And so since the derivative at two is not zero, this is not going to be a minimum, a relative minimum, or a relative maximum. So we could say since f prime of two, f prime of two does not equal zero, this, we have a, f has, right this way, f has neither, neither minimum, or relative minimum I guess I could say, relative min, or relative max at x equals two. Alright, let's do the next one. Find the values of the constants m and b for which y equals mx plus b is a solution to the differential equation. Alright, this one is interesting. So let's actually, let's just write down everything we know before we even think that y equals mx plus b could be a solution to the differential equation. So we know that, we know that dy over dx is equal to two x minus y.