If Ken's house is twice as far from Dawn's house as Mary's house along a certain road, and Ken's house is 4 miles away from Dawn's house along this same road, how much distance (in miles) will Ken cover if he goes from his house to Dawn's house, then Mary's, then back to Dawn's before going back to his own house?
Ken's house is twice as far from Dawn's house as Mary's, so the distance between Ken's and Mary's is half that between Ken's and Dawn's (4 miles) which means the former is (1/2)*4 miles = <<4*1/2=2>>2 miles
If Ken goes from his house to Dawn's, he has covered 4 miles
He goes from there to Mary's (2 miles, same as Ken's to Mary's) for a total of 4+2 = <<4+2=6>>6 miles.
He goes back to Dawn's (another 2 miles) for a total of 6+2 = <<6+2=8>>8 miles
Then he goes to his own house (4 miles) for a final total of 8+4 = <<8+4=12>>12 miles
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Eğer Ken'in evi Dawn'ın evinden Mary'nin evinden iki kat daha uzaktaysa ve Ken'in evi Dawn'ın evinden aynı yol boyunca 4 mil uzaktaysa, Ken kendi evinden Dawn'ın evine, sonra Mary'nin evine, sonra Dawn'ın evine gidip kendi evine dönerse (mil olarak) ne kadar mesafe kat etmiş olur?
Ken'in evi Dawn'ın evinden Mary'ninkinin iki katı uzaktadır, bu nedenle Ken'in evi ile Mary'nin evi arasındaki mesafe Ken'in evi ile Dawn'ın evi arasındaki mesafenin yarısıdır (4 mil), bu da ilkinin (1/2)*4 mil = <<4*1/2=2>>2 mil olduğu anlamına gelir
Ken kendi evinden Dawn'ın evine giderse 4 mil yol kat etmiş olur.
Oradan Mary'ye (2 mil, Ken'den Mary'ye olanla aynı) toplam 4+2 = <<4+2=6>>6 mil gider.
Dawn'a geri dönüyor (2 mil daha) toplam 6+2 = <<6+2=8>>8 mil
Sonra kendi evine gider (4 mil) ve toplamda 8+4 = <<8+4=12>>12 mil yapar.
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