So it's going to be, that right over there is going to be negative x squared plus six x minus one. And then minus four, minus the lower function. So that could be simplified as negative x squared plus six x minus five. And so if we wanna figure out the volume of this little section right over here, we'd multiply x times this. And then we would multiply that times an infinitesimally small depth, a dx. And then we can just integrate from x equals one to x equals five. So let's do that.