We would increment the exponent so it's y to the first but so now when we take the antiderivative, it would be y squared and then we divide by that incremented exponent is equal to, well, the exciting thing about e to the x is its antiderivative is, and its derivative is e to the x is equal to e to the x plus, is equal to e to the x plus c and so we can leave it like this if we like. In fact, this right over here, this isn't an explicit function. Y here isn't an explicit function of x. You could actually say y is equal to the plus or minus square root of two times all of this business but this would be a pretty general relationship which would satisfy this separable differential equation. Let's do another example. So let's say that we have the derivative of y with respect to x is equal to, let's say it's equal to y squared times sine of x. Pause the video and see if you can find the general solution here.