And now what I want to do is essentially take the derivative of both sides again. Now there's a bunch of ways that we could try to tackle it, but the way it's written right now, if I take the derivative of the right-hand side, I'm gonna have to apply the quotient rule, which really just comes from the product rule, but it gets pretty hairy. So let's see if I can simplify my task a little bit. I'm going to have to do implicit differentiation one way or the other. So what if I multiplied both sides of this times three y squared minus x? Then I get three y squared minus x times dy dx is equal to y. And so now taking the derivative of both sides of this is going to be a little bit more straightforward.