This is the case we're dealing with. Limit as x approaches 0 of sine of x is equal to 0. Limit as x approaches 0 of x is also equal to 0. The limit of the derivative of sine of x over the derivative of x, which is cosine of x over 1, we found this to be equal to 1. All of these top conditions are met. Then we know this must be the case, that the limit as x approaches 0 of sine of x over x must be equal to 1. It must be the same limit as this value right here, where we take the derivative of the f of x and of the g of x. I'll do more examples in the next few videos, and I think it will make it a lot more concrete.