Actually, I'll draw it visually in a few seconds, but it makes sense that if it's continuous, if I were to draw the graph, I can't pick up my pencil, well, then it makes sense that I would have to take on every value between three and six, or there's at least one point in this interval where I take on any given value between three and six. So let's see which of these answers are consistent with that. We only pick one. So f of C equals four, so that would be a case where L is equal to four. So there's at least one C in this interval such that f of C is equal to four. We could say that, but that's not exactly what they're saying here. F of C could be four for at least one C, not in this interval.