Negative 1 1 2 x. What's the antiderivative of two over x minus one? And you might be able to do this in your head. The derivative of x minus one is just one. So you could say that the derivative is sitting there. And so we can essentially do u substitution in our heads and say, okay, let's just take the antiderivative, I guess you could say with respect to x minus one, which would be the natural log of the absolute value of x minus one. If all of that sounds really confusing, I'll actually do the u substitution.