Remember, the second derivative was equal to 12x times 3x minus 2. I like writing it this way because you've kind of decomposed it into two linear expressions, and you can see whether each of them are positive or negative. So if x is greater than 0, this thing right here is definitely going to be positive. And then this thing right here, right when you go right above x is greater than 0. So you have to make sure to be very close to this number. So if this number is like point 1, so you're right above 0. So this isn't going to be true for all of x greater than 0.