So this is equal to the sum from i equals 1 to n of x sub i squared, and let's see, minus 2 times mu. Sorry, that mu doesn't look good. Edit, undo. Minus 2 times mu times the sum from i is equal to 1 to n of x i, and then what is this? What is another way to write this, right? Essentially we're going to add 1 to itself n times, right? This is kind of saying just look, whatever you have here, just iterate through it n times.