So let's divide both sides of this equation by this term right here, by the mean of the x's. And if we do that, we get m times the mean of the x squareds divided by the mean of the x's plus b is equal to the mean of the xy's divided by the mean of the x's. And so when you write it in this form, this is the exact same equation as that. I just divided both sides by the mean of the x's. You get another interesting point that will lie on this optimal fitting line, at least from the point of view of the squared distances. So another point that will lie on it. So another point that will lie on this optimal line is going to be the point, the x value is going to be this.