So this gets us, let me scroll to the right a little bit, this gives us negative 8 degrees Celsius over 3 minutes. Or the rate at 3 and a half minutes is going to be approximately negative 8 thirds degrees Celsius per minute. So that is part A. And then part B. Using correct units, explain the meaning of 1 over 10 times the definite integral from 0 to 10 of h of t dt in the context of this problem. Use a trapezoidal sum with the 4 subintervals indicated by the table to estimate this thing. So the integral from 0 to 10 of h of t is really the area of this entire, under this curve right over here.