That's where the C would be between, but it's not guaranteed by the intermediate value theorem that f of C is going to be equal to zero because zero is not between three and six. So I'm gonna rule that one out. I'm going to rule this one out, saying f of C equals zero. And let's see, we're only left with this one, so I hope it works. So f of C is equal to four. Well, that seems reasonable because four is between three and six for at least one C between negative two and one. Well, yeah, because that's in this interval right over here.