How can he compare sum of areas to volume? Its better if we use n*(n+1)*(2n+1)/6 to represent the sum of n^2 terms and compare it with other two terms.####[['sum of areas to volume', 'Mathematical_Related_Concept', 'NEU'], ['n*(n+1)*(2n+1)/6', 'Mathematical_Related_Concept', 'NEU'], ['sum of n^2 terms', 'Mathematical_Related_Concept', 'NEU']]