If you multiply both the numerator and the denominator by negative 1, you could see this written as the mean of the xy's minus the mean of x times the mean of the y's, all of that over the mean of the x squared's minus the mean of the x's squared. These are obviously the same thing. They're just multiplying the numerator and the denominator by negative 1, which is the same thing as multiplying the whole thing by 1. And of course, whatever you get for y, oh sorry, whatever you get for m, you can then just substitute back in this, back over here to get your b. Your b is going to be equal to the mean of the y's minus your m, whatever m value you got over here. Let me write that in yellow so it's very clear. You solved for the m value here.