A can go into any of the three spaces. Then B would have two spaces left once A takes one of them. And then C would have one space left once A and B take two of them. So there's three times two times one way to arrange three different things. So three times two times one is equal to six. So the number of possibilities of getting three heads is actually going to be this 5 times 4 times 3. Let me write this down in another color.