So you can have a completely identical expression if you say that this is the same thing. You can divide the numerator and the denominator by x minus 5 if you assume x does not equal 5. So this is going to be the same thing as 1 over square root of x plus 4 plus 3 for x does not equal 5. Which is fine because in the first part of this function definition, this is for the case for x does not equal 5. So we could actually replace this, and this is a simpler expression, with 1 over square root of x plus 4 plus 3. And so now when we take the limit as x approaches 5, we're going to get closer and closer to 5. We're going to get x values closer and closer to 5, but not quite at 5.