is continuous with the index number k of the SRS in the SRS sequence within the radio frame and the different uplink and downlink sub-frame configurations in a TDD system so that the UE can sound the entire SRS frequency-hop bandwidth allocated by the eNB. 
         [0064]    By these requirements, it can be concluded that n SRS =f(n f ,k). Here, the implementation mode cannot be confined within the mapping method of Equation (7) as follows: 
         [0000]        n   SRS =└( n   f ×10 +└n   s /2┘)/ T┘+Δ   k   (7)
 
         [0065]    (a) For the TDD uplink and downlink configurations 0, 1, 2 and 6: 
         [0000]    
       
         
           
             
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         [0066]    (b) For the TDD uplink and downlink configurations 3, 4 and 5 
         [0000]      Δ k   =k ( k= 0,1)
 
         [0067]    Where k=0, 1, 2 and 3 (if the configurations for the uplink and downlink in TDD system are 0, 1, 2 and 6), k=0 and 1 (if the configurations for the uplink and downlink in TDD system are 3, 4 and 5), k is indexed in ascending order, i.e., the first SC-FDMA symbol in each radio frame for transmitting the SRS corresponds to k=0, the second SC-FDMA symbol in each radio frame for transmitting the SRS corresponds to k=1, the third SC-FDMA symbol in each radio frame for transmitting the SRS corresponds to k=2, the fourth SC-FDMA symbol in each radio frame for transmitting the SRS corresponds to k=3, and n f ≧0 denotes the index number of radio frame. Here T=5. 
         [0068]    Other methods for deriving continuous n SRS  according to different values of k may be used as long as the same requirements are applied. 
         [0069]    In step  1504  the UE determines the frequency-hop parameter n SRS  according to the index number n f  of the radio frame for transmitting the SRS, and the index number n s  of time slot in the radio frame for transmitting the SRS, in Equation (8) as follows: 
         [0000]        n   SRS =└( n   f ×10+└ n   s /2┘)/ T┘   (8)
 
         [0070]    In Equation (8), n f ≧0 denotes the index number of radio frame, 0≦n s ≦19 denotes the index number of the time slot in the radio frame for transmitting the SRS, and according to the RRC signaling from the eNB, the UE determines T and n s  with reference to  FIG. 8 , 5≦T≦320. 
         [0071]    In step  1505  the frequency-domain increment that the SRS needs to be updated within the frame is calculated according to the obtained n SRS , by Equation (9) as follows: 
         [0000]    
       
         
           
             
               
                 
                   
                     
                       F 
                       b 
                     
                      
                     
                       ( 
                       
                         n 
                         SRS 
                       
                       ) 
                     
                   
                   = 
                   
                     { 
                     
                       
                         
                           
                             
                               
                                 ( 
                                 
                                   
                                     N 
                                     b 
                                   
                                   / 
                                   2 
                                 
                                 ) 
                               
                                
                               
                                 ⌊ 
                                 
                                   
                                     
                                       n 
                                       SRS 
                                     
                                      
                                     mod 
                                      
                                     
                                       
                                         ∏ 
                                         
                                           
                                             b 
                                             ′ 
                                           
                                           = 
                                           
                                             b 
                                             hop 
                                           
                                         
                                         b 
                                       
                                        
                                       
                                         N 
                                         
                                           b 
                                           ′ 
                                         
                                       
                                     
                                   
                                   
                                     
                                       ∏ 
                                       
                                         
                                           b 
                                           ′ 
                                         
                                         = 
                                         
                                           b 
                                           hop 
                                         
                                       
                                       
                                         b 
                                         - 
                                         1 
                                       
                                     
                                      
                                     
                                       N 
                                       
                                         b 
                                         ′ 
                                       
                                     
                                   
                                 
                                 ⌋ 
                               
                             
                             + 
                             
                               ⌊ 
                               
                                 
                                   
                                     n 
                                     SRS 
                                   
                                    
                                   mod 
                                    
                                   
                                     
                                       ∏ 
                                       
                                         
                                           b 
                                           ′ 
                                         
                                         = 
                                         
                                           b 
                                           hop 
                                         
                                       
                                       b 
                                     
                                      
                                     
                                       N 
                                       
                                         b 
                                         ′ 
                                       
                                     
                                   
                                 
                                 
                                   2 
                                    
                                   
                                     
                                       ∏ 
                                       
                                         
                                           b 
                                           ′ 
                                         
                                         = 
                                         
                                           b 
                                           hop 
                                         
                                       
                                       
                                         b 
                                         - 
                                         1 
                                       
                                     
                                      
                                     
                                       N 
                                       
                                         b 
                                         ′ 
                                       
                                     
                                   
                                 
                               
                               ⌋ 
                             
                           
                         
                         
                           
                             if 
                              
                             
                                 
                             
                              
                             
                               N 
                               b 
                             
                              
                             
                                 
                             
                              
                             even 
                           
                         
                       
                       
                         
                           
                             
                               ⌊ 
                               
                                 
                                   N 
                                   b 
                                 
                                 / 
                                 2 
                               
                               ⌋ 
                             
                              
                             
                               ⌊ 
                               
                                 
                                   n 
                                   SRS 
                                 
                                 / 
                                 
                                   
                                     ∏ 
                                     
                                       
                                         b 
                                         ′ 
                                       
                                       = 
                                       
                                         b 
                                         hop 
                                       
                                     
                                     
                                       b 
                                       - 
                                       1 
                                     
                                   
                                    
                                   
                                     N 
                                     
                                       b 
                                       ′ 
                                     
                                   
                                 
                               
                               ⌋ 
                             
                           
                         
                         
                           
                             if 
                              
                             
                                 
                             
                              
                             
                               N 
                               b 
                             
                              
                             
                                 
                             
                              
                             odd 
                           
                         
                       
                     
                   
                 
               
               
                 
                   ( 
                   9 
                   ) 
                 
               
             
           
         
       
     
         [0072]    In Equation (9), N b  is obtained according to the RRC signaling from the eNB and with reference to  FIGS. 13A through 13D , b hop  denotes SRS frequency-hop bandwidth parameter, 0≦b hop ≦3, which the UE obtains by reading the RRC signaling from the eNB. 
         [0073]    In step  1506  the index number n b  frequency-domain location for transmitting the SRS is calculated according to the obtained F b (n SRS ), by Equation (10) as follows: 
         [0000]    
       
         
           
             
               
                 
                   
                     n 
                     b 
                   
                   = 
                   
                     { 
                     
                       
                         
                           
                             ⌊ 
                             
                               4 
                                
                               
                                 
                                   n 
                                   RRC 
                                 
                                 / 
                                 
                                   m 
                                   
                                     SRS 
                                     , 
                                     b 
                                   
                                 
                               
                             
                             ⌋ 
                           
                         
                         
                           
                             b 
                             ≤ 
                             
                               b 
                               hop 
                             
                           
                         
                       
                       
                         
                           
                             
                               { 
                               
                                 
                                   
                                     F 
                                     b 
                                   
                                    
                                   
                                     ( 
                                     
                                       n 
                                       SRS 
                                     
                                     ) 
                                   
                                 
                                 + 
                                 
                                   ⌊ 
                                   
                                     4 
                                      
                                     
                                       
                                         n 
                                         RRC 
                                       
                                       / 
                                       
                                         m 
                                         
                                           SRS 
                                           , 
                                           b 
                                         
                                       
                                     
                                   
                                   ⌋ 
                                 
                               
                               } 
                             
                              
                             mod 
                              
                             
                                 
                             
                              
                             
                               N 
                               b 
                             
                           
                         
                         
                           else 
                         
                       
                     
                   
                 
               
               
                 
                   ( 
                   10 
                   ) 
                 
               
             
           
         
       
     
         [0074]    In Equation (10), m SRS,b , b hop , n RRC  are the parameters that the UE obtains by reading the RRC signaling from the eNB. 
         [0075]    In step  1507  the start frequency-domain position k 0  is calculated for transmitting the SRS by Equation (11), as follows: 
         [0000]    
       
         
           
             
               
                 
                   
                     
                       k 
                       0 
                       ′ 
                     
                     = 
                     
                       
                         
                           ( 
                           
                             
                               ⌊ 
                               
                                 
                                   N 
                                   RB 
                                   UL 
                                 
                                 / 
                                 2 
                               
                               ⌋ 
                             
                             - 
                             
                               
                                 m 
                                 
                                   SRS 
                                   , 
                                   0 
                                 
                               
                               / 
                               2 
                             
                           
                           ) 
                         
                          
                         
                           N 
                           SC 
                           RB 
                         
                       
                       + 
                       
                         k 
                         TC 
                       
                     
                   
                    
                   
                     
 
                   
                    
                   
                     
                       k 
                       0 
                     
                     = 
                     
                       
                         k 
                         0 
                         ′ 
                       
                       + 
                       
                         
                           ∑ 
                           
                             b 
                             = 
                             0 
                           
                           
                             B 
                             SRS 
                           
                         
                          
                         
                           2 
                            
                           
                             M 
                             
                               sc 
                               , 
                               b 
                             
                             RS 
                           
                            
                           
                             n 
                             b 
                           
                         
                       
                     
                   
                    
                   
                     
 
                   
                    
                   
                     
                       M 
                       
                         sc 
                         , 
                         b 
                       
                       RS 
                     
                     = 
                     
                       
                         m 
                         
                           SRS 
                           , 
                           b 
                         
                       
                        
                       
                         
                           N 
                           sc 
                           RB 
                         
                         / 
                         2 
                       
                     
                   
                 
               
               
                 
                   ( 
                   11 
                   ) 
                 
               
             
           
         
       
     
         [0076]    In Equation (11), m SRS,0  is obtained from the 3-bit cell-specific SRS parameter broadcast by the eNB, m SRS,b  is allocated by the eNB through RRC signaling and obtained with reference to the lookup table in  FIGS. 13A through 13D , N sc   RB =12 denotes the number of sub-carrier in each RB, k TC ε{0,1} denotes the Comb number, and N RB   UL  denotes the number of frequency-domain RB in the uplink sub-frame. 
         [0077]    In step  1508  the SRS sequence is mapped to sub-carriers numbered beginning with k 0 . The detailed mapping technique is shown in  FIG. 17 . 
         [0078]    In step  1509  the frequency-domain symbols obtained by using IFFT are mapped to time-domain symbols, and then transmitted through antennas. 
         [0079]    In addition, another SRS frequency-hop method according to the present invention is shown in  FIGS. 16A and 16B . In the method, in step  1600  the UE generates the SRS reference symbol sequence according to the SRS bandwidth parameter (allocated by the eNB through RRC signaling) and the cyclic shift parameter. 
         [0080]    In step  1601  the UE reads out the SRS period index I SRS  transmitted from the eNB. If 0≦I SRS ≦9, the method proceeds to step  1602 ; otherwise, the method proceeds to step  1603 . 
         [0081]    In step  1602  the parameter n SRS  is calculated according to different configurations in a TDD system. For the TDD uplink and downlink configurations 0, 1, 2 and 6 as shown in  FIG. 4 , Equation (12) is used as follows: 
         [0000]        n   SRS   =n   f ×2+└ n   s /10┘  (12)
 
         [0082]    For the TDD uplink and downlink configurations 3, 4 and 5 as shown in  FIG. 4 , Equation (13) is used a follows: 
         [0000]        n   SRS   =n   f   (13)
 
         [0083]    In Equations (12) and (13), n f  denotes the index number of radio frame, n f ≧0; n s  denotes the index number of the time slot in the radio frame for transmitting the SRS, and 0≦n s ≦19. 
         [0084]    In step  1603  the UE determines the frequency-hop parameter n SRS  according to the index number n f  of the radio frame for transmitting the SRS, and the index number n s  of time slot in the radio frame for transmitting the SRS, by Equation (14) as follows: 
         [0000]        n   SRS =└( n   f ×10+└ n   s /2┘)/ T┘   (14)
 
         [0085]    In Equation (14), n f  denotes the index number of radio frame, n f ≧0, n s  denotes the index number of the time slot in the radio frame for transmitting the SRS, 0≦n s ≦19, and according to the RRC signaling from the eNB, the UE determines T and n s . 
         [0086]    In step  1604  the frequency-domain increment that the SRS needs to be updated within the frame is calculated according to the obtained n SRS , by Equation (15) as follows: 
         [0000]    
       
         
           
             
               
                 
                   
                     
                       F 
                       b 
                     
                      
                     
                       ( 
                       
                         n 
                         SRS 
                       
                       ) 
                     
                   
                   = 
                   
                     { 
                     
                       
                         
                           
                             
                               
                                 ( 
                                 
                                   
                                     N 
                                     b 
                                   
                                   / 
                                   2 
                                 
                                 ) 
                               
                                
                               
                                 ⌊ 
                                 
                                   
                                     
                                       n 
                                       SRS 
                                     
                                      
                                     mod 
                                      
                                     
                                       
                                         ∏ 
                                         
                                           
                                             b 
                                             ′ 
                                           
                                           = 
                                           
                                             b 
                                             hop 
                                           
                                         
                                         b 
                                       
                                        
                                       
                                         N 
                                         
                                           b 
                                           ′ 
                                         
                                       
                                     
                                   
                                   
                                     
                                       ∏ 
                                       
                                         
                                           b 
                                           ′ 
                                         
                                         = 
                                         
                                           b 
                                           hop 
                                         
                                       
                                       
                                         b 
                                         - 
                                         1 
                                       
                                     
                                      
                                     
                                       N 
                                       
                                         b 
                                         ′ 
                                       
                                     
                                   
                                 
                                 ⌋ 
                               
                             
                             + 
                             
                               ⌊ 
                               
                                 
                                   
                                     n 
                                     SRS 
                                   
                                    
                                   mod 
                                    
                                   
                                     
                                       ∏ 
                                       
                                         
                                           b 
                                           ′ 
                                         
                                         = 
                                         
                                           b 
                                           hop 
                                         
                                       
                                       b 
                                     
                                      
                                     
                                       N 
                                       
                                         b 
                                         ′ 
                                       
                                     
                                   
                                 
                                 
                                   2 
                                    
                                   
                                     
                                       ∏ 
                                       
                                         
                                           b 
                                           ′ 
                                         
                                         = 
                                         
                                           b 
                                           hop 
                                         
                                       
                                       
                                         b 
                                         - 
                                         1 
                                       
                                     
                                      
                                     
                                       N 
                                       
                                         b 
                                         ′ 
                                       
                                     
                                   
                                 
                               
                               ⌋ 
                             
                           
                         
                         
                           
                             if 
                              
                             
                                 
                             
                              
                             
                               N 
                               b 
                             
                              
                             
                                 
                             
                              
                             even 
                           
                         
                       
                       
                         
                           
                             
                               ⌊ 
                               
                                 
                                   N 
                                   b 
                                 
                                 / 
                                 2 
                               
                               ⌋ 
                             
                              
                             
                               ⌊ 
                               
                                 
                                   n 
                                   SRS 
                                 
                                 / 
                                 
                                   
                                     ∏ 
                                     
                                       
                                         b 
                                         ′ 
                                       
                                       = 
                                       
                                         b 
                                         hop 
                                       
                                     
                                     
                                       b 
                                       - 
                                       1 
                                     
                                   
                                    
                                   
                                     N 
                                     
                                       b 
                                       ′ 
                                     
                                   
                                 
                               
                               ⌋ 
                             
                           
                         
                         
                           
                             if 
                              
                             
                                 
                             
                              
                             
                               N 
                               b 
                             
                              
                             
                                 
                             
                              
                             odd 
                           
                         
                       
                     
                   
                 
               
               
                 
                   ( 
                   15 
                   ) 
                 
               
             
           
         
       
     
         [0087]    In Equation (15), N b  is obtained according to the RRC signaling from the eNB and with reference to  FIGS. 13A through 13D , b hop  denotes the SRS frequency-hop bandwidth parameter, which the UE obtains by reading the RRC signaling from the eNB, and 0≦b hop ≦3. 
         [0088]    In step  1605  the UE reads out the SRS period index I SRS  transmitted from eNB. If 0≦I SRS ≦9, the method proceeds to step  1606 ; otherwise, the method proceeds to step  1607 . 
         [0089]    In step  1606  the UE determines whether the SRS to be transmitted is the first one in a current time slot. If yes, the method proceeds to step  1607 ; otherwise, the method proceeds to step  1608 . 
         [0090]    In step  1607  the index number n b  frequency-domain location for transmitting the SRS is calculated according to the obtained F b (n SRS ), by Equation (16) as follows: 
         [0000]    
       
         
           
             
               
                 
                   
                     n 
                     b 
                   
                   = 
                   
                     { 
                     
                       
                         
                           
                             ⌊ 
                             
                               4 
                                
                               
                                 
                                   n 
                                   RRC 
                                 
                                 / 
                                 
                                   m 
                                   
                                     SRS 
                                     , 
                                     b 
                                   
                                 
                               
                             
                             ⌋ 
                           
                         
                         
                           
                             b 
                             ≤ 
                             
                               b 
                               hop 
                             
                           
                         
                       
                       
                         
                           
                             
                               { 
                               
                                 
                                   
                                     F 
                                     b 
                                   
                                    
                                   
                                     ( 
                                     
                                       n 
                                       SRS 
                                     
                                     ) 
                                   
                                 
                                 + 
                                 
                                   ⌊ 
                                   
                                     4 
                                      
                                     
                                       
                                         n 
                                         RRC 
                                       
                                       / 
                                       
                                         m 
                                         
                                           SRS 
                                           , 
                                           b 
                                         
                                       
                                     
                                   
                                   ⌋ 
                                 
                               
                               } 
                             
                              
                             mod 
                              
                             
                                 
                             
                              
                             
                               N 
                               b 
                             
                           
                         
                         
                           else 
                         
                       
                     
                   
                 
               
               
                 
                   ( 
                   16 
                   ) 
                 
               
             
           
         
       
     
         [0091]    In Equation (16), m SRS , b hop , n RRC  are the parameters that the UE obtains by reading the RRC signaling from the eNB. 
         [0092]    In step  1608  the index number n b  frequency-domain location for transmitting the SRS is calculated according to the obtained F b (n SRS ), by Equation (17) as follows: 
         [0000]    
       
         
           
             
               
                 
                   
                     n 
                     b 
                   
                   = 
                   
                     { 
                     
                       
                         
                           
                             ⌊ 
                             
                               4 
                                
                               
                                 
                                   n 
                                   RRC 
                                 
                                 / 
                                 
                                   m 
                                   
                                     SRS 
                                     , 
                                     b 
                                   
                                 
                               
                             
                             ⌋ 
                           
                         
                         
                           
                             b 
                             ≤ 
                             
                               b 
                               hop 
                             
                           
                         
                       
                       
                         
                           
                             
                               { 
                               
                                 
                                   
                                     F 
                                     b 
                                   
                                    
                                   
                                     ( 
                                     
                                       n 
                                       SRS 
                                     
                                     ) 
                                   
                                 
                                 + 
                                 
                                   f 
                                    
                                   
                                     ( 
                                     
                                       n 
                                       RRC 
                                     
                                     ) 
                                   
                                 
                               
                               } 
                             
                              
                             mod 
                              
                             
                                 
                             
                              
                             
                               N 
                               b 
                             
                           
                         
                         
                           else 
                         
                       
                     
                   
                 
               
               
                 
                   ( 
                   17 
                   ) 
                 
               
             
           
         
       
     
         [0093]    In Equation (17), m SRS,b , b hop , n RRC  are the parameters that the UE obtains by reading the RRC signaling from the eNB. 
         [0094]    Different variations to the foregoing method can be applied. For example, in Equation (18), 
         [0000]    
       
         
           
             
               
                 
                   
                     n 
                     b 
                   
                   = 
                   
                     { 
                     
                       
                         
                           
                             ⌊ 
                             
                               4 
                                
                               
                                 
                                   n 
                                   RRC 
                                 
                                 / 
                                 
                                   m 
                                   
                                     SRS 
                                     , 
                                     b 
                                   
                                 
                               
                             
                             ⌋ 
                           
                         
                         
                           
                             b 
                             ≤ 
                             
                               b 
                               hop 
                             
                           
                         
                       
                       
                         
                           
                             
                               { 
                               
                                 
                                   
                                     F 
                                     b 
                                   
                                    
                                   
                                     ( 
                                     
                                       n 
                                       SRS 
                                     
                                     ) 
                                   
                                 
                                 + 
                                 
                                   ⌊ 
                                   
                                     4 
                                      
                                     
                                       
                                         n 
                                         RRC 
                                       
                                       / 
                                       
                                         m 
                                         
                                           SRS 
                                           , 
                                           b 
                                         
                                       
                                     
                                   
                                   ⌋ 
                                 
                                 + 
                                 
                                   Δ 
                                   b 
                                 
                               
                               } 
                             
                              
                             mod 
                              
                             
                                 
                             
                              
                             
                               N 
                               b 
                             
                           
                         
                         
                           else 
                         
                       
                     
                   
                 
               
               
                 
                   ( 
                   18 
                   ) 
                 
               
             
           
         
       
     
         [0095]    Where: Δ b =0, 1, 2, . . . N b −1. 
         [0096]    The approach in Equation (19) can also be adopted to calculate n b , as follows: 
         [0000]    
       
         
           
             
               
                 
                   
                     n 
                     b 
                   
                   = 
                   
                     { 
                     
                       
                         
                           
                             ⌊ 
                             
                               4 
                                
                               
                                 
                                   n 
                                   RRC 
                                 
                                 / 
                                 
                                   m 
                                   
                                     SRS 
                                     , 
                                     b 
                                   
                                 
                               
                             
                             ⌋ 
                           
                         
                         
                           
                             b 
                             ≤ 
                             
                               b 
                               hop 
                             
                           
                         
                       
                       
                         
                           
                             
                               { 
                               
                                 
                                   
                                     F 
                                     b 
                                   
                                    
                                   
                                     ( 
                                     
                                       n 
                                       SRS 
                                     
                                     ) 
                                   
                                 
                                 + 
                                 
                                   ⌊ 
                                   
                                     4 
                                      
                                     
                                       
                                         ( 
                                         
                                           
                                             n 
                                             RRC 
                                           
                                           + 
                                           Δ 
                                         
                                         ) 
                                       
                                       / 
                                       
                                         m 
                                         
                                           SRS 
                                           , 
                                           b 
                                         
                                       
                                     
                                   
                                   ⌋ 
                                 
                               
                               } 
                             
                              
                             mod 
                              
                             
                                 
                             
                              
                             
                               N 
                               b 
                             
                           
                         
                         
                           else 
                         
                       
                     
                   
                 
               
               
                 
                   ( 
                   19 
                   ) 
                 
               
             
           
         
       
     
         [0097]    Where: Δ≧0. 
         [0098]    In step  1609  the start frequency-domain position k 0  for transmitting the SRS is calculated by Equation (20), as follows: 
         [0000]    
       
         
           
             
               
                 
                   
                     
                       k 
                       0 
                       ′ 
                     
                     = 
                     
                       
                         
                           ( 
                           
                             
                               ⌊ 
                               
                                 
                                   N 
                                   RB 
                                   UL 
                                 
                                 / 
                                 2 
                               
                               ⌋ 
                             
                             - 
                             
                               
                                 m 
                                 
                                   SRS 
                                   , 
                                   0 
                                 
                               
                               / 
                               2 
                             
                           
                           ) 
                         
                          
                         
                           N 
                           SC 
                           RB 
                         
                       
                       + 
                       
                         k 
                         TC 
                       
                     
                   
                    
                   
                     
 
                   
                    
                   
                     
                       k 
                       0 
                     
                     = 
                     
                       
                         k 
                         0 
                         ′ 
                       
                       + 
                       
                         
                           ∑ 
                           
                             b 
                             = 
                             0 
                           
                           
                             B 
                             SRS 
                           
                         
                          
                         
                           2 
                            
                           
                             M 
                             
                               sc 
                               , 
                               b 
                             
                             RS 
                           
                            
                           
                             n 
                             b 
                           
                         
                       
                     
                   
                    
                   
                     
 
                   
                    
                   
                     
                       M 
                       
                         sc 
                         , 
                         b 
                       
                       RS 
                     
                     = 
                     
                       
                         m 
                         
                           SRS 
                           , 
                           b 
                         
                       
                        
                       
                         
                           N 
                           sc 
                           RB 
                         
                         / 
                         2 
                       
                     
                   
                 
               
               
                 
                   ( 
                   20 
                   ) 
                 
               
             
           
         
       
     
         [0099]    In Equation (20), m SRS,0  is obtained from the 3-bit cell-specific SRS parameter broadcast by the eNB, m SRS,b  is allocated by the eNB through RRC signaling and obtained with reference to the lookup table in  FIGS. 13A through 13D , N sc   RB =12 denotes the number of sub-carrier in each RB, k TC ε{0,1} denotes the Comb number, and N RB   UL  denotes the number of the frequency-domain RB in the uplink sub-frame. 
         [0100]    In step  1610  the SRS sequence is mapped to sub-carriers numbered starting from k 0 . The detailed mapping technique is shown in  FIG. 17 . 
         [0101]    In step  1611  the frequency-domain symbols obtained by IFFT are mapped to time-domain symbols and are then transmitted through antennas. 
         [0102]    In the following embodiment of the present invention, it is assumed that the uplink of the TDD system occupies N RBs, where N=25. 
         [0103]    The index number of the SRS bandwidth configuration broadcast by the eNB is k, where k=3. 
         [0104]    The SRS period parameter configured by the eNB for the UE through the RRC signaling is I SRS , where I SRS =0 in this example. 
         [0105]    The SRS bandwidth parameter configured by the eNB for the UE through the RRC signaling is M SRS,b , and the frequency-hop bandwidth is b hop , the index of number of Comb for transmitting the SRS is k TC , where b=3, and m SRS,b =4, b hop =0, k TC =0. 
         [0106]    The start frequency-hop position configured by the eNB for the UE through the RRC signaling is └4n RRC /m SRS,b ┘, where n RRC =0. 
         [0107]    In a TDD system, the uplink and downlink are configured with the configuration l, where l=1 in the examples 1, 2 and 3, and l=4 in the examples 4, 5 and 6. 
         [0108]    A first embodiment is suitable for the TDD system for which  FIG. 7  illustrates the UE SRS configuration table. The processing flow is illustrated in  FIGS. 14A and 14B . 
         [0109]    In step  1 , the UE generates the Zadeoff-chu sequence with the length of H=m SRS,b ×12/2=4×12/2=24 according to the SRS bandwidth parameter m SRS,b =4 configured by the eNB through RRC signaling. 
         [0110]    In step  2 , the UE deduces the SRS period T=2 according to the SRS period index I SRS =0 and with the information in  FIG. 7 . Moreover, the UE learns about in each radio frame the SRS index k=0, 1, 2 and 3 and the corresponding time slot index, as shown in  FIG. 18(   a ); 
         [0111]    In step  3 , before transmitting the SRS signal each time, the UE calculates the key frequency-hop parameter n SRS  according to current SRS index k and the radio frame index n f . In this embodiment, it is assumed that current frame&#39;s index number n f =0, and for the second transmission of SRS, k=1, L=4, and n SRS =n f ×4+k=0×4+1=1. 
         [0112]    In subsequent steps, the frequency-domain increment is calculated by Equation (21) as follows: 
         [0000]        F   3 (1)=└5/2┘└1/Π b′=0   2   N   b′ ┘=2  (21)
 
         [0113]    The frequency-domain location for transmitting the SRS is calculated according to Equation (22) as follows: 
         [0000]        F   3 (1) as  n   3   ={F   3 (1)+0} mod 5=2  (22)
 
         [0114]    The frequency-domain sub-carrier&#39;s start position for transmitting the SRS is calculated by Equation (23) as 
         [0000]    
       
         
           
             
               
                 
                   
                     
                       
                         
                           k 
                           0 
                           ′ 
                         
                         = 
                         
                           
                             
                               ( 
                               
                                 
                                   ⌊ 
                                   
                                     
                                       N 
                                       RB 
                                       UL 
                                     
                                     / 
                                     2 
                                   
                                   ⌋ 
                                 
                                 - 
                                 
                                   
                                     m 
                                     
                                       SRS 
                                       , 
                                       0 
                                     
                                   
                                   / 
                                   2 
                                 
                               
                               ) 
                             
                             × 
                             
                               N 
                               SC 
                               RB 
                             
                           
                           + 
                           
                             k 
                             TC 
                           
                         
                       
                     
                   
                   
                     
                       
                         
                           = 
                           
                             
                               
                                 
                                   ( 
                                   
                                     
                                       ⌊ 
                                       
                                         25 
                                         / 
                                         2 
                                       
                                       ⌋ 
                                     
                                     - 
                                     
                                       20 
                                       / 
                                       2 
                                     
                                   
                                   ) 
                                 
                                 × 
                                 12 
                               
                               + 
                               0 
                             
                             = 
                             24 
                           
                         
                         ; 
                       
                     
                   
                   
                     
                       
                         
                           k 
                           0 
                         
                         = 
                         
                           
                             k 
                             0 
                             ′ 
                           
                           + 
                           
                             
                               ∑ 
                               
                                 b 
                                 = 
                                 0 
                               
                               3 
                             
                              
                             
                               2 
                               × 
                               
                                 m 
                                 
                                   SRS 
                                   , 
                                   b 
                                 
                               
                               × 
                               
                                 n 
                                 b 
                               
                             
                           
                         
                       
                     
                   
                   
                     
                       
                         
                           = 
                           
                             
                               24 
                               + 
                               
                                 ( 
                                 
                                   
                                     20 
                                     × 
                                     12 
                                     × 
                                     0 
                                   
                                   + 
                                   
                                     4 
                                     × 
                                     12 
                                     × 
                                     2 
                                   
                                 
                                 ) 
                               
                             
                             = 
                             120 
                           
                         
                         ; 
                       
                     
                   
                 
               
               
                 
                   ( 
                   23 
                   ) 
                 
               
             
           
         
       
     
         [0115]    The UE maps the generated SRS symbols to the sub-carriers numbered starting from k 0 , as shown in  FIG. 17 , and then adopts IFFT to translate the frequency-domain symbols to time-domain symbols and transmit the symbols through an antenna. 
         [0116]    A second embodiment is suitable for the TDD system for which  FIG. 8  shows the UE SRS configuration table. 
         [0117]    The processing flow is illustrated in  FIGS. 15A and 15B : 
         [0118]    In step  1 , the UE generates the Zadeoff-chu sequence with the length of H=m SRS,b ×12/2=4×12/2=24 according to the SRS bandwidth parameter m SRS,b =4 configured by eNB through RRC signaling. 
         [0119]    In step  2 , the UE deduces the SRS period T=5 according to the SRS period index I SRS =0 and with the information in  FIG. 8 . Moreover, the UE learns about in each radio frame the SRS index k=0, 1, 2 and 3 and the corresponding time slot index, as shown in  FIG. 18(   a ). 
         [0120]    In step  3 , before transmitting the SRS signal each time, the UE calculates the key frequency-hop parameter n SRS  according to the current SRS index k and the radio frame index n f . In this embodiment, it is assumed that the current frame&#39;s index number n f =0, and for the third transmission of the SRS, k=2. Thus, n SRS =└(n f ×10+└n s /2┘)/T┘+2×n f +k=└(0×10+└3/2┘)/5┘+2×0+2=2. 
         [0121]    In subsequent steps, the frequency-domain increment is calculated by Equation (24) as follows: 
         [0000]        F   3 (1)=└5/2┘└2/Π b′=0   2   N   b′ ┘=4  (24)
 
         [0122]    The frequency-domain location for transmitting the SRS is calculated according to Equation (25) as follows: 
         [0000]        F   3 (1) as  n   3   ={F   3 (1)+0} mod 5=4  (25)
 
         [0123]    The frequency-domain sub-carrier&#39;s start position for transmitting the SRS is calculated by Equation (26) as follows: 
         [0000]    
       
         
           
             
               
                 
                   
                     
                       
                         
                           k 
                           0 
                           ′ 
                         
                         = 
                         
                           
                             
                               ( 
                               
                                 
                                   ⌊ 
                                   
                                     
                                       N 
                                       RB 
                                       UL 
                                     
                                     / 
                                     2 
                                   
                                   ⌋ 
                                 
                                 - 
                                 
                                   
                                     m 
                                     
                                       SRS 
                                       , 
                                       0 
                                     
                                   
                                   / 
                                   2 
                                 
                               
                               ) 
                             
                             × 
                             
                               N 
                               SC 
                               RB 
                             
                           
                           + 
                           
                             k 
                             TC 
                           
                         
                       
                     
                   
                   
                     
                       
                         
                           = 
                           
                             
                               
                                 
                                   ( 
                                   
                                     
                                       ⌊ 
                                       
                                         25 
                                         / 
                                         2 
                                       
                                       ⌋ 
                                     
                                     - 
                                     
                                       20 
                                       / 
                                       2 
                                     
                                   
                                   ) 
                                 
                                 × 
                                 12 
                               
                               + 
                               0 
                             
                             = 
                             24 
                           
                         
                         ; 
                       
                     
                   
                   
                     
                       
                         
                           k 
                           0 
                         
                         = 
                         
                           
                             k 
                             0 
                             ′ 
                           
                           + 
                           
                             
                               ∑ 
                               
                                 b 
                                 = 
                                 0 
                               
                               3 
                             
                              
                             
                               2 
                               × 
                               
                                 m 
                                 
                                   SRS 
                                   , 
                                   b 
                                 
                               
                               × 
                               
                                 n 
                                 b 
                               
                             
                           
                         
                       
                     
                   
                   
                     
                       
                         
                           = 
                           
                             
                               24 
                               + 
                               
                                 ( 
                                 
                                   
                                     20 
                                     × 
                                     12 
                                     × 
                                     0 
                                   
                                   + 
                                   
                                     4 
                                     × 
                                     12 
                                     × 
                                     4 
                                   
                                 
                                 ) 
                               
                             
                             = 
                             192 
                           
                         
                         ; 
                       
                     
                   
                 
               
               
                 
                   ( 
                   26 
                   ) 
                 
               
             
           
         
       
     
         [0124]    The UE maps the generated SRS symbols to the sub-carriers numbered starting from k 0 =192, as shown in  FIG. 17 , and then adopts IFFT to translate the frequency-domain symbols to time-domain symbols and transmit the signals through an antenna. 
         [0125]    A third embodiment corresponds to the RRC indicated frequency-hop method illustrated in  FIGS. 16A and 16B . In step  1 , the UE generates the Zadeoff-chu sequence with the length of H=m SRS,b ×12/2=4×12/2=24 according to the SRS bandwidth parameter m SRS,b =4 configured by the eNB through RRC signaling. 
         [0126]    In step  2 , the UE deduces the index number n s  of the time slot where the SC-FDMA symbol for transmitting the SRS locates in each radio frame according to the SRS period index I SRS =0. The UE calculates the key frequency-hop parameter n SRS  according to the radio frame index n f  and the obtained time slot index n s . In this embodiment, it is assumed that current frame&#39;s index number n f =0, and for the second transmission of the SRS, n SRS =2×n f +└n s /10┘=└(0×2+└3/10┘)┘=0. 
         [0127]    In subsequent steps, the frequency-domain increment is calculated by Equation (27) as follows: 
         [0000]        F   3 (1)=└5/2┘└0/Π b′=0   2   N   b′ ┘=0.  (27)
 
         [0128]    It is assumed that f(n RRC )=└4n RRC /m SRS,3 ┘+2=2 in this embodiment. The frequency-domain location for transmitting the SRS is calculated according to Equation (28) as follows: 
         [0000]        F   3 (1) as  n   3   ={F   3 (1)+0+2} mod 5=2;  (28)
 
         [0129]    The frequency-domain sub-carrier&#39;s start position for transmitting the SRS is calculated by Equation (29) as 
         [0000]    
       
         
           
             
               
                 
                   
                     
                       
                         
                           k 
                           0 
                           ′ 
                         
                         = 
                         
                           
                             
                               ( 
                               
                                 
                                   ⌊ 
                                   
                                     
                                       N 
                                       RB 
                                       UL 
                                     
                                     / 
                                     2 
                                   
                                   ⌋ 
                                 
                                 - 
                                 
                                   
                                     m 
                                     
                                       SRS 
                                       , 
                                       0 
                                     
                                   
                                   / 
                                   2 
                                 
                               
                               ) 
                             
                             × 
                             
                               N 
                               SC 
                               RB 
                             
                           
                           + 
                           
                             k 
                             TC 
                           
                         
                       
                     
                   
                   
                     
                       
                         = 
                         
                           
                             
                               
                                 ( 
                                 
                                   
                                     ⌊ 
                                     
                                       25 
                                       / 
                                       2 
                                     
                                     ⌋ 
                                   
                                   - 
                                   
                                     20 
                                     / 
                                     2 
                                   
                                 
                                 ) 
                               
                               × 
                               12 
                             
                             + 
                             0 
                           
                           = 
                           24 
                         
                       
                     
                   
                   
                     
                       
                         
                           k 
                           0 
                         
                         = 
                         
                           
                             k 
                             0 
                             ′ 
                           
                           + 
                           
                             
                               ∑ 
                               
                                 b 
                                 = 
                                 0 
                               
                               3 
                             
                              
                             
                               2 
                               × 
                               
                                 m 
                                 
                                   SRS 
                                   , 
                                   b 
                                 
                               
                               × 
                               
                                 n 
                                 b 
                               
                             
                           
                         
                       
                     
                   
                   
                     
                       
                         = 
                         
                           
                             24 
                             + 
                             
                               ( 
                               
                                 
                                   20 
                                   × 
                                   12 
                                   × 
                                   0 
                                 
                                 + 
                                 
                                   4 
                                   × 
                                   12 
                                   × 
                                   2 
                                 
                               
                               ) 
                             
                           
                           = 
                           120 
                         
                       
                     
                   
                 
               
               
                 
                   ( 
                   29 
                   ) 
                 
               
             
           
         
       
     
         [0130]    The UE maps the generated SRS symbols to the sub-carriers numbered starting from k 0 =120, as shown in  FIG. 17 , and then adopts IFFT to translate the frequency-domain symbols to time-domain symbols and transmit the symbols through an antenna. 
         [0131]    A fourth embodiment is suitable for the TDD system for which  FIG. 7  shows the UE SRS configuration table. 
         [0132]    The processing flow is illustrated in  FIGS. 14A and 14B . 
         [0133]    In step  1 , the UE generates the Zadeoff-chu sequence with the length of H=m SRS,b ×12/2=4×12/2=24 according to the SRS bandwidth parameter m SRS,b =4 configured by the eNB through RRC signaling. 
         [0134]    In step  2 , the UE deduces the SRS period T=2 according to the SRS period index I SRS =0 and with the information in  FIG. 7 . Moreover, the UE learns about in each radio frame the SRS index k=0, 1 and the corresponding time slot index, as shown in  FIG. 18(   b ). 
         [0135]    In step  3 , before transmitting the SRS signal each time, the UE calculates the key frequency-hop parameter n SRS  according to a current SRS index k and the radio frame index n f . In this embodiment, it is assumed that the current frame&#39;s index number n f =1, and for the second transmission of the SRS, k=1, and L=2. Thus n SRS =n f ×2+k=1×2+1=3. 
         [0136]    In subsequent steps, the frequency-domain increment is calculated by Equation (30) as follows: 
         [0000]        F   3 (1)=└5/2┘└3/Π b′=0   2   N   b′ ┘=6  (30)
 
         [0137]    The frequency-domain location for transmitting the SRS is calculated by Equation (31) according to F 3 (1) as 
         [0000]        n   3   ={F   3 (1)+0} mod 5=1.  (31)
 
         [0138]    The frequency-domain sub-carrier&#39;s start position for transmitting the SRS is calculated by Equation (32) as 
         [0000]    
       
         
           
             
               
                 
                   
                     
                       
                         
                           
                             k 
                             0 
                             ′ 
                           
                           = 
                           
                             
                               
                                 ( 
                                 
                                   
                                     ⌊ 
                                     
                                       
                                         N 
                                         RB 
                                         UL 
                                       
                                       / 
                                       2 
                                     
                                     ⌋ 
                                   
                                   - 
                                   
                                     
                                       m 
                                       
                                         SRS 
                                         , 
                                         0 
                                       
                                     
                                     / 
                                     2 
                                   
                                 
                                 ) 
                               
                               × 
                               
                                 N 
                                 SC 
                                 RB 
                               
                             
                             + 
                             
                               k 
                               TC 
                             
                           
                         
                       
                     
                     
                       
                         
                           = 
                           
                             
                               
                                 ( 
                                 
                                   
                                     ⌊ 
                                     
                                       25 
                                       / 
                                       2 
                                     
                                     ⌋ 
                                   
                                   - 
                                   
                                     20 
                                     / 
                                     2 
                                   
                                 
                                 ) 
                               
                               × 
                               12 
                             
                             + 
                             0 
                           
                         
                       
                     
                     
                       
                         
                           = 
                           24 
                         
                       
                     
                   
                    
                   
                     
 
                   
                    
                   
                     
                       
                         
                           
                             k 
                             0 
                           
                           = 
                           
                             
                               k 
                               0 
                               ′ 
                             
                             + 
                             
                               
                                 ∑ 
                                 
                                   b 
                                   = 
                                   0 
                                 
                                 3 
                               
                                
                               
                                 2 
                                 × 
                                 
                                   m 
                                   
                                     SRS 
                                     , 
                                     b 
                                   
                                 
                                 × 
                                 
                                   n 
                                   b 
                                 
                               
                             
                           
                         
                       
                     
                     
                       
                         
                           = 
                           
                             24 
                             + 
                             
                               ( 
                               
                                 
                                   20 
                                   × 
                                   12 
                                   × 
                                   0 
                                 
                                 + 
                                 
                                   4 
                                   × 
                                   12 
                                   × 
                                   1 
                                 
                               
                               ) 
                             
                           
                         
                       
                     
                     
                       
                         
                           = 
                           72 
                         
                       
                     
                   
                 
               
               
                 
                   ( 
                   32 
                   ) 
                 
               
             
           
         
       
     
         [0139]    The UE maps the generated SRS symbols to the sub-carriers numbered starting from k 0 , as shown in  FIG. 17 , and then adopts IFFT to translate the frequency-domain symbols to time-domain symbols and transmit the symbols through an antenna. 
         [0140]    A fifth embodiment is suitable for the TDD system for which  FIG. 8  shows the UE SRS configuration table. The processing flow is illustrated in  FIGS. 15A and 15B : 
         [0141]    In step  1 , the UE generates the Zadeoff-chu sequence with the length of H=m SRS,b ×12/2=4×12/2=24 according to the SRS bandwidth parameter m SRS,b =4 configured by the eNB through RRC signaling. 
         [0142]    In step  2 , the UE deduces the SRS period T=5 according to the SRS period index I SRS =0 and with the information in  FIG. 8 . Moreover, the UE learns about in each radio frame the SRS index k=0 and 1 and the corresponding time slot index, as shown in  FIG. 18(   b ). 
         [0143]    In step  3 , before transmitting the SRS signal each time, the UE calculates the key frequency-hop parameter n SRS  according to a current SRS index k and the radio frame index n f . In this embodiment, it is assumed that current frame&#39;s index number n f =2, and for the 0 th  transmission of SRS, n SRS =└(n f ×10+└n s /2┘)/T┘+2×n f +k=└(2×10+└3/2┘)/5┘+2×2+0=8. 
         [0144]    In subsequent steps, the frequency-domain increment is calculated by Equation (33) as follows: 
         [0000]        F   3 (1)=└5/2┘└8/Π b′=0   2   N   b′ ┘=16  (33)
 
         [0145]    The frequency-domain location for transmitting the SRS is calculated according to Equation (34) as follows: 
         [0000]        F   3 (1) as  n   3   ={F   3 (1)+0} mod 5=1.  (34)
 
         [0146]    The frequency-domain sub-carrier&#39;s start position for transmitting the SRS is calculated by Equation (35) as follows: 
         [0000]    
       
         
           
             
               
                 
                   
                     
                       
                         
                           
                             k 
                             0 
                             ′ 
                           
                           = 
                           
                             
                               
                                 ( 
                                 
                                   
                                     ⌊ 
                                     
                                       
                                         N 
                                         RB 
                                         UL 
                                       
                                       / 
                                       2 
                                     
                                     ⌋ 
                                   
                                   - 
                                   
                                     
                                       m 
                                       
                                         SRS 
                                         , 
                                         0 
                                       
                                     
                                     / 
                                     2 
                                   
                                 
                                 ) 
                               
                               × 
                               
                                 N 
                                 SC 
                                 RB 
                               
                             
                             + 
                             
                               k 
                               TC 
                             
                           
                         
                       
                     
                     
                       
                         
                           = 
                           
                             
                               
                                 ( 
                                 
                                   
                                     ⌊ 
                                     
                                       25 
                                       / 
                                       2 
                                     
                                     ⌋ 
                                   
                                   - 
                                   
                                     20 
                                     / 
                                     2 
                                   
                                 
                                 ) 
                               
                               × 
                               12 
                             
                             + 
                             0 
                           
                         
                       
                     
                     
                       
                         
                           
                             = 
                             24 
                           
                           ; 
                         
                       
                     
                   
                    
                   
                     
 
                   
                    
                   
                     
                       
                         
                           
                             k 
                             0 
                           
                           = 
                           
                             
                               k 
                               0 
                               ′ 
                             
                             + 
                             
                               
                                 ∑ 
                                 
                                   b 
                                   = 
                                   0 
                                 
                                 3 
                               
                                
                               
                                 2 
                                 × 
                                 
                                   m 
                                   
                                     SRS 
                                     , 
                                     b 
                                   
                                 
                                 × 
                                 
                                   n 
                                   b 
                                 
                               
                             
                           
                         
                       
                     
                     
                       
                         
                           = 
                           
                             24 
                             + 
                             
                               ( 
                               
                                 
                                   20 
                                   × 
                                   12 
                                   × 
                                   0 
                                 
                                 + 
                                 
                                   4 
                                   × 
                                   12 
                                   × 
                                   1 
                                 
                               
                               ) 
                             
                           
                         
                       
                     
                     
                       
                         
                           
                             = 
                             72 
                           
                           ; 
                         
                       
                     
                   
                 
               
               
                 
                   ( 
                   35 
                   ) 
                 
               
             
           
         
       
     
         [0147]    The UE maps the generated SRS symbols to the sub-carriers numbered starting from k 0 =72, as shown in  FIG. 17 , and then adopts IFFT to translate the frequency-domain symbols to time-domain symbols and transmit the symbols through an antenna. 
         [0148]    A sixth embodiment corresponds to the RRC indicated frequency-hop method illustrated in  FIGS. 16A and 16B . In step  1 , the UE generates the Zadeoff-chu sequence with the length of H=m SRS,b ×12/2=4×12/2=24 according to the SRS bandwidth parameter m SRS,b =4 configured by the eNB through RRC signaling. 
         [0149]    In step  2 , the UE deduces the index number n s  of the time slot where the SC-FDMA symbol for transmitting the SRS locates in each radio frame according to SRS period index I SRS =0. The UE calculates the key frequency-hop parameter n SRS  according to the radio frame index n f  and the obtained time slot index n s . In this embodiment, it is assumed that current frame&#39;s index number n f =8, and for the second transmission of the SRS, n SRS =n f =8. 
         [0150]    In subsequent steps, the frequency-domain increment is calculated by Equation (36) as follows: 
         [0000]        F   3 (1)=└5/2┘└8/Π b′=0   2   N   b′ ┘=16  (36)
 
         [0151]    It is assumed that f(n RRC )=└4n RRC /m SRS,3 ┘+2=2 in this embodiment. The frequency-domain location for transmitting the SRS is calculated according to F 3 (1) as by Equation (37): 
         [0000]        n   3   ={F   3 (1)+0+2} mod 5=3  (37)
 
         [0152]    The frequency-domain sub-carrier&#39;s start position for transmitting the SRS is calculated by Equation (38) as follows: 
         [0000]    
       
         
           
             
               
                 
                   
                     
                       
                         
                           
                             k 
                             0 
                             ′ 
                           
                           = 
                           
                             
                               
                                 ( 
                                 
                                   
                                     ⌊ 
                                     
                                       
                                         N 
                                         RB 
                                         UL 
                                       
                                       / 
                                       2 
                                     
                                     ⌋ 
                                   
                                   - 
                                   
                                     
                                       m 
                                       
                                         SRS 
                                         , 
                                         0 
                                       
                                     
                                     / 
                                     2 
                                   
                                 
                                 ) 
                               
                               × 
                               
                                 N 
                                 SC 
                                 RB 
                               
                             
                             + 
                             
                               k 
                               TC 
                             
                           
                         
                       
                     
                     
                       
                         
                           = 
                           
                             
                               
                                 ( 
                                 
                                   
                                     ⌊ 
                                     
                                       25 
                                       / 
                                       2 
                                     
                                     ⌋ 
                                   
                                   - 
                                   
                                     20 
                                     / 
                                     2 
                                   
                                 
                                 ) 
                               
                               × 
                               12 
                             
                             + 
                             0 
                           
                         
                       
                     
                     
                       
                         
                           
                             = 
                             24 
                           
                           ; 
                         
                       
                     
                   
                    
                   
                     
 
                   
                    
                   
                     
                       
                         
                           
                             k 
                             0 
                           
                           = 
                           
                             
                               k 
                               0 
                               ′ 
                             
                             + 
                             
                               
                                 ∑ 
                                 
                                   b 
                                   = 
                                   0 
                                 
                                 3 
                               
                                
                               
                                 2 
                                 × 
                                 
                                   m 
                                   
                                     SRS 
                                     , 
                                     b 
                                   
                                 
                                 × 
                                 
                                   n 
                                   b 
                                 
                               
                             
                           
                         
                       
                     
                     
                       
                         
                           = 
                           
                             24 
                             + 
                             
                               ( 
                               
                                 
                                   20 
                                   × 
                                   12 
                                   × 
                                   0 
                                 
                                 + 
                                 
                                   4 
                                   × 
                                   12 
                                   × 
                                   3 
                                 
                               
                               ) 
                             
                           
                         
                       
                     
                     
                       
                         
                           
                             = 
                             168 
                           
                           ; 
                         
                       
                     
                   
                 
               
               
                 
                   ( 
                   38 
                   ) 
                 
               
             
           
         
       
     
         [0153]    The UE maps the generated SRS symbols to the sub-carriers numbered starting from k 0 =168, as shown in  FIG. 17 , and then adopts IFFT to translate the frequency-domain symbols to time-domain symbols and transmit the symbols through an antenna.
Disclosed are a method and apparatus for transmitting an uplink Sounding Reference Signal (SRS), the method including identifying a number of downlink and uplink switch points within a radio frame N sp  and a system frame number n f , calculating a value of n SRS  according to a number of downlink and uplink switch points within a radio frame N sp , and the system frame number n f  for transmitting the SRS, determining a frequency-domain starting position of the SRS with n SRS , and transmitting the SRS at the determined frequency-domain starting position.