Negative three, the function is clearly, at negative three, the function is just plain old continuous. The two-sided limit approaches the value of the function, but at negative two, the two-sided limit does not exist. When you approach from the left, looks like you're approaching zero, f of x is equal to zero. When you approach from the right, it looks like f of x is approaching negative three. So even though the two-sided limit does not exist, we can still be good because the left-handed limit does exist, and the left-handed limit is approaching the value of the function. So we actually are continuous over that interval. But then if we did the interval, if we did the closed interval from negative two to negative two to one, pause the video and think about, based on what we just talked about, are we continuous over this interval?