a is, sorry, as x approaches infinity, what does n approach? Well, n is x divided by a, right? So n would also approach infinity. So this thing would be the same thing as just making our substitution. The limit as n approaches infinity of 1 plus a over x, I mean the substitution is 1 over n, and x is, by this substitution, n times a. And this is going to be the same thing as the limit as n approaches infinity of 1 plus 1 over n to the n, all of that, to the a. And since there's no n out here, we could just take the limit of this and then take that to the a power, so that's going to be equal to the limit as n approaches infinity of 1 plus 1 over n to the nth power, all of that, to the a.