Well that's x minus 5 over x minus 5 times the square root of x plus 4 plus 3. And now it pops out at you. Both the numerator and the denominator are now divisible by x minus 5. So you can have a completely identical expression if you say that this is the same thing. You can divide the numerator and the denominator by x minus 5 if you assume x does not equal 5. So this is going to be the same thing as 1 over square root of x plus 4 plus 3 for x does not equal 5. Which is fine because in the first part of this function definition, this is for the case for x does not equal 5.