So we want to evaluate the definite integral from negative one to negative two of 16 minus x to the third over x to the third dx. Now at first this might seem daunting. I have this rational expression. I have x's in the numerators and x's in the denominators, but we just have to remember, we just have to do some algebraic manipulation and this is going to seem a lot more tractable. This is the same thing as the definite integral from negative one to negative two of 16 over x to the third minus x to the third over x to the third. Minus x to the third over x to the third dx. And now what is that going to be equal to?