Y is negative 16 over x. Negative 16 over x. And then that's what we will now square. So this is equal to x squared plus, what is this? 256, 256 over x squared, or we could write that as 256, 256 x to the negative 2 power. That is the sum of our squares that we now want to minimize. Well, to minimize this, we would wanna look at the critical points of this, which is where the derivative is either zero or undefined, and see whether those critical points are possibly a minimum or a maximum point.