We know what the value of the function is at negative two. It's three, so let me write that. F of negative two is equal to three and f of one, they tell us right over here, is equal to six. And all the intermediate value theorem tells us, and if this is completely unfamiliar to you, I encourage you to watch the video on the intermediate value theorem, is that if we have a continuous function on some closed interval, then the function must take on every value between the values at the end points of the interval. Or another way to say it is, for any L between three and six, there is at least one C, there is at least one C, one C between, or I could say one C in the interval from negative two to one, the closed interval, such that f of C is equal to L. This comes straight out of the intermediate value theorem. And just saying it in everyday language is, look, this is a continuous function. Actually, I'll draw it visually in a few seconds, but it makes sense that if it's continuous, if I were to draw the graph, I can't pick up my pencil, well, then it makes sense that I would have to take on every value between three and six, or there's at least one point in this interval where I take on any given value between three and six.