And then if we want to, this isn't in simplified form right here, since both twelve and fourteen are divisible by two. So let's divide both the numerator and the denominator by two, and you get six over seven. So we have a six-seventh chance of selecting a non-blue marble from the bag. Let's do another one. If a number is randomly chosen from the following list, what is the probability that the number is a multiple of five? So once again, we want to find the fraction of the total possibilities that meet our constraint. And our constraint is being a multiple of five.