Update the old_opts option dictionary with the options defined in
    new_opts. Instead of a shallow update as would be performed by calling
    old_opts.update(new_opts), this updates the dictionaries of all option
    types separately.

    Given two dictionaries
        old_opts = {'a': {'x': 'old', 'y': 'old'}}
    and
        new_opts = {'a': {'y': 'new', 'z': 'new'}, 'b': {'k': 'new'}}
    this returns a dictionary
        {'a': {'x': 'old', 'y': 'new', 'z': 'new'}, 'b': {'k': 'new'}}

def merge_option_dicts(old_opts, new_opts):
    """
    Update the old_opts option dictionary with the options defined in
    new_opts. Instead of a shallow update as would be performed by calling
    old_opts.update(new_opts), this updates the dictionaries of all option
    types separately.

    Given two dictionaries
        old_opts = {'a': {'x': 'old', 'y': 'old'}}
    and
        new_opts = {'a': {'y': 'new', 'z': 'new'}, 'b': {'k': 'new'}}
    this returns a dictionary
        {'a': {'x': 'old', 'y': 'new', 'z': 'new'}, 'b': {'k': 'new'}}
    """
    merged = dict(old_opts)

    for option_type, options in new_opts.items():
        if option_type not in merged:
            merged[option_type] = {}

        merged[option_type].update(options)

    return merged