But obviously if you're working this out on a test or notebook, you wouldn't be taking, or taking as much trouble to be putting all of these caveats in. So what we've now realized is that, okay, this expression, actually let's think about this. Let's think about the limit, the limit as theta approaches negative pi over four of this thing, without the restriction, of one over one minus the square root of two sine of theta. If we're dealing with this over, you know, in this open interval, or actually even disregarding that, this theta, or this expression is continuous at, it is defined and it is continuous at theta is equal to negative pi over four. So this is just going to be equal to one over one minus the square root of two times sine of negative pi over four. Sine of negative pi over four. Sine of negative pi over four, which we've already seen is negative square root of two over two.