The graph of f consists of two quarter circles and one line segment. So this right here is one quarter circle, then we have another quarter circle, and then it has this line segment over here. As shown in the figure above, I put the figure on the side so that we have some screen real estate down here. Let g of x be equal to two x plus the definite integral from zero to x of f of t dt. All right, that's a little bit interesting. Now let's do part a. Part a, find g of negative three.