So it's approximately equal to 1.949, approximately 1.949. Now let's do part c. So part c, find the total distance traveled by the particle from time t equals zero to t equals six. So you might say, hey, didn't we just figure that out? No, this is displacement, and to remember the difference between distance and displacement, if I have something that starts here, it goes over there, and then it comes back to right over there, the distance traveled is the total path length, so it would be that plus this, while the displacement would just be this right over here. So if you wanna figure out distance, what you wanna do is take the integral of the absolute value of velocity. You could think about it as you're taking the integral of the speed function. So this is just going to be the integral from zero to six of the absolute value of v of t dt, and then we can type this, actually let me just write it out since you would wanna do this if you're actually taking the test.