What club has tries against of 75?
CREATE TABLE table_name_58 (
    club VARCHAR,
    tries_against VARCHAR
)
SELECT club FROM table_name_58 WHERE tries_against = "75"
Below are sql tables schemas paired with instruction that describes a task. Using valid SQLite, write a response that appropriately completes the request for the provided tables. ### Instruction: What club has tries against of 75? ### Input: CREATE TABLE table_name_58 (
    club VARCHAR,
    tries_against VARCHAR
) ### Response: SELECT club FROM table_name_58 WHERE tries_against = "75"