 
 <prompt> ```The pikin for Ms. Swanson class get average of 5 zits each. The pikin for Mr. Jones class get average of six zits each. If dem get 25 pikin for Ms. Swanson class and 32 for Mr. Jones class, how many more zits dey for Mr. Jones class pass for Ms. Swanson class?``` <response>: ```First find di total number of zits for Mr. Jones' class: 6 zits/kid * 32 kids = 192 zits
Then find di total number of zits for Ms. Swanson's class: 5 zits/kid * 25 kids = 125 zits
Then subtract di number of zits for Ms. Swanson's class from di number for Mr. Jones' class to find di difference: 192 zits - 125 zits = 67 zits

Di final answer: 67.``` 