And once again, if this part over here, what I just did seems strange, the u substitution, you might want to review that piece. Now, what can I do here? Well I have a constant on the left-hand side, it's an arbitrary constant, we don't know what it is. I haven't used this initial condition yet, we could call it. So let me just subtract c one from both sides. So if I just subtract c one from both sides, I have an arbitrary, so this is going to cancel, and I have c two, sorry, let me, so this is c one, so these are going to cancel, and c two minus c one, these are both constants, arbitrary constants, we don't know what they are yet, and so we could just rewrite this as, on the left-hand side we have y squared over two is equal to, on the right-hand side, I'll write one half e, let me write that in blue, just because I wrote it in blue before, one half, one half e to the negative x squared, and I'll just say c two minus c one, let's just call that c. So if you take the sum of those two things, let's just call that c. And so now, this is kind of a general solution, we don't know what this constant is, and we haven't explicitly solved for y yet, but even in this form, we can now find a particular solution using this initial condition. Let me separate it out, this wasn't part, this wasn't part of this original expression right over here, but using this initial condition.