The antiderivative of 4 times the square root of y plus 1, you just really have to think of it as 4 times y plus 1 to the 1 half power. We could use u substitution explicitly, but you probably are pretty practiced and this can do this in your head. y plus 1 raised to the 1 half power. Derivative of y plus 1 is just 1, which is essentially out here. So you can really just, if you did u substitution, you'd say u is equal to y plus 1. But this antiderivative is going to be equal to, well, if you increment this exponent, you get 3 halves multiplied by the reciprocal 2 thirds. 2 thirds times 4 is 8 thirds.