I haven't used this initial condition yet, we could call it. So let me just subtract c one from both sides. So if I just subtract c one from both sides, I have an arbitrary, so this is going to cancel, and I have c two, sorry, let me, so this is c one, so these are going to cancel, and c two minus c one, these are both constants, arbitrary constants, we don't know what they are yet, and so we could just rewrite this as, on the left-hand side we have y squared over two is equal to, on the right-hand side, I'll write one half e, let me write that in blue, just because I wrote it in blue before, one half, one half e to the negative x squared, and I'll just say c two minus c one, let's just call that c. So if you take the sum of those two things, let's just call that c. And so now, this is kind of a general solution, we don't know what this constant is, and we haven't explicitly solved for y yet, but even in this form, we can now find a particular solution using this initial condition. Let me separate it out, this wasn't part, this wasn't part of this original expression right over here, but using this initial condition. So it tells us when x is zero, y needs to be equal to one. So we would have one squared, which is just one, over two is equal to one half, e to the negative zero squared, well that's just going to be, e to the zero is just one, so it's going to be one half plus c, and just like that, we're able to figure out if you subtract one half from both sides, c is equal to zero. So the relationship between y and x that goes through this point, we could just set c is equal to zero, so that's equal to zero, that's zero right over there, and so we are left with y squared over two is equal to e to the negative x squared over two.