We know that if we're taking the integral of x to the n dx, the antiderivative of that is going to be x to the n plus one over n plus one. And if we were just taking an indefinite integral, there would be some plus c. The reason why we don't put the plus c's here is when you evaluated both bounds of integration, the c would cancel out regardless of what it is. So we don't really think about the c much when we're taking indefinite integrals. But let's apply that to six x to the negative third power. So it's going to be, we're going to take x to the negative three plus one, so it's x to the negative two, and so we're going to divide by negative two as well. And of course we had that six out front from the get-go, so that's the antiderivative six x to the negative three power. And what's the antiderivative one over x?