So we can rewrite this integral, and I'll try to stay consistent with the colors, as the indefinite integral. What we have in magenta right over here, that's du over x to the fourth plus 7, which is just u. Or we could rewrite this entire thing as the integral of 1 over u du. What is the indefinite integral of 1 over u du? That's just going to be equal to the natural log of the absolute value, and we use the absolute value so it'll be defined even for negative u's. It actually does work out, and I'll do another video where I show you that it definitely does. The natural log of the absolute value of u, and then we might have had a constant there that was lost when we took the derivative.