So the first thing I'm going to do is I'm going to take the pi, I should do that in a different color since I've already used, let me take the pi and just stick it out front. So I'm going to stick the pi out in front of the integral and so this becomes the integral of, and let me write the one over natural log of x first, one over the natural log of x times one over x dx. Now it becomes a little bit clearer. These are completely equivalent statements. But this makes it clear that yes, u substitution will work over here. If we set our u equal to natural log of x, then our du is one over x dx, one over x dx. Our du is one over x dx.