And then we can find the particular one by substituting in, when x is equal to one, y is equal to zero. So let's do that to solve for c. So we get, or when y is equal to zero, x is equal to one. So sine of zero plus two times zero, all I did is I substituted in the zero for y, is equal to x squared, well now x is one, is equal to one squared plus c. Well sine of zero zero, two times zero zero, all of that's just going to be zero. So we get zero is equal to one plus c, or c is equal to negative one. So now we can write down the particular solution to this differential equation that meets these conditions. So we get, let me write it over here. Sine of y plus two y is equal to x squared, and our constant is negative one, so minus one.