So what we really just have to do is evaluate g at the different end points of this interval to see how high it gets or how large of a value we get for the g at the end points. And then we have to see if g has any critical points in between, and then evaluate it there to see if that's a candidate for the global maximum. So let's just evaluate g at the different end points. So let's start off, let's evaluate g at negative 4, at kind of the lowest end or the starting point of our interval. So g of negative 4 is equal to 2 times negative 4, plus the integral from 0 to negative 4 f of t dt. The first part is very easy, 2 times negative 4 is negative 8. Let me do it over here so I have some real estate.