So we could say y is equal to negative two, negative two times x, times x plus b. And then to solve for b, we know that the point negative one comma three is on this line. And this goes back to some of your algebra one that you might have learned a few years ago. So let's substitute negative one and three for x and y. So when y is equal to three, so three, three is equal to, is equal to negative two, negative two times x times negative one, times negative one plus b, plus b. And so let's see, this is negative two times negative one is positive two. And so if you subtract two from both sides, you get one is equal to b.