And if we want, we can distribute the 1 7th. So it would get 1 7th times 2 1⁄3 is 2 over 21, 2 over 21 u to the 3 1⁄2. And 1 7th times some constant, well, that's just going to be some constant. And so I could write a constant like that. I could call that c one, and then I could call this c two, but it really is just some arbitrary constant. And we're done. Oh, actually, no, we aren't done.