I just like to have a clean first coefficient. So if we multiply both sides by negative one, we get 3x squared minus 12x plus five is equal to zero. And now we can use the quadratic formula to solve for x. So x is going to be equal to negative b, which is 12 plus or minus the square root. I always need to make my radical signs wide enough. The square root of b squared, which is 144, minus four times a, which is three, times c, which is five, times five. All of that, all of that over 2a.