def first(seq, key=lambda x: bool(x), default=None, apply=lambda x: x):
    """Give the first value that satisfies the key test.

    Args:
        seq (iterable):
        key (callable): test for each element of iterable
        default: returned when all elements fail test
        apply (callable): applied to element before return, but not to default value

    Returns: first element in seq that passes key, mutated with optional apply

    Examples:
        >>> first([0, False, None, [], (), 42])
        42
        >>> first([0, False, None, [], ()]) is None
        True
        >>> first([0, False, None, [], ()], default='ohai')
        'ohai'
        >>> import re
        >>> m = first(re.match(regex, 'abc') for regex in ['b.*', 'a(.*)'])
        >>> m.group(1)
        'bc'

        The optional `key` argument specifies a one-argument predicate function
        like that used for `filter()`.  The `key` argument, if supplied, must be
        in keyword form.  For example:
        >>> first([1, 1, 3, 4, 5], key=lambda x: x % 2 == 0)
        4

    """
    return next((apply(x) for x in seq if key(x)), default() if callable(default) else default)
def first ( seq , key = lambda x : bool ( x ) , default = None , apply = lambda x : x ) : return next ( ( apply ( x ) for x in seq if key ( x ) ) , default ( ) if callable ( default ) else default )
Give the first value that satisfies the key test.

    Args:
        seq (iterable):
        key (callable): test for each element of iterable
        default: returned when all elements fail test
        apply (callable): applied to element before return, but not to default value

    Returns: first element in seq that passes key, mutated with optional apply

    Examples:
        >>> first([0, False, None, [], (), 42])
        42
        >>> first([0, False, None, [], ()]) is None
        True
        >>> first([0, False, None, [], ()], default='ohai')
        'ohai'
        >>> import re
        >>> m = first(re.match(regex, 'abc') for regex in ['b.*', 'a(.*)'])
        >>> m.group(1)
        'bc'

        The optional `key` argument specifies a one-argument predicate function
        like that used for `filter()`.  The `key` argument, if supplied, must be
        in keyword form.  For example:
        >>> first([1, 1, 3, 4, 5], key=lambda x: x % 2 == 0)
        4