And so this is going to be equal to two minus two x plus y. Plus y. And then they say, determine the concavity of all solutions for the given differential equation in quadrant two. Remember, if you're thinking about our coordinate axes, if you think about our coordinate axes, so if that's our y-axis, that is our x-axis, this is quadrant one, this is quadrant two, this is quadrant three, and this is quadrant four. So they're talking about quadrant two. So what do we know about x and y in quadrant two? We know x is less than zero, and we know y is greater than zero.