We're going to get x values closer and closer to 5, but not quite at 5. We can use this expression right over here. So the limit of f of x as x approaches 5 is going to be the same thing as the limit of 1 over the square root of x plus 4 plus 3 as x approaches 5. And now we can substitute a 5 in here. It's going to be 1 over 5 plus 4 is 9, the principal root of that is 3, 3 plus 3 is 6. So if c is equal to 1 6, then the limit of our function as x approaches 5 is going to be equal to f of 5, and we are continuous at x equals 5. So it's 1 6.