This one also isn't defined at positive 2 because you're dividing by 0. So you could say for x does not equal to positive or negative 2 if you want to make it very explicit. But they ask us, what can we assign f of negative 2 to make the function continuous at the point? Well, the function is completely equivalent to this expression except that the function is not defined at x equals negative 2. So that's why we had to put that constraint here if we wanted this to be the same thing as our original function. But if we wanted to re-engineer the function so it is continuous at that point, well, then we just have to set f of x equal to whatever this expression would have been when x is equal to negative 2. So let's think about that.