We're gonna evaluate that at five and two. And so this is going to be five to the fourth over four minus two to the fourth over four. And then we could simplify this if we like. But we've just evaluated this definite integral. Now another way to do it is to think about the, is to try to solve the indefinite integral in terms of x and use u substitution as an intermediate. So one way to think about this is to say, well let's just try to evaluate what the indefinite integral of two x times x squared plus one to the third power dx is. And then whatever this expression ends up being algebraically I'm going to evaluate it at x equals two and at x equals one.