So on our calculator, we would hit Math, and then we would wanna do number nine, which is definite integral, so we'll hit nine, and we are going to go from zero to six of, this is going to be two sine of e to the, so let me do second e to the, and I'll just use the variable x instead of t because it's easier to type in, x divided by four power. So that's my sine, and then let me close the parentheses for the sine, plus one, and then I'm integrating here with respect to x just because it was more convenient, and I am going to get that, and then I divide by six, divide by six, and I get, and when you're taking an AP calculus exam, it's important to round to three decimal places unless they tell you otherwise. That's what they expect. So it's approximately equal to 1.949, approximately 1.949. Now let's do part c. So part c, find the total distance traveled by the particle from time t equals zero to t equals six. So you might say, hey, didn't we just figure that out? No, this is displacement, and to remember the difference between distance and displacement, if I have something that starts here, it goes over there, and then it comes back to right over there, the distance traveled is the total path length, so it would be that plus this, while the displacement would just be this right over here.