Let me do another one. My second sample of size 4, let's say that I get a 3, a 4, let's say I get another 3, and let's say I get a 1. I just didn't happen to get a 6 that time. And notice, I can't get a 2 or a 5. It's impossible for this distribution. The chance of getting a 2 or a 5 is 0, so I can't have any 2s or 5s over here. So for the second sample of sample size 4, my sample mean, so my second sample mean is going to be 3 plus 4 is 7, 7 plus 3 is 10, plus 1 is 11, 11 divided by 4, once again is 2.75.