So first of all, the first person could be born on any day, then the second person could be born on 364 possible days out of 365, and then the third person, what's the probability that this third person isn't born on either of these people's birthdays? So two days are taken up, so the probability is 363 over 365. So this is equal to, you multiply them out, you get 365 times 360. Actually, I should rewrite this one. Instead of saying this is 1, let me write this as, the numerator is 365 times 364 over 365 squared. Because I want you to see the pattern, right? Here the probability is 365 times 364 times 363 over 365 to the third power.