We don't know exactly what this is, but luckily we also need to take the sum of everything I just showed, but plus this right over here. And this we're going from four to six, so it's going to be this area. Well, once again, when you look at it this way, you can see that this expression is going to be equivalent to taking the definite integral all the way from zero to six, zero to six of f of x, dx. And once again, even if you didn't see the graph, you would know that because in both cases you're getting the definite integral of f of x, dx, and our upper bound here is our lower bound here. So once again, we're able to merge the integrals. And what is this going to be equal to? Well, we have this area here, which is five, and then we have this area, which is six.