Let me move it over right over here. So we went from there to there. I didn't gain a lot of real estate, but hopefully this helps a little bit. And actually, I don't even like that. Let me leave it where it was before. So then if we subtract the square root of y from both sides, we get, and I'll try to simplify as I go, we get this thing, which I can rewrite as x times, well, it's just going to be x in the numerator, divided by 2 times the square root of y. y to the negative 1 half is just the square root of y in the denominator. And 1 half, I just put the 2 in the denominator there, times dy dx times the derivative of y with respect to x is going to be equal to the negative square root of y. I just subtracted the square root of y from both sides.