If this is delta x is equal to b minus a over n, let me write this down. So this is going to be equal to b, b minus our a, which is two. All of that over n. So b minus two is equal to five, which would make b equal to seven. B is equal to seven. So there you have it. We have our original limit, our Riemann limit, or limit of our Riemann sum being rewritten as a definite integral. And once again, I want to emphasize why this makes sense.