Write an equation for the line tangent to the curve at the point negative one comma one. Alright, so we can figure out the equation for the line if we know the slope of the line and we know a point that it goes through, so that should be enough to figure out the equation of the line. So, the line's going to have a form y is equal to mx plus b. M is the slope and is going to be equal to dy dx at that point. And we know that that's going to be equal to, let's see, y is, when x is negative one, y is one, that sits on this curve. So y is one, so one, over three y squared. So three times one squared, which is three, minus x. When y is one, x is negative one, or when x is negative one, y is one.