Steve is holding nickels and dimes in his hand. He has 4 more dimes than nickels. He has a total of 70 cents in his hand. How many nickels is he holding?
Let x be the number of nickels he is holding.
His nickels are worth 5 * x = 5x cents.
He has x+4 dimes.
The dimes are worth 10 * (x+4)
The total worth of the nickels and dimes is 5x + 10*(x+4) = 70.
5x + 10x + 40 = 70
15x = 30
x = <<2=2>>2, Steve has 2 nickels in his hand.
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Steve elinde bozuk para ve on sent tutuyor. Beş sentten 4 tane daha fazla on senti var. Elinde toplam 70 sent var. Elinde kaç tane bozuk para var?
Elindeki bozuk para sayısı x olsun.
Elindeki bozuk paralar 5 * x = 5x sent değerindedir.
Elinde x+4 kuruş var.
On sentlerin değeri 10 * (x+4)
Beşlik ve onlukların toplam değeri 5x + 10*(x+4) = 70'tir.
5x + 10x + 40 = 70
15x = 30
x = <<2=2>>2, Steve'in elinde 2 tane bozuk para var.
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