When 27,822 (72.3) is the percentage for how many electorate measurements are there?
CREATE TABLE table_20683381_3 (
    electorate VARCHAR,
    for___percentage_ VARCHAR
)
SELECT COUNT(electorate) FROM table_20683381_3 WHERE for___percentage_ = "27,822 (72.3)"
Below are sql tables schemas paired with instruction that describes a task. Using valid SQLite, write a response that appropriately completes the request for the provided tables. ### Instruction: When 27,822 (72.3) is the percentage for how many electorate measurements are there? ### Input: CREATE TABLE table_20683381_3 (
    electorate VARCHAR,
    for___percentage_ VARCHAR
) ### Response: SELECT COUNT(electorate) FROM table_20683381_3 WHERE for___percentage_ = "27,822 (72.3)"