You add 10 to both sides, you get C, in this case, is equal to 0. So we've figured out what our position function is as well. This C right over here is just going to be 0. So our position, as a function of time, is equal to T squared over 2 minus 6T. And you can verify. When T is equal to 2, 2 squared over 2 is 2, minus 12 is negative 10. You take the derivative here, you get T minus 6, and you can see, and we already verified, that V of 3 is negative 3.