So we have a question here from the 2015 AP Calculus A-B test, and it says, consider the curve given by the equation y to the third minus xy is equal to two. It can be shown that the first derivative of y with respect to x is equal to that, so they solved that for us. And then part c of it, I skipped parts a and b for the sake of this video, evaluate the second derivative of y with respect to x at the point on the curve where x equals negative one and y is equal to one. So pause this video and see if you can do that. All right, now let's do it together. And so let me just first write down the first derivative. So dy, derivative of y with respect to x is equal to y over three y squared minus x.