Let's see if we can find the limit as theta approaches zero of one minus cosine theta over two sine squared theta. And like always, pause the video and see if you can work through this. All right, well, our first temptation is to say, well, this is going to be the same thing as the limit of one minus cosine theta as x approaches, or not x, as theta approaches zero, of theta as theta approaches zero over the limit as theta approaches zero of two sine squared theta. Now, both of these expressions, which could be used to define a function, they'd be continuous if you graphed them. They'd be continuous at theta equals zero, so the limit is going to be the same thing as just evaluating them at theta equals zero. So this is going to be equal to one minus cosine of zero over two sine squared of zero. Now, cosine of zero is one, and then one minus one is zero, and sine of zero is zero, and you square it, you still got zero, and you multiply it times two, you still got zero, so you got zero over zero.