One minus that is gonna be the proportion that scores more than him. The reason why we have to do this is because the z-table gives us the proportion less than a certain z-score. So this gives us right over here, 0.0062. So that's the proportion. If you thought of it in percent, it would be.62% scores higher than Ludwig. And that makes sense, because Ludwig scored over two standard deviations, two and a half standard deviations above the mean. So our answer here is 0.0062.