So g of 3 is 6. So we already know that our starting point, g of negative 4, that when x is equal to negative 4, that is not where g hits a global maximum, because that's a negative number, but it's the end point where g hits a positive value. So negative 4 is definitely not a candidate. 3, x is equal to 3, is still in the running for the x-coordinate where g has a global absolute maximum. Now what we have to do is figure out any critical points that g has in between. So points that it's either undifferentiable or its derivative is equal to 0. So let's look at its derivative.