And so this is the area of the left region, and by the exact same logic, we can figure out the area of the right region. The right region, and then we can just sum the two things together. The right region, we're going from x is equal to 0 to x, sorry, x is equal to 1, x is equal to 2, 1 to 2. The upper function is 2 minus x, and from that we're going to subtract, from that we're going to subtract the lower function, which is x squared over 4 minus 1. x squared over 4 minus 1. And now we just have to evaluate. So let's first simplify this right over here. This is equal to the definite integral from 0 to 1 of square root of x minus x squared over 4 plus 1 dx, I'm going to write it all in one color now, plus the definite integral from 1 to 2 of 2 minus x minus x squared over 4, then subtracting a negative 1 is a positive 3, or a positive 1, we could just add it to this 2, and so this 2 just becomes a 3.