And so we can rewrite all of that as this is going to be equal to the square root of 3 over 18x plus, let's see, I could write this as positive x over 8. So I could write this as 1 8th x, because negative 1 times negative x is positive x over 8. And then minus 100 over 8, which is negative 12.5. Minus 12.5. And we want to figure out an x that minimizes this area. So this derivative right over here is defined for any x. So we're not going to get our critical point by figuring out where the derivative is undefined.