So I'm just gonna try to simplify this denominator so that my coefficient on my x squared term is a one. And so I can just factor a five out of the denominator. And if I did that, then this integral will become 1 5th times the integral of one over, so I factored a five out of the denominator. So it is x squared minus six x plus 13 dx. And then as I mentioned, I'm gonna complete the square down here. So let me rewrite it. So this is equal to 1 5th times the integral of one over, and so x squared minus six x.