It's also not defined on every point of the interval, but let's say not continuous over the closed interval from negative one to one. And we could even put parentheses not defined, not defined at x is equal to zero. All right, now let's start asking the second question. Can we use the intermediate value theorem to say that the equation g of x is equal to 3 4ths has a solution where one is less than or equal to x is less than or equal to two? If so, write a justification. All right, so first let's look at the interval. If we're thinking about the interval from one to two, well, yeah, our function is going to be continuous over that interval.