And so we get three minus one over three minus one. Well, that's gonna be two over two, which is equal to one. So there's some point between one and three where the derivative at that point, the slope of the tangent line, is equal to one. So let's see if we can solve this thing right over here. Well, we can multiply both sides of this by the square root of four c minus three. And so then we are going to get, we're going to get two is equal to the square root of four c minus three. All I did is multiply both sides of this by square root of four c minus three to get rid of this in the denominator.