We know what y is. We know what dy dt is. All we need to figure out is what s and then what ds dt is, the rate at which this distance is changing with respect to time. Well, what's s right now? Well, we can actually use the Pythagorean theorem at this exact moment. We know that x squared, so x is 0.6, we know 0.6 squared plus y squared, 0.8 squared, is equal to s squared. Well, this is 0.36 plus 0.64 is equal to s squared.