@[USERNAME]The fact that A^T * A and A * A^T have the same non-zero eigenvalues is blowing my mind right now. I guess this is intimately related to the fact that det(B) = det(B^T), since det is where we get the characteristic polynomial/egenvalues...####[['A^T * A', 'Mathematical_Related_Concept', 'NEU'], ['A * A^T', 'Mathematical_Related_Concept', 'NEU'], ['det(B) = det(B^T),', 'Mathematical_Related_Concept', 'NEU']]