Because this could have been our first limit problem. And if this is our first limit problem, we say hey, maybe we could use L'Hopital's rule here because we've got an indeterminate form where both the numerator and the denominator approach 0 as x approaches 0. So let's take the derivatives again. This will be equal to, if the limit exists, the limit as x approaches 0. Let's take the derivative of the numerator. The derivative of negative 2 sine of x is negative 2 cosine of x. And then plus the derivative of 4 sine of 2x, well it's 2 times 4, which is 8 times cosine of 2x.