How many viewers for the episode with the weekly rank for living of 4?
CREATE TABLE table_77974 (
    "Episode" text,
    "Air Date" text,
    "Timeslot" text,
    "Viewers" text,
    "Weekly Rank for Living" text
)
SELECT "Viewers" FROM table_77974 WHERE "Weekly Rank for Living" = '4'
Below are sql tables schemas paired with instruction that describes a task. Using valid SQLite, write a response that appropriately completes the request for the provided tables. ### Instruction: How many viewers for the episode with the weekly rank for living of 4? ### Input: CREATE TABLE table_77974 (
    "Episode" text,
    "Air Date" text,
    "Timeslot" text,
    "Viewers" text,
    "Weekly Rank for Living" text
) ### Response: SELECT "Viewers" FROM table_77974 WHERE "Weekly Rank for Living" = '4'