And then our inner radius is going to be equal to what? Well, that's going to be the difference, the horizontal distance between this vertical line and our inner function, our inner boundary. So it's going to be the horizontal distance between 2 and whatever x value this is. But this x value as a function of y is just the square root of y. So it's going to be 2 minus the square root of y. And so now we can come up with an expression for area. It's going to be, and I'll just factor out, I'll leave the pi there.