And let's see, we are going to have, when x is equal to one, h prime of one is three times one minus two squared. One minus two, negative one squared is positive one times three is still positive. And then three, well, three minus two squared times three, that's also gonna be three. So this is actually a situation where, like I just drawn it, where our slope is positive before we hit the critical point. It gets to zero, but then it starts becoming positive again. And so that's why you actually have to do this test in order to identify whether it's an extremum. It turns out that this is not an extremum.