Now, I want to know, in either of these scenarios, what is the percent probability of getting four heads? So if given I've got the unfair coin, the probability of getting four heads is going to be 55% for each of those flips. So the probability of getting exactly four heads is going to be 0.55 times 0.55 times 0.55 times 0.55. And so the probability of picking an unfair coin and getting four heads in a row is going to be equal to 3 4ths times all of this business over here. So that's 3 4ths times, and this is 0.55 times itself four times. So I could write it as 0.55 to the fourth power. And we'll get the calculator out in a second to actually calculate what this is.