Same as search, but will throw an error if there are multiple or no
            results. If there are multiple results and only one is an exact match
            on api_version, that resource will be returned.

def get(self, **kwargs):
        """ Same as search, but will throw an error if there are multiple or no
            results. If there are multiple results and only one is an exact match
            on api_version, that resource will be returned.
        """
        results = self.search(**kwargs)
        # If there are multiple matches, prefer exact matches on api_version
        if len(results) > 1 and kwargs.get('api_version'):
            results = [
                result for result in results if result.group_version == kwargs['api_version']
            ]
        # If there are multiple matches, prefer non-List kinds
        if len(results) > 1 and not all([isinstance(x, ResourceList) for x in results]):
            results = [result for result in results if not isinstance(result, ResourceList)]
        if len(results) == 1:
            return results[0]
        elif not results:
            raise ResourceNotFoundError('No matches found for {}'.format(kwargs))
        else:
            raise ResourceNotUniqueError('Multiple matches found for {}: {}'.format(kwargs, results))