So we know that the variance, or we could almost say the variance of the mean, or the standard error, well, you know, the variance of the sampling distribution of the sample mean is equal to the variance of our original distribution divided by n. Take the square roots of both sides, and then you get standard error of the mean is equal to standard deviation of your original distribution divided by the square root of n. So let's see if this works out for these two things. So if I were to take 9.3, so let me do this case. So 9.3 divided by the square root of 16, right? N is 16. So divided by the square root of 16, which is four, what do I get? So 9.3 divided by four. Let me get a little calculator out here.