So the average of our function is going to be, it's going to be equal to the definite integral over this interval. So essentially, the area under this curve. So it's going to be the definite integral from zero to three of f of x, which is x squared plus one, dx. And then we're gonna take this area. We're gonna take this area right over here, and we're gonna divide it by the width of our interval to essentially come up with the average height or the average value of our function. So we're gonna divide it by b minus a, or three minus zero, which is just going to be three. And so now we just have to evaluate this.