And so here I'll apply the product rule. First I'll take the derivative of this expression and then multiply that times dy dx and then I'll take the derivative of this expression and multiply it times this. So the derivative of three y squared minus x with respect to x, well that is going to be, so if I take the derivative of three y squared with respect to y, it's going to be six y. And then I have to take the derivative of y with respect to x, so times dy dx. As we say, if this is completely unfamiliar to you, I encourage you to watch the several videos on Khan Academy on implicit differentiation, which is really just an extension of the chain rule. I took the derivative of three y squared with respect to y and took the derivative of y with respect to x. Now if I take the derivative of negative x with respect to x, that's going to be negative one.