We're scaling up the vertical dimension by c. When you multiply c times f of x, f of x is giving us the vertical height. Now, obviously, that changes as our x changes, but when you think back to the Riemann sums, the f of x is what gave us the height of our rectangles. We're now scaling up the height, or scaling, I should say, because we might be scaling down, depending on the c. We're scaling it, we're scaling one dimension by c. If you scale one dimension by c, you're going to scale the area by c. So this right over here, the integral, let me just rewrite it, the integral from a to b of c f of x dx, that's just going to be the scaled, we're just going to take the area of f of x, so let me do that in that same color. We're going to take the area under the curve f of x from a to b f of x dx, and we're just going to scale it up, we're going to scale it up by this c. We're just going to scale it up by this c. So you might say, okay, maybe I could have felt that that was, you know, if it was a c inside the integral, now I can take the c out of the integral. Once again, this is not a rigorous proof based on the definition of the definite integral, but it hopefully gives you a little bit of intuition why you can do this. If you scale up the function, you're essentially scaling up the vertical dimension, so the area under this is going to just be a scaled up version of the area under the original function f of x. And once again, really, really, really useful property, really, really useful property of definite integrals that's going to help us solve a bunch of definite integrals and kind of clarify what we're even doing with them.