So on either side of four, g prime prime of x is greater than zero. So even though the second derivative at x equals four is equal to zero, on either side, we are concave upwards. On either side, the second derivative is positive, and so, and that was the only potential candidate, so there are no values of x for which g has a point of inflection. X equals four would have been a value of x at which g had a point of inflection if we switch, if the second derivative switched signs here, if it went from positive to negative or negative to positive, but it's just staying from positive to positive. So the second derivative is positive. It just touches zero right here, and then it goes positive again. So going back to the question, for what x values does the graph of g have a point of inflection?