You could say a line has a form y is equal to mx plus b where m is the slope and b is the y intercept. Well we already know what the slope of this line is. It is negative two. So we could say y is equal to negative two, negative two times x, times x plus b. And then to solve for b, we know that the point negative one comma three is on this line. And this goes back to some of your algebra one that you might have learned a few years ago. So let's substitute negative one and three for x and y.