And now what is that going to be equal to? That is going to be equal to the definite integral from negative one to negative two of, I could write this first term right over here. Let me do this in a different color. I could write this as 16x to the negative three. x to the negative three. And this second one, we have minus x to the third over x to the third. Well, x to the third is just over, x to the third over x to the third is just going to be equal to one.