def parse_kwargs(kwargs):
    """
    Convert a list of kwargs into a dictionary. Duplicates of the same keyword
    get added to an list within the dictionary.

    >>> parse_kwargs(['--var1=1', '--var2=2', '--var1=3']
    {'var1': [1, 3], 'var2': 2}
    """
    
    d = defaultdict(list)
    for k, v in ((k.lstrip('-'), v) for k,v in (a.split('=') for a in kwargs)):
        d[k].append(v)

    ret = {}
    for k, v in d.items():
        # replace single item lists with just the item.
        if len(v) == 1 and type(v) is list:
            ret[k] = v[0]
        else:
            ret[k] = v
    return ret
def parse_kwargs ( kwargs ) : d = defaultdict ( list ) for k , v in ( ( k . lstrip ( '-' ) , v ) for k , v in ( a . split ( '=' ) for a in kwargs ) ) : d [ k ] . append ( v ) ret = { } for k , v in d . items ( ) : if len ( v ) == 1 and type ( v ) is list : ret [ k ] = v [ 0 ] else : ret [ k ] = v return ret
Convert a list of kwargs into a dictionary. Duplicates of the same keyword
    get added to an list within the dictionary.

    >>> parse_kwargs(['--var1=1', '--var2=2', '--var1=3']
    {'var1': [1, 3], 'var2': 2}