So we could just say that's going to be equal to K times T plus some constant. I'll just call that C1. And once again, I could have put a plus C2 here, but I could have then subtracted the constant from both sides, and I would just get the constant on the right-hand side. Now, how can I solve for P? Well, the natural log of the absolute value of P is equal to this thing right over here. That means, that's the same thing, that means that the absolute value of P is equal to E to all of this business. E to the, let me do the same colors, KT plus C1.