So let's try the other bounds. Let's see what g of positive 3 is. Let's see what g of positive, I'll do it over here so I have more space. So g of positive 3, when x is equal to 3, that, we go back to our definition, that is 2 times 3, plus the integral from 0 to 3, f of t dt. And this is going to be equal to 2 times 3 is 6, and the integral from 0 to 3, f of t dt, that's this entire area. So we have positive area over here, and then we have an equal negative area right over here, because it's below the x-axis. So the integral from 0 to 3 is just going to be 0.