And that's what we showed in the calculus playlist, that an integral actually is kind of this infinite sum of infinitely small things, but I don't want to digress too much, but this was just a long way of saying that the sum from i equals 1 to n of the second term is the same thing as minus 2 times mu of the sum from i is equal to 1 to n of x sub i. And then finally, you have plus, well this is just a constant term, right? This is just a constant term, so you can take it out, times mu squared times the sum from i equals 1 to n. And what's going to be here? It's going to be a 1. We just divided a 1, we just divided this by 1, took it out of the sigma sign, out of the sum, and you're just left with a 1 there. And actually, we could have just left the mu squared there. But either way, let's just keep simplifying it.