And then our denominator, square root of x plus five minus two isn't continuous everywhere, but it is continuous at x equals negative one, and so we can do the same thing. We can just substitute negative one for x. So this is going to be the square root of negative one plus five minus two. Now what does this evaluate to? Well, in the numerator we get a zero, and in the denominator, negative one plus five is four, take the principal root is two minus two, we get zero again. So we get, we got zero over zero. Now when you see that, you might be tempted to give up.