Can anyone clarify my question....!At 32.01 it was told that r12(n) = 1- r11(n)... it is correct intuitively but if i calculate r12(n) using normal method i got it as r11(n-1)0.5+r12(n-1)0.8 which is not same as 1- r11(n) (Here r11(n)  = r11(n-1)0.2+r12(n-1)0.5)####[['r12(n)', 'Mathematical_Related_Concept', 'NEU'], ['r12(n) = 1- r11(n)', 'Mathematical_Related_Concept', 'NEU'], ['r11(n-1)0.5+r12(n-1)0.8', 'Mathematical_Related_Concept', 'NEU'], ['1- r11(n)', 'Mathematical_Related_Concept', 'NEU'], ['r11(n) \xa0= r11(n-1)0.2+r12(n-1)0.5', 'Mathematical_Related_Concept', 'NEU']]