So we can apply that to a problem that is harder to do than writing all of the scenarios like we did in the first problem, we can say, let's say we have 10 flips, the probability of at least 1 head in 10 flips. Well, we use the same idea, this is the same thing, this is going to be equal to the probability of not all tails in 10 flips. So we're just saying the probability of not getting all of the flips going to be tails, all of the flips is tails, not all tails in 10 flips. And this is going to be 1 minus the probability of flipping tails 10 times. So it's 1 minus 10 tails in a row. And so this is going to be equal to, this part right over here, let me write this. So this is going to be this 1, let me just rewrite it, this is equal to 1 minus, and this part is going to be, well, 1 tail, another tail, so it's 1 half times 1 half, and I'm going to do this 10 times.