So negative 12 plus three is negative nine. All right, now let's evaluate f of negative two. f of negative two is equal to the integral from one to negative two of f prime of u du plus three. Well, it's kind of, feels a little strange to have the upper bound being lower than the lower bound, so we can swap the bounds and then add a negative out here. So this is going to be equal to the negative of, if we swap the bounds here, so from negative two to one, f prime of u du plus three. So what's the integral from negative two to one? Well, they give us that.