 
 <prompt> Parker wan sabi wetin be di average percentage of kernels wey dey pop for inside one bag. For di first bag wey e do, 60 kernels pop out of 75 wey dey inside di bag. For di second bag, 42 kernels pop out of 50 wey dey inside di bag. For di final bag, 82 kernels pop out of 100 wey dey inside di bag. <response>: ```For di first bag, di proportion wey dey pop na .8 because 60 / 75 = .8
For di second bag, di proportion wey dey pop na .84 because 42 / 50 = .84
For di third bag, di proportion wey dey pop na .82 because 82 / 100 = .82
Di total proportions na 2.46 because .8 + . 84 + .82 = 2.46
Di average proportion na .82 because 2.46 / 3 = .82
Di average percentage na 82 because .82 x 100 = 82

Di answer go be 82.``` 