So we know that v of t is equal to negative t to the third power plus six t squared plus two t, and so from that we can figure out the acceleration as a function of time, which is just going to be the derivative with respect to t of the velocity. So I'll just use the power rule a bunch. So that's going to be, this is a third power right there, so negative three t squared plus two times six is 12 t to the first plus two, so that's our acceleration as a function of time. And we want to figure out when we obtain our maximum acceleration. And just inspecting this acceleration function here, we see it's a quadratic, it has a second degree polynomial, so we have a negative coefficient out in front of the highest degree term, in front of the second degree term, so it is going to be a downward opening parabola. So it is going to be a downward opening, let me draw it in the same color. So it is going to have that general shape, and so it will indeed take on, it will indeed take on a maximum value.