# Compare Version Numbers

'''
Compare two version numbers version1 and version2.
If version1 > version2 return 1; if version1 < version2 return -1;otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and the . character.

The . character does not represent a decimal point and is used to separate number sequences.

For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.

You may assume the default revision number for each level of a version number to be 0. For example, version number 3.4 has a revision number of 3 and 4 for its first and second level revision number. Its third and fourth level revision number are both 0.

 

Example 1:

Input: version1 = "0.1", version2 = "1.1"
Output: -1
Example 2:

Input: version1 = "1.0.1", version2 = "1"
Output: 1
Example 3:

Input: version1 = "7.5.2.4", version2 = "7.5.3"
Output: -1
Example 4:

Input: version1 = "1.01", version2 = "1.001"
Output: 0
Explanation: Ignoring leading zeroes, both “01” and “001" represent the same number “1”
Example 5:

Input: version1 = "1.0", version2 = "1.0.0"
Output: 0
Explanation: The first version number does not have a third level revision number, which means its third level revision number is default to "0"
 

Note:

Version strings are composed of numeric strings separated by dots . and this numeric strings may have leading zeroes.
Version strings do not start or end with dots, and they will not be two consecutive dots.
'''

class Solution:
    def compareVersion(self, v1: str, v2: str) -> int:
        
        v1 = v1.split('.')
        v2 = v2.split('.')
        
        while v1 or v2:
            
            if not v1:
                n1 = 0
            else:
                n1 = int(v1.pop(0))
            
            if not v2:
                n2 = 0
            else:
                n2 = int(v2.pop(0))
                 
            if n1!=n2:
                if n1>n2:
                    return 1

                elif n1<n2:
                    return -1
        return 0
                
            
# Compare Version Numbers

'''
Compare two version numbers version1 and version2.
If version1 > version2 return 1; if version1 < version2 return -1;otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and the . character.

The . character does not represent a decimal point and is used to separate number sequences.

For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.

You may assume the default revision number for each level of a version number to be 0. For example, version number 3.4 has a revision number of 3 and 4 for its first and second level revision number. Its third and fourth level revision number are both 0.

 

Example 1:

Input: version1 = "0.1", version2 = "1.1"
Output: -1
Example 2:

Input: version1 = "1.0.1", version2 = "1"
Output: 1
Example 3:

Input: version1 = "7.5.2.4", version2 = "7.5.3"
Output: -1
Example 4:

Input: version1 = "1.01", version2 = "1.001"
Output: 0
Explanation: Ignoring leading zeroes, both “01” and “001" represent the same number “1”
Example 5:

Input: version1 = "1.0", version2 = "1.0.0"
Output: 0
Explanation: The first version number does not have a third level revision number, which means its third level revision number is default to "0"
 

Note:

Version strings are composed of numeric strings separated by dots . and this numeric strings may have leading zeroes.
Version strings do not start or end with dots, and they will not be two consecutive dots.
'''

class Solution:
    def compareVersion(self, v1: str, v2: str) -> int:
        
        v1 = v1.split('.')
        v2 = v2.split('.')
        
        while v1 or v2:
            
            if not v1:
                n1 = 0
            else:
                n1 = int(v1.pop(0))
            
            if not v2:
                n2 = 0
            else:
                n2 = int(v2.pop(0))
                 
            if n1!=n2:
                if n1>n2:
                    return 1

                elif n1<n2:
                    return -1
        return 0
                
            
# Compare Version Numbers Compare two version numbers version1 and version2. If version1 > version2 return 1; if version1 < version2 return -1;otherwise return 0.  You may assume that the version strings are non-empty and contain only digits and the . character.  The . character does not represent a decimal point and is used to separate number sequences.  For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.  You may assume the default revision number for each level of a version number to be 0. For example, version number 3.4 has a revision number of 3 and 4 for its first and second level revision number. Its third and fourth level revision number are both 0.     Example 1:  Input: version1 = "0.1", version2 = "1.1" Output: -1 Example 2:  Input: version1 = "1.0.1", version2 = "1" Output: 1 Example 3:  Input: version1 = "7.5.2.4", version2 = "7.5.3" Output: -1 Example 4:  Input: version1 = "1.01", version2 = "1.001" Output: 0 Explanation: Ignoring leading zeroes, both “01” and “001" represent the same number “1” Example 5:  Input: version1 = "1.0", version2 = "1.0.0" Output: 0 Explanation: The first version number does not have a third level revision number, which means its third level revision number is default to "0"    Note:  Version strings are composed of numeric strings separated by dots . and this numeric strings may have leading zeroes. Version strings do not start or end with dots, and they will not be two consecutive dots.