Let's make it equal to the definite integral from negative two to x of f of t dt. Now pause this video, really take a look at it. This might look really fancy, but what's happening here is given an input x, g of x is going to be based on what the definite integral here would be for that x. And so we can set up a little table here to think about some potential values. So let's say x, and let's say g of x right over here. So if x is one, what is g of x going to be equal to? All right, so g of one is going to be equal to the definite integral going from negative two.