The big takeaway is you just have to do a little bit of distribution to get a form where it's easy to evaluate the antiderivative. Let's do another example. Let's say that we want to take the indefinite integral of, it's going to be a hairy expression, so x to the third plus three x squared minus five, all of that over x squared dx. What would this be? Pause the video again and see if you can figure it out. So once again, your brain might want to try to do some fancy tricks or whatever else but the main insight here is to realize that you could just simplify it algebraically. What happens if you just divide each of these terms by x squared?