One over natural log of eight times e to the u. Times e to the u, e to the u. And of course, if we're thinking in terms of just antiderivative, there would be some constant out there. And then we would just reverse the substitution. We already know what u is. So this is going to be equal to the antiderivative of this expression is one over the natural log of eight times e to the, instead of u, we know that u is x to the third times the natural log of two. And of course, we could put a plus c there.