I just divided both sides by the mean of the x's. You get another interesting point that will lie on this optimal fitting line, at least from the point of view of the squared distances. So another point that will lie on it. So another point that will lie on this optimal line is going to be the point, the x value is going to be this. So it's going to be the coordinate, the mean of the x squareds divided by the mean of the x's. And then the y value is going to be the mean of the xy's divided by the mean of the x's. And I'll let you think about that a little bit more.