So g of positive 3, when x is equal to 3, that, we go back to our definition, that is 2 times 3, plus the integral from 0 to 3, f of t dt. And this is going to be equal to 2 times 3 is 6, and the integral from 0 to 3, f of t dt, that's this entire area. So we have positive area over here, and then we have an equal negative area right over here, because it's below the x-axis. So the integral from 0 to 3 is just going to be 0. You're going to have this positive area, and then this negative area right over here is going to completely cancel it out, because it's symmetric right over here. So this thing is going to evaluate to 0. So g of 3 is 6.