So this is equal to the integral from negative two to three of negative y squared plus three y plus 11 minus all of this stuff. So if we just distribute a negative sign here, it's minus y squared minus y plus one and then we have a dy, dy. This is equal to the definite integral from negative two to positive three of, let's see, negative y squared minus y squared, negative two y squared and then three y minus y is going to be plus two y and then 11 plus one plus 12. We saw this just now when we were trying to solve for y, dy. And so what is that going to be equal to? Well, we just take the antiderivative here. This is going to be, let's see, negative two, let's increment the exponent, y to the third, divide by that exponent, reverse power rule, plus two y squared divided by two, which is just y squared, just the reverse power rule, and then plus 12 y and we're going to evaluate that at three and at negative two.