Well, we can, we got some trig functions here, so maybe we can use some of our trig identities to simplify this. And the one that jumps out at me is that we have the sine squared of theta, and we know from the Pythagorean identity in trigonometries, comes straight out of the unit circle definition of sine and cosine, we know that sine squared theta plus cosine squared theta is equal to one, or we know that sine squared theta is one minus cosine squared theta. One minus cosine squared theta. So we could rewrite this. This is equal to one minus cosine theta over two times one minus cosine squared theta. Now, this is a one minus cosine theta, this is a one minus cosine squared theta, so it's not completely obvious yet of how you can simplify it, until you realize that this could be viewed as a difference of squares. If you view this as, if you view this as a squared minus b squared, we know that this can be factored as a plus b times a minus b.