Y is equal to f of x. So when x is equal to two, when x is equal to two, y is equal to three. So two times two minus three, and so this is going to be equal to four minus three is equal to one. And so since the derivative at two is not zero, this is not going to be a minimum, a relative minimum, or a relative maximum. So we could say since f prime of two, f prime of two does not equal zero, this, we have a, f has, right this way, f has neither, neither minimum, or relative minimum I guess I could say, relative min, or relative max at x equals two. Alright, let's do the next one. Find the values of the constants m and b for which y equals mx plus b is a solution to the differential equation.