So for this section, this sub-region right over here, y equals square root of x is the upper function the entire time. And then we can set up a different, we can separately tackle figuring out the area of this region, from x is equal to 1 to x is equal to 2, where y equals 2 minus x is the upper function. So let's do it. So let's first think about this first region. Well, that's going to be the definite integral from x is equal to 0 to x is equal to 1, and our upper function is square root of x, so square root of x, and then from that we want to subtract our lower function, square root of x minus x squared over 4 minus 1. So minus x squared over 4 minus 1. And then, of course, we have our dx.