But this is the other way around. The function is below the horizontal axis here. So this area, which they told us in the problem, the area bounded by the x-axis in the graph of f prime over the interval one, four is 12. So this area over here is 12, but the integral is going to be a negative because once again, our function is below the x-axis. So this integral, this right over here is going to be a negative 12. This is negative 12. So negative 12 plus three is negative nine.