Well, it looks like the left boundary is where the two graphs intersect right over here, and the right boundary is where they intersect right over there. Well, what is this point of intersection? It looks like it is negative one comma negative two. We can verify that. In this red curve, if x is negative one, let's see, you square that, you'll get one minus three. You do indeed get y is equal to negative two. And in this blue function, when x is equal to negative one, you get one minus four plus one.