I'm not talking about taking 2 rolls of this die. So in this situation, there are 6 possibilities, but none of these possibilities are 2 and a 3. 2 and a 3 cannot exist on one trial. You cannot get a 2 and a 3 in the same experiment. Getting a 2 and a 3 are mutually exclusive events. They cannot happen at the same time. So the probability of this is actually 0.