We're gonna hollow it out by subtracting out this volume. So the volume of that region is going to be the integral, I'll do this in a new color, integral from zero to 1 1⁄2 of pi times one minus f of x squared dx minus the integral from zero to 1 1⁄2 of pi times one minus g of x squared dx. And this is a completely valid answer, but you might want to simplify it. We have the same bounds of integration. We have the same variable of integration. And actually we have this pi over here, so we could factor that out. And so this is the same thing as pi times the integral from zero to 1 1⁄2 of one minus f of x, one minus f of x squared minus one minus g of x, one minus g of x squared, and then all of that dx.