Return a nodeid by name

def nodeByName(self, name):
        """ Return a nodeid by name """
        # note: really long names are encoded differently:
        #  'N'+'\x00'+pack('Q', nameid)  => ofs
        #  and  (ofs, 'N') -> nameid

        # at nodebase ( 0xFF000000, 'S', 0x100*nameid )  there is a series of blobs for max 0x80000 sized names.
        cur = self.btree.find('eq', self.namekey(name))
        if cur:
            return struct.unpack('<' + self.fmt, cur.getval())[0]