We are now integrating with respect to u. And the way we did it is we used our substitution right over here. When x equals one, u is equal to two. When x is equal to two, two squared plus one, u is equal to five. And then we can just evaluate this right over here. Let's see, this is going to be equal to the antiderivative of u to the third power is u to the fourth over four. We're gonna evaluate that at five and two.