Well, let's just express in math what we've already said. We already said that this function average should be some height, so let's say the function average, so that's a height, and if I multiply it times the width of this interval, so this width right over here, this width right over here is just going to be the larger value minus the smaller value, so that's going to be b minus a, so the average value of the function times the width of the interval should give us an area that is equivalent to the area under the curve, so it should be equal to the definite integral from a to b of f of x dx, and so if we just, if we knew all of this other stuff, we could solve for the function's average. The function's average, if we divide both sides by b minus a, the function's average is going to be equal to, just dividing both sides by b minus a, you're going to get one over b minus a times the definite integral, the definite integral from a to b of f of x dx, or another way to think about it, you're going to figure out what the area under the curve is over that interval. You're going to divide that by the width, and then you're going to have the function's average. One way to think about it, you're going to have the average height, and once again, I'd like to remind you that because you shouldn't just sit there and try to memorize this thing. Just get a conceptual understanding of what this is really just trying to say. Area under the curve divided by the width, well, that's just going to give you the average height.