So you get negative 2y over x is equal to the derivative of y with respect to x. Now, you might be saying, look, we just figured out the derivative implicitly, and it looks very different than what we did right over here. When we just used the power rule, we got negative 2x to the negative third power. x to the negative 3 power. The key here is to realize that this thing right over here, we could solve explicitly in terms of, we could solve for y. So we could just make this substitution back here to see that these are the exact same thing. So if we make the substitution y is equal to 1 over x squared, you get dy dx, the derivative of y with respect to x, is equal to our negative 2, is equal to the negative 2 times 1 over x squared, and then all of that over x, which is equal to negative 2 over x to the third, which is exactly what we have over here.