Time is measured in seconds, and actually I'm gonna do two scenarios here. So let's say that I have a first velocity time graph. Let's just call it v one of t, which is equal to three, and it would be three meters per second. So one, two, three. So it would look like that. That is v one of t. And if I were to look at the definite integral going from time equals one to time equals five of v sub one of t dt, what would this be equal to? Well, here my function is above my t axis, so I'll just go from one to five, which will be around there, and I could just think about the area here, and this area is pretty easy to calculate.