So that is this choice right over here. Now there's other ways you could have tackled this. If you just look at kind of the structure of this expression here, the numerator is a constant, so that's clearly always going to be positive. Let's ignore this negative for the time being. That negative's out front. This numerator, this one, is always going to be positive. Down here, we're taking the, at x equals one, well, this becomes zero, and the whole expression becomes undefined, but as we approach one, x minus one could be positive or negative, as we see over here, but then when we square it, this is going to become positive as well.