So how would we evaluate this? Well one simplification you can do, and I haven't rigorously proven it to you just yet, but we know that scalars can go in and out of the derivative operator when you're multiplying by a scalar. So this is indeed equal to 5 times the antiderivative of x to the negative 2 power dx. And now we can just use, I guess we could call it this anti-power rule. So this is going to be equal to 5 times x to the negative 2 power plus 1 over the negative 2 power plus 1 plus some constant right over here. And then we can rewrite this as 5 times negative 2 power plus 1 is x to the negative 1 over negative 2 plus 1 is negative 1 plus some constant. And this is equal to 5 times negative x to the negative 1 plus some constant.