 
 <prompt> Carter get one jar wey get 20 green M&Ms and 20 red M&Ms. E chop 12 of the green M&Ms, then im sister come chop half of the red M&Ms and add 14 yellow M&Ms. If Carter pick one M&M at random now, wetin be the percentage chance wey e go get green M&M? <response>: ```First find di final number of green M&Ms by subtracting 12 from di starting number: 20 M&Ms - 12 M&Ms = 8 green M&Ms
Then find di final number of red M&Ms by dividing di starting number by half: 20 M&Ms / 2 = 10 red M&Ms
Then find di total number of M&Ms at di end by adding di number of red, green and yellow M&Ms: 8 M&Ms + 10 M&Ms + 14 M&Ms = 32 M&Ms
Then divide di number of green M&Ms by di total number of M&Ms and multiply by 100 to find di percentage chance Carter gets a green M&M: 8 M&Ms / 32 M&Ms * 100 = 25%

Di answer go be 25.``` 