And one over x is not continuous over that interval. It is not defined when x is equal to zero. And so we could say no, because, because g of x not defined, not defined, or I could say, let me just say not continuous. It's also not defined on every point of the interval, but let's say not continuous over the closed interval from negative one to one. And we could even put parentheses not defined, not defined at x is equal to zero. All right, now let's start asking the second question. Can we use the intermediate value theorem to say that the equation g of x is equal to 3 4ths has a solution where one is less than or equal to x is less than or equal to two?