So that all seems reasonable, kind of consistent with method two, except now instead of 75, it's 30. And obviously, 75 was overkill. Even here, this is overkill. He just really needs 15 pieces of paper. And he then counts the number of windows in the room and chooses the volunteer with that number. So the question here is, is the number of windows in the room, is it random, and is it evenly distributed? So maybe you could make a case that depending on what building it's in and someone's house, it's somewhat random on how many windows that house happens to have, the house that's happening to host the birthday party.