 
 <translate> Let number of boys = x
Let number of girls = y
Therefore x/y = B and y/x = G
10(B + G) = 10[(x/y) + (y/x)] = 10[(x2 + y2)/xy] > 10 The answer: (C). <ibo> Ka ọnụọgụ ụmụ nwoke = x Ka ọnụ ọgụgụ ụmụ agbọghọ = y Ya mere x/y = B na y/x = G 10[(B + G) = 10[(x/y) + (y/x) ] = 10[(x2 + y2)/xy] > 10 Azịza ya bụ (C). 