It is so easy to differentiate I got e^(xarctan(x))[arctan(x)+(x/(1+x^2))] in about 1 minute and this is right because I checked it on Wolfram Alpha and they are only doing it at the end of this degree level unit.I thought USA was good at education.I'm in Year 12 in the UK by the way.####[['e^(xarctan(x))[arctan(x)+(x/(1+x^2))]', 'Mathematical_Related_Concept', 'NEU']]