If we're dealing with this over, you know, in this open interval, or actually even disregarding that, this theta, or this expression is continuous at, it is defined and it is continuous at theta is equal to negative pi over four. So this is just going to be equal to one over one minus the square root of two times sine of negative pi over four. Sine of negative pi over four. Sine of negative pi over four, which we've already seen is negative square root of two over two. And so this is going to be equal to one over one minus square root of two times the negative square root of two over two. So negative negative, you get a positive. Square root of two times square root of two is two over two is gonna be one.