As we do that, the right-hand side of the inequality is going to be expressed in terms of delta. Then we can essentially say, well, look, if the right-hand side looks like delta, or is in terms of delta, and the left-hand side looks just like that, that really defines how we can express delta in terms of epsilon. If that doesn't make sense, bear with me. I'm about to do it. If we want x minus 5 to look a lot more like this, when x is not equal to 5, and all of this whole interval, x is not equal to 5, f of x is equal to 2x. Our limit, our proposed limit, is equal to 10. If we could somehow get this to be 2x minus 10, then we're in good shape.