And I think you might see where this is going. Now what if you were to add up all of these from x equals zero to x equals two? Well, then you would have the volume of the entire thing. This is the power of the definite integral. So we could just integrate from x equals zero to x equals two from x equals zero to x equals two. If you drew where these intersect our base, you would say, all right, this thing right over here would be this thing right over here, where it's dx. Instead of just multiplying dx times the difference between these functions, we're going to square the difference of these functions because we're visualizing this three-dimensional shape, the surface area of this three-dimensional shape as opposed to just the height of this little rectangle.