So the definite integral from t is equal to two to t is equal to five of this expression of e to the 1.2t minus two t dt, dt. So if we just evaluate that, that will be the answer to this first question. So what is this going to be? Well, let's actually work it out. So what is the antiderivative of e to the 1.2t? Well, let me just try to do it over here. So if I am trying to calculate, let me write it as e to the five, or actually 6 5ths t, 12 tenths is the same thing as 6 5ths, 6 5ths t dt.