And we keep going at the point zero comma two. Well, let's see, when x is zero and y is two, the derivative of y with respect to x is going to be equal to y, which is two, minus two times zero. Well, that's just going to be two. And then last but not least, for this third point, the derivative of y with respect to x is going to be equal to y, which is three, minus two times x. X here is two. Two times two, three minus four is equal to four. Three minus four is equal to negative one. And that's all that problem asks us to do.