So it's going to be minus six, I'll just write plus negative six e to the negative 3x. Notice I just took this two times the first derivative. Two times the first derivative is going to be equal to, or needs to be equal to, if this indeed does satisfy, if y one does indeed satisfy the differential equation, this needs to be equal to three times y. Well three times y is three times e to the negative 3x. Three e to the negative 3x. And let's see if that indeed is true. So these two terms right over here, nine e to the negative 3x, essentially minus six e to the negative 3x, that's going to be three e to the negative 3x, which is indeed equal to three e to the negative 3x.