Three meters per second times four seconds would be 12 meters. But what if it were the other way around? What if I had another velocity function? Let's call that v sub two of t that is equal to negative two meters per second. And it's just a constant negative two meters per second. So this is v sub two of t right over here. What would or what should the definite integral from one to five of v sub two of t be dt be equal to?