And you might have been saying, OK, well, I know what to do in this case. When we first learned about derivatives, we know that the derivative, let me do this in yellow, the derivative with respect to x of the natural log of x is equal to 1 over x. So why can't we just say that the antiderivative of this right over here is equal to the natural log of x plus c? And this isn't necessarily wrong. The problem here is that it's not broad enough. And when I say it's not broad enough, is that the domain over here for our original function, that we're taking the antiderivative of, is all real numbers except for x equals 0. So over here, x cannot be equal to 0.