But needless to say, this would be 5 6ths times e to the 6 5ths t, and if you're thinking about the indefinite integral, you would then have a plus c here, of course, and you can verify that the derivative of this is indeed e to the 1.2 t. So this is going to be equal to, so this part right over here the antiderivative is 5 6th e to the 6 5ths t, and then this part right over here, the antiderivative of 2t is t squared, so minus t squared, and we are going to evaluate that at five and two and find the difference. So let's evaluate this at when t is equal to five. Well, you are going to, let me color code this a little bit. When t is equal to five, you get 5 6ths times e to the 6 5ths times five is e to the 6th minus five squared, so minus 25, and so from that, I want to subtract. When we evaluate it at two, we get 5 6ths e to the 6 5ths times two is the same thing as 12 5ths, or we could say that's 2.4, 2.4 minus four. Two squared is four, and so what do we get? Well, there's a couple of ways that we could do this.