 
 <prompt> Hasan nikan lo n fi awọn ohun rẹ sile nitori o ti yoo mu ilẹ rẹ lo si orile-ede keji fun iṣẹ titun. O gbọdọ awọn ọpọlọpọ ibi rẹ si ilẹ rẹ titun. Awọn alagbada ti pe Hasan lati jẹ ki o ki o si fi ohun kan lori ibi kaadi lẹhin pe o si fi ohun kan lori ibi kaadi. Awọn alagbada ti pe Hasan pẹlu iwe aṣẹ dijiti ti yoo fi o lati kọwọ pe o ni ibi ti o ba ti jẹ ni ibi kan kaadi. Hasan ni lọwọ ilẹ rẹ, o si mu kaadi kaadi pẹlu 38 awọn ọpọlọpọ dinner. Nigba ti o ṣe iṣẹ, iwe aṣẹ rẹ ti sọ pe kaadi rẹ jẹ ti jẹ ni ibi. Hasan mo pe gbogbo awọn ọpọlọpọ rẹ jẹ ọpọlọpọ ọpọlọpọ 10 ounces. O gbe ọpọlọpọ kan lori kaadi ati ṣe iṣẹ rẹ lẹhin pe iwe aṣẹ alagbada kan. Iwe aṣẹ rẹ ti sọ pe kaadi rẹ jẹ ti jẹ ni ibi. Hasan rẹpẹtẹ iṣẹ yii lẹhin pe o ti yọ awọn ọpọlọpọ, iwe aṣẹ alagbada ni kaadi yoo jẹ ni ibi ti o le fi kaadi. Hasan ni yan pe gbogbo kaadi ti o le fi 20 pounds nigbati iwe aṣẹ rẹ sọ pe kaadi rẹ jẹ ti jẹ ni ibi. Níbẹ ni o ti yọ awọn ọpọlọpọ ti o ni kaadi lati kaadi? <response>: ```Let x be the number of plates removed from the box.
Hasan figured out the movers' weight limit was 20 pounds. Since a pound is equal to 16 ounces, each box can hold 20 * 16, or 320 ounces.
Each plate weighs 10 ounces, so the weight of the plates in the box after Hasan removes enough plates to satisfy the movers' weight limit is (38 - x) * 10 ounces
Since these two values are equal, we can write the equation (38 - x) * 10 = 320.
Dividing both sides by 10 leaves 38-x = 32.
Adding x to both sides gives 38 – x + x = 32 +x, or, 38 = 32 +x
Subtracting 32 from both sides gives the value of x, which is the number of plates removed from the box, 38 -32 = 32 + x – 32, or, 6 = x

Answer is 6.``` 