The derivative of x minus one is just one. So you could say that the derivative is sitting there. And so we can essentially do u substitution in our heads and say, okay, let's just take the antiderivative, I guess you could say with respect to x minus one, which would be the natural log of the absolute value of x minus one. If all of that sounds really confusing, I'll actually do the u substitution. So if I were just trying to evaluate, if I were just trying to evaluate the integral two over x minus one dx, I could see, okay, the derivative of x minus one is just one. So I could say u is equal to x minus one. And then du is going to be equal to dx.