This is just going to equal this value, which is what? If we put it in lowest common form, simplified form, it's negative 4 over 3. So this limit exists. This was an indeterminate form, and the limit of this function's derivative over this function's derivative exists. So this limit must also equal negative 4 over 3. And by that same argument, that limit also must be equal to negative 4 over 3. And for those of you who say, hey, we already knew how to do this.