Over here, it's going to be a negative 1. So right over here, our slope is a negative 1. And then as we get closer and closer to 0, it's just going to get more and more and more negative. So the derivative of the natural log of the absolute value of x for x is less than 0 looks something like this. And you see, and once again, it's not a ultra rigorous proof, but what you see is that the derivative of the natural log of the absolute value of x is equal to 1 over x for all x's not equaling 0. So what you're seeing, or hopefully you can visualize, that the derivative, let me write it this way, the derivative of the natural log of the absolute value of x is indeed equal to 1 over x for all x does not equal 0. So this is a much more satisfying antiderivative for 1 over x.