1 1⁄2 plus one is 1 1⁄2 or 3 1⁄2. So it's going to be u to the 3 1⁄2, u to the 3 1⁄2. And then we're gonna multiply this new thing times the reciprocal of 3 1⁄2, which is 2 1⁄3. And I encourage you to verify the derivative of 2 1⁄3 u to the 3 1⁄2 is indeed u to the 1 1⁄2. And so we have that, and since we're multiplying 1 7th times this entire indefinite integral, we could also throw in a plus c right over here. There might have been a constant. And if we want, we can distribute the 1 7th.