We're saying for at least one C in this interval, f of C is going to be equal to four. It's important that four is between three and six because that's the value of our function, and the C needs to be in our closed interval along the X axis. So I'm gonna rule this out. They're trying to confuse us. All right, f of C equals zero for at least one C between negative two and one. Well, here they got the interval along the X axis right. That's where the C would be between, but it's not guaranteed by the intermediate value theorem that f of C is going to be equal to zero because zero is not between three and six.