Who wrote the story viewed by 0.53 million viewers?
CREATE TABLE table_26914076_3 (
    story_by VARCHAR,
    us_viewers__millions_ VARCHAR
)
SELECT story_by FROM table_26914076_3 WHERE us_viewers__millions_ = "0.53"
Below are sql tables schemas paired with instruction that describes a task. Using valid SQLite, write a response that appropriately completes the request for the provided tables. ### Instruction: Who wrote the story viewed by 0.53 million viewers? ### Input: CREATE TABLE table_26914076_3 (
    story_by VARCHAR,
    us_viewers__millions_ VARCHAR
) ### Response: SELECT story_by FROM table_26914076_3 WHERE us_viewers__millions_ = "0.53"