So it looks like this limit is three, even though the value g of negative three is negative two, but it's a point discontinuity. As we approach it from either side, the value of the function is at three. So this thing is going to be three. So it exists, so we meet that first condition. And then the second question is, is our function f continuous at this limit, continuous at three? So when x equals three, yeah, it looks like at that point, our function is definitely continuous. And so we could say that this limit is going to be the same thing as this equals f of the limit as x approaches negative three of g of x, close the parentheses.