Now many of y'all might already be saying, hey, this looks a lot like arctangent, but I'm gonna try to simplify it even more so it becomes very clear that it looks like arctangent is going to be involved. I'm actually gonna do some u substitution in order to do it. So the first thing I'm gonna do is, let's factor a four out of the denominator here. So if we do that, then this is going to become 1 5th times 1 4th, which is going to be 1 20th times the integral of one over x minus three squared over two squared. And then this is going to be a plus one. And of course, we have our dx. And then we could write this as, and I'm trying to just do every step here.