The absolute minimum point, well, it seems like we hit it right over here when x is, let's say this is x is c. And this is f of c right over there. And it looks like we hit our absolute maximum point over the interval right over there when x is, let's say that this is x is equal to d. And this right over here is f of d. This right over here is f of d. So another way to say the statement right over here, if f is continuous over the interval, we could say there exists a c and d that are in the interval. So there are members of this set that are in the interval such that, and I'm just using the logical notation here, such that f of c is less than or equal to f of x, which is less than or equal to f of d for all x in the interval. Just like that. So in this case, they're saying, look, our minimum value when x is equal to c, that's that right over here, our maximum value when f is equal to d. And for all the other x's in the interval, we are between those two values. Now, one thing, and we could draw other continuous functions. And once again, I'm not doing a proof of the extreme value theorem, but just to make you familiar with it and why it's stated the way it is.