Now at first when you see this, you're like, wow, this is strange. I have a function that is being defined by an integral, a definite integral, but one of its bounds are x. And you should just say, well, this is okay. A function can be defined any which way. And as we'll see, it's actually quite straightforward to evaluate this. So g of negative two, g of negative two, and I'll do the negative two in a different color, g of negative two, well, what we do is we take this expression right over here, this definite integral, and everywhere we see an x, we replace it with a negative two. So this is going to be equal to the integral from zero to x of, and I'll write x in a second, f of t dt.