So we get zero is equal to one plus c, or c is equal to negative one. So now we can write down the particular solution to this differential equation that meets these conditions. So we get, let me write it over here. Sine of y plus two y is equal to x squared, and our constant is negative one, so minus one. And now what is x when y is equal to pi? So sine of pi plus two times pi is equal to x squared minus one. See sine of pi is equal to zero, and so we get, see we can add one to both sides, and we get two pi plus one is equal to x squared, or we could say that x is equal to the plus or minus square root of two pi plus one.