So dy, derivative of y with respect to x is equal to y over three y squared minus x. Well, if we're concerning ourselves with the second derivative, well, then we wanna take the derivative with respect to x of both sides of this. So let's just do that, do the derivative operator on both sides right over here. Now on the left-hand side, we of course are going to get the second derivative of y with respect to x. But what do we get on the right-hand side? And there's multiple ways to approach this, but for something like this, the quotient rule probably is the best way to tackle it. I sometimes complain about the quotient rule, saying, hey, it's just a variation of the product rule, but it's actually quite useful in something like this.