So I subtracted y from both sides. Now, let's see, if I divide both sides by x, I'm gonna get the derivative of y with respect to x is equal to, actually, I'm gonna write it this way, I'm gonna write it three minus y times one over x. And so it's clear, I'm able to write the derivative as the product of a function of y and a function of x. So this indeed is separable. And I could show you, I can multiply both sides by dx, and I can divide both sides by three minus y now, and I would get one over three minus y dy is equal to one over x dx. So clearly, this one right over here is separable. Now let's do the second one.