So the integral from 0 to 3 is just going to be 0. You're going to have this positive area, and then this negative area right over here is going to completely cancel it out, because it's symmetric right over here. So this thing is going to evaluate to 0. So g of 3 is 6. So we already know that our starting point, g of negative 4, that when x is equal to negative 4, that is not where g hits a global maximum, because that's a negative number, but it's the end point where g hits a positive value. So negative 4 is definitely not a candidate. 3, x is equal to 3, is still in the running for the x-coordinate where g has a global absolute maximum.