We get this from the previous parts of the problem and we get this just taking the first and second derivatives of y equals mx plus b. So given this, can we figure out, can we figure out what m and b are? Alright, so we could, if we said m is equal to two x minus y, that doesn't seem right. This one is a tricky one. Let's see, we know that the second derivative is going to be equal to zero. We know that this is going to be equal to zero for this particular solution. And we know dy dx is equal to m. We know this is m. And so there you have it, we have enough information to solve for m. We know that zero is equal to two minus m. So zero is equal to two minus m. And so we can add m to both sides and we get m is equal to two.