What is 2012 that has a winning % of 67%?
CREATE TABLE table_name_60 (
    win__percentage VARCHAR
)
SELECT 2012 FROM table_name_60 WHERE win__percentage = "67%"
Below are sql tables schemas paired with instruction that describes a task. Using valid SQLite, write a response that appropriately completes the request for the provided tables. ### Instruction: What is 2012 that has a winning % of 67%? ### Input: CREATE TABLE table_name_60 (
    win__percentage VARCHAR
) ### Response: SELECT 2012 FROM table_name_60 WHERE win__percentage = "67%"