Run the pymongo insert_one command against the default database and collection
        and returne the inserted ID.

def insert_one(self, *args, **kwargs):
        """
        Run the pymongo insert_one command against the default database and collection
        and returne the inserted ID.
        """
        # print(f"database.collection: '{self.database.name}.{self.collection.name}'")
        result = self.collection.insert_one(*args, **kwargs)
        return result.inserted_id