They wanna know what's the position of the particle at that time. Well, we know how to find our change in position. Our change in position is going to be our displacement from time equals zero to time 5.196, and the displacement, we're integrating the velocity function, so that's going to be two sine of e to the t over four plus one dt. Now, this is going to be our change in position, but where did we start? Well, they say at x equals zero, or when x, at time zero, our position was two. So if this is our change, we would start here. This would give us our total position, where we started, plus our change, and so this is going to be approximately equal to, we are going to have two plus, and then I go to Math, definite integral from zero to 5.196, and I've typed this in many times already, two sine of e to the x divided by four power, and then close that parentheses, plus one, and then I'm integrating with respect to x, and so this gives us 14.135, approximately 14.135 is its position, and let me make sure that I put those parentheses there in the right place, and we are done.