So in this situation, what happens if we distribute this x squared? Well, then we're going to get a polynomial here within the integral. So this is going to be equal to the integral of x squared times three x is three x to the third and then negative one times x squared is minus x squared and then that times dx. And now this is pretty straightforward to evaluate. This is going to be equal to the antiderivative of x to the third is x to the fourth over four. So this is going to be three times x to the fourth over four I could write it that way or let me just write it, x to the fourth over four and then the antiderivative of x squared is x to the third over three. So minus x to the third over three and this is an indefinite integral.