Show the number of buildings with a height above the average or a number of floors above the average.
CREATE TABLE building (
    height_feet INTEGER,
    floors INTEGER
)
SELECT COUNT(*) FROM building WHERE height_feet > (SELECT AVG(height_feet) FROM building) OR floors > (SELECT AVG(floors) FROM building)
Below are sql tables schemas paired with instruction that describes a task. Using valid SQLite, write a response that appropriately completes the request for the provided tables. ### Instruction: Show the number of buildings with a height above the average or a number of floors above the average. ### Input: CREATE TABLE building (
    height_feet INTEGER,
    floors INTEGER
) ### Response: SELECT COUNT(*) FROM building WHERE height_feet > (SELECT AVG(height_feet) FROM building) OR floors > (SELECT AVG(floors) FROM building)