And 1 half, I just put the 2 in the denominator there, times dy dx times the derivative of y with respect to x is going to be equal to the negative square root of y. I just subtracted the square root of y from both sides. And actually, this is something that I might actually want to copy and paste up here. So copy and then paste. So let's go back up here just to continue our simplification solving for dy dx. Well, to solve for dy dx, we just have to divide both sides by x over 2 times the square root of y. So we're left with dy dx is equal to, or dividing both sides by this is the same thing as multiplying by the reciprocal of this, is equal to 2 times the square root of y over x, over my yellow x, times the negative square root of y. Well, what's this going to simplify to?