So I encourage you to try to do that. So once again, this is, let me rewrite all of this. This is going to be equal to, this over here is the exact same thing as the definite integral from a to b of f prime of x dx. Think about it. You're gonna take the antiderivative of f prime of x, which is going to be f of x, and you're going to evaluate it at b, f of b, and then from that, you're going to subtract it, evaluate it at a, minus f of a. These two things are identical, and then you can, of course, divide by b minus a. Now this is starting to get interesting.