Alright, let's see if we can find the limit of one over square root of two sine of theta over cosine of two theta as theta approaches negative pi over four. And like always, try to give it a shot before we go through it together. Well, one take on it is, well, let's just say that this is going to be the same thing as the limit as theta approaches negative pi over four of one plus square root of two sine theta theta over the limit as theta approaches negative pi over four, make sure we can see that negative there, of cosine of two theta. And both of these expressions are, if these were function definitions, or if we were to graph y equals one plus square root of two times sine theta, or y equals cosine of two theta, we would get continuous functions, especially at theta is equal to negative pi over four, so we could just substitute in. We say, well, this is going to be equal to, this expression evaluated at negative pi over four, so one plus square root of two times sine of negative pi over four over cosine of two times negative pi over four. Now, negative pi over four, sine of negative pi over four is going to be negative square root of two over two. So this is negative square root of two over two.