And then the derivative of a constant here is just going to be zero. So this is our derivative of f, and if we want to evaluate it at one, f prime of one is going to be three times one squared, which is just three, minus 12 times one, so it's just minus 12, and then we have plus one. So this is three minus 12 is negative nine, and negative nine plus one is equal to negative eight. So we know the slope right over here is a slope of negative eight. We know a point on that line, it contains the point one comma negative nine, so we could use that information to find the equation of the line. The line, just to remind ourselves, has the form y is equal to mx plus b, where m is the slope, so we know that y is going to be equal to negative 8x plus b and now we can substitute the x and y value that we know sits on that line to solve for b. So we know that y is equal to negative nine, let me just write this here, y is equal to negative nine when x is equal to one.