So let's look at its derivative. So g prime of x, we just take the derivative of this business up here, the derivative of 2x is 2, derivative of this definite integral from 0 to x of f of t dt, we did that in Part A, this is just the fundamental theorem of calculus, this is just going to be plus f of x right over there. So it actually turns out that g is differentiable over the entire interval. You give any x value over this interval, we have a value for f of x. f of x isn't differentiable everywhere, but definitely f of x is defined everywhere over the interval. So you'll get a number here, and obviously 2 is just 2, and you add 2 to it and you get the derivative of g at that point of the interval. So g is actually differentiable throughout the interval. So the only critical points would be where this derivative is equal to 0.