So let's take the absolute value of f of x minus g of x dx. So that's gonna be the sum of the areas, or we could say this is going to be the integral from zero to two of the absolute value, f of x, is one plus x plus e to the x squared minus two x minus g of x. So minus x to the fourth plus 6.5 x squared minus six x minus two. Take the absolute value, dx. Now this would be pretty hairy to solve if we did not have access to a calculator, but lucky for us on this part of the AP exam, we can use a graphing calculator. So let's do that to evaluate this definite integral here. And if you're wondering why I say minus two instead of plus two, remember we're subtracting, we're subtracting g of x, we're finding the difference between them.