So it exists, so we meet that first condition. And then the second question is, is our function f continuous at this limit, continuous at three? So when x equals three, yeah, it looks like at that point, our function is definitely continuous. And so we could say that this limit is going to be the same thing as this equals f of the limit as x approaches negative three of g of x, close the parentheses. And we know that this is equal to three. And we know that f of three is going to be equal to negative one. So this met the conditions for this theorem, and we were able to use the theorem to actually solve this limit.