So minus x to the third over three and this is an indefinite integral. There might be a constant there. So let me write that down and we're done. The big takeaway is you just have to do a little bit of distribution to get a form where it's easy to evaluate the antiderivative. Let's do another example. Let's say that we want to take the indefinite integral of, it's going to be a hairy expression, so x to the third plus three x squared minus five, all of that over x squared dx. What would this be?