So this is equal to the integral from two to four of six over x to the third power plus x squared over x to the third power dx. I just separated this numerator out. I just divided each of those terms by x to the third power. And this I could rewrite. This is equal to the integral from two to four of six x to the negative three power. That's that first term there. And x squared divided by x to the third, well that is going to be one over x.