So this right over here is y is equal to negative two, and then the upper bound is y is equal to three. So now we just have to evaluate this from negative two all the way until three. So let's do that, I'm going to clear this out so I get a little bit of real estate. So this is equal to the integral from negative two to three of negative y squared plus three y plus 11 minus all of this stuff. So if we just distribute a negative sign here, it's minus y squared minus y plus one and then we have a dy, dy. This is equal to the definite integral from negative two to positive three of, let's see, negative y squared minus y squared, negative two y squared and then three y minus y is going to be plus two y and then 11 plus one plus 12. We saw this just now when we were trying to solve for y, dy.