Caden has four jars of coins. One jar of pennies, one jar of nickels, one jar of dimes and one jar of quarters. He has twice as many quarters as he does dimes. He has five times as many nickels as he does dimes. He has three times as many pennies as he does nickels. If he has 120 pennies, how much money does he have?
Starting with 120 pennies he has $1.20
If he has three times as many pennies as he does nickels, he has 120 pennies / 3 nickels per penny = 40 nickels. 40 nickels = 40 * $0.05 = $<<40*0.05=2>>2
If he has five times as many nickels as dimes he has 40 nickels / 5 dimes per nickel = 8 dimes. 8 * $0.10 = $<<40/5*0.10=0.80>>0.80
if he has twice as many quarters than he does dimes, he has 8 dimes * 2 quarters per dime = 16 quarters = 16 *$ 0.25 = $<<8*2*0.25=4.00>>4.00
In all he has $1.20 + $2.00 + $0.80 + $4.00 = $<<1.20+2+0.8+4=8.00>>8.00
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Caden'ın dört kavanoz bozuk parası var. Bir kavanoz bozuk para, bir kavanoz beş sent, bir kavanoz on sent ve bir kavanoz da çeyrek sent. Onlukların iki katı kadar çeyrekliği var. On sentlerin beş katı kadar nikeli var. Bozuk paraların üç katı kadar bozuk parası var. Eğer 120 kuruşu varsa, ne kadar parası vardır?
120 peni ile başladığında 1,20 doları vardır.
Eğer bozuk parasının üç katı kadar bozuk parası varsa, 120 bozuk para / bozuk para başına 3 bozuk para = 40 bozuk parası vardır. 40 nikel = 40 * 0,05 $ = $<<40*0,05=2>>2
Eğer on sentlerin beş katı kadar nikeli varsa, 40 nikeli / nikel başına 5 on sent = 8 on senti vardır. 8 * $0.10 = $<<40/5*0.10=0.80>>0.80
Eğer on sentlerinin iki katı kadar çeyrek senti varsa, 8 on sent * on sent başına 2 çeyrek sent = 16 çeyrek sent = 16 * 0.25 $ = <<8*2*0.25=4.00>>4.00 $
Toplamda 1.20$ + 2.00$ + 0.80$ + 4.00$ = <1.20+2+0.8+4=8.00>>8.00$
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