Well, that would represent this area right over here, and what would the integral from c to d of g of x dx represent? Well, you might say it is this area right over here, but remember, over this interval, g of x is below the x-axis, so this would give you a negative value, but if you wanted this total area, what you could do is take this blue area, which is positive, and then subtract this negative area, and so then you would get the entire positive area. Well, this just amounted to, this is equivalent to the integral from c to d of f of x, of f of x minus g of x again, minus g of x. Let me make it clear, we've got parentheses there, and then we have our dx. So once again, even over this interval, when f of x was above the x-axis and g of x was below the x-axis, it still boiled down to the same thing. Well, let's take another scenario. Let's take the scenario when they are both below the x-axis.