How many viewers for the episode with the weekly rank for living of 4?
CREATE TABLE table_name_25 (
    viewers VARCHAR,
    weekly_rank_for_living VARCHAR
)
SELECT viewers FROM table_name_25 WHERE weekly_rank_for_living = "4"
Below are sql tables schemas paired with instruction that describes a task. Using valid SQLite, write a response that appropriately completes the request for the provided tables. ### Instruction: How many viewers for the episode with the weekly rank for living of 4? ### Input: CREATE TABLE table_name_25 (
    viewers VARCHAR,
    weekly_rank_for_living VARCHAR
) ### Response: SELECT viewers FROM table_name_25 WHERE weekly_rank_for_living = "4"