So this is equal to 1 5th times the integral of one over, and so x squared minus six x. It's clearly not a perfect square the way it's written. Let me write this plus 13 out here. Now what could I add, and then I'm gonna have to subtract if I don't wanna change the value of the denominator, in order to make this part right over here a perfect square? Well, we've done this before. You take half of your coefficient here, which is negative three, and you square that. So you wanna add a nine here.