And then I have to take the derivative of y with respect to x, so times dy dx. As we say, if this is completely unfamiliar to you, I encourage you to watch the several videos on Khan Academy on implicit differentiation, which is really just an extension of the chain rule. I took the derivative of three y squared with respect to y and took the derivative of y with respect to x. Now if I take the derivative of negative x with respect to x, that's going to be negative one. Fair enough. And so I took the derivative of this, I'm gonna multiply it times that, so times dy dx. And then to that, I'm going to add the derivative of this with respect to x.