But the expected value of a geometric random variable is gonna be one over the probability of success on any given trial. So now let's prove it to ourselves. So the expected value of any random variable is just going to be the probability weighted outcomes that you could have. So you could say it is the probability, the probability that our random variable is equal to one times one plus the probability that our random variable is equal to two times two plus, and you get the general idea, it goes on and on and on. And a geometric random variable, it can only take on values one, two, three, four, so forth and so on. It will not take on the value zero because you cannot have a success if you have not had a trial yet. But what is this going to be equal to?