You get x is equal to negative 5 over negative 2, which is equal to 5 halves, which is exactly what we thought it was when we looked at it visually. It looked like we were at about 2 and 1 half, which is the same thing as 5 halves. Now, we don't know what this is. We don't know if this is an inflection point, is this a maximum, is this a minimum? So really we just want to evaluate g at this point to see if it gets higher than when we evaluate g at 3. So let's evaluate g at 5 halves. So g at 5 halves is going to be equal to 2 times 5 halves plus the integral from 0 to 5 halves of f of t dt.