And by the same logic, the same exact logic, we can figure out the volume if we take g of x, if we rotate g of x around, if we rotate g of x, if we construct disks like this and rotate them around y is equal to one. And so the volume, if I take g of x around y equals one, would be zero to 1 1⁄2 times pi times one minus g of x, because one minus g of x is each of these radiuses right over here, each of these radiuses. That squared dx. And so the volume of what they're asking us, the volume of the solid generated when r is rotated, well, r is kind of the space in between f of x and g of x. So it's going to be, the volume is going to be the difference between these volumes. It's going to be this volume, this is kind of the outer volume, and we're gonna take out its hollow core. We're gonna hollow it out by subtracting out this volume.