Square root of two times square root of two is two over two is gonna be one. So this is going to be equal to 1 1 2. And so, I wanna be very clear. This expression is not the same thing as this expression. Where the same thing at all values of theta, especially if we're dealing in this open interval, except at theta equals negative pi over four, this one is not defined, and this one is defined. But as we've seen multiple times before, if we find a function that is equal to our original, or an expression that's equal to our original expression, at all values of theta, except where the original one was not defined at a certain point, but this new one is defined and is continuous there, well then these two limits are going to be equal. So if this limit is 1 1 2, then this limit is going to be 1 1 2.