But it is symmetric, and that point of symmetry is right over here, and so this value, once again, would be the median. Another way to think about it is the area to the left of that value is equal to the area to the right of that value, making it the median. What if we're dealing with non-symmetric distributions? Well, we'd want to do the same principle. We'd want to think at what value is the area on the right and the area on the left equal? And once again, this isn't going to be super exact, but I'm going to try to approximate it. You might be tempted to go right at the top of this lump right over here, but if I were to do that, it's pretty clear, even eyeballing it, that the right area right over here is larger than the left area.