Well, x to the third is just over, x to the third over x to the third is just going to be equal to one. So this is going to be minus one dx. So dx. And so what is this going to be equal to? Well, let's take the antiderivative of each of these parts and then we're going to have to evaluate them at the different bounds. So let's see. The antiderivative of 16x to the negative three.