So an antiderivative of this is going to be, if we don't take the, well, an antiderivative is going to be negative four t to the negative three power, and we saw that over here. Obviously, if you were really just taking an indefinite integral, we would have to put some constant here, but in the definite integral, even if we put a constant here, it would get, assuming the same constant, it would get canceled out when you actually do the calculation. But the antiderivative of this, we increment the exponent, and then we divide by that new exponent. So 12 divided by negative three is negative four, and we're going to evaluate that from at two and at one. And so this is going to be equal to, when we evaluate it at two, at the upper bound of our interval, it's gonna be negative four times two to the negative three power. So it's negative four times, what is that, two, that's one over two to the third, times 1 1 8th is one way to think about that. And then we're gonna have minus this evaluated at one.