This expression is defined at zero, but this tells me, well, I really shouldn't apply zero to this function. But we know that if we can find another function that is defined, that is the exact same thing as f of x, except at zero, and it is continuous at zero. And so we could say g of x is equal to one over two plus two cosine theta. Well, then we know this limit is going to be the exact same thing as the limit of g of x as theta approaches zero. Once again, these two functions are identical, except f of x is not defined at theta equals zero, while g of x is. But the limits as theta approaches zero are going to be the same, and we've seen that in previous videos. And I know what a lot of you are thinking, Sal, this seems like a very, you know, why don't I just, you know, do this algebra here, cross these things out, and just substitute zero for theta?