Pause this video and see if you can figure this one out from this graph. All right, we're going from x equals negative six to x equals negative two, and the definite integral is going to be the area below our graph and above the x-axis. So it's going to be this area right over here. And how do we figure that out? Well, this is a semicircle, and we know how to find the area of a circle if we know its radius, and this circle has radius two, has a radius of two. No matter what direction we go in from the center, it has a radius of two. And so the area of a circle is pi r squared, so it'd be pi times our radius, which is two squared, but this is a semicircle, so I'm gonna divide by two.