So before I even look at this, what do we know about the intermediate value theorem? Well, it applies here. It's a continuous function on this closed interval. We know what the value of the function is at negative two. It's three, so let me write that. F of negative two is equal to three and f of one, they tell us right over here, is equal to six. And all the intermediate value theorem tells us, and if this is completely unfamiliar to you, I encourage you to watch the video on the intermediate value theorem, is that if we have a continuous function on some closed interval, then the function must take on every value between the values at the end points of the interval.