So this is correct. And then step three, he says g doesn't have any inflection points. Now this is a little bit suspect. It is, in many cases, our inflection point is a situation where our second derivative is equal to zero. And even then, we don't know it's an inflection point. It would be a candidate inflection point. We would have to confirm that our second derivative crosses signs, or switches signs, as we cross that x value.