Now what's the limit as n approaches infinity of this thing right here? 1 minus lambda over n to the n. Well, in the last video we showed that it would be, I'll write it right here, that the limit as n approaches infinity of 1 plus a over n to the n is equal to e to the a, right? That's exactly what we have here, but instead of an a, we have a minus lambda, right? Minus lambda, so this is going to be equal to e to the minus lambda, right? We have a minus lambda instead of an a. And then finally, what's the limit as n approaches infinity? Let me write it a little bit neater.