What is the largest average for the episode with 1.97 million Hong Kong viewers?
CREATE TABLE table_24856090_1 (
    average INTEGER,
    hk_viewers VARCHAR
)
SELECT MAX(average) FROM table_24856090_1 WHERE hk_viewers = "1.97 million"
Below are sql tables schemas paired with instruction that describes a task. Using valid SQLite, write a response that appropriately completes the request for the provided tables. ### Instruction: What is the largest average for the episode with 1.97 million Hong Kong viewers? ### Input: CREATE TABLE table_24856090_1 (
    average INTEGER,
    hk_viewers VARCHAR
) ### Response: SELECT MAX(average) FROM table_24856090_1 WHERE hk_viewers = "1.97 million"