Solve the following sql problem:
When compared to the total number of breweries in the US producing American Blonde Ale, how many in the state of Wisconsin produces American Blonde Ale? Indicate your answer in percentage (%).

Schema:
SCHEMA:
- Table: breweries
  - Column: id
    - Samples: [0, 1, 2, 3, 4]
  - Column: name
    - Samples: [NorthGate Brewing , Against the Grain Brewery, Jack's Abby Craft Lagers, Mike Hess Brewing Company, Fort Point Beer Company]
  - Column: city
    - Samples: [Minneapolis, Louisville, Framingham, San Diego, San Francisco]
  - Column: state
    - Samples: [MN, KY, MA, CA, CA]
- Table: beers
  - Column: id
    - Samples: [1, 4, 5, 6, 7]
  - Column: brewery_id
    - Samples: [166, 166, 166, 166, 166]
  - Column: abv
    - Samples: [0.065, 0.087, 0.08, 0.099, 0.053]
  - Column: ibu
    - Samples: [65.0, 85.0, 35.0, 100.0, 35.0]
  - Column: name
    - Samples: [Dale's Pale Ale, Gordon Ale (2009), Old Chub, GUBNA Imperial IPA, Mama's Little Yella Pils]
  - Column: style
    - Samples: [American Pale Ale (APA), American Double / Imperial IPA, Scottish Ale, American Double / Imperial IPA, Czech Pilsener]
  - Column: ounces
    - Samples: [12.0, 12.0, 12.0, 12.0, 12.0]

SELECT CAST(SUM(IIF(T2.state = 'WI', 1, 0)) AS REAL) * 100 / COUNT(T1.id) FROM beers AS T1 INNER JOIN breweries AS T2 ON T1.brewery_id = T2.id WHERE T1.style = 'American Blonde Ale'