 
<translate> Samantha, Aira, da kuma Joe suna da 6 x 3 = 18 rubber bands gaba ɗaya. Idan muka bari x ya zama adadin bands da Aira ke da shi, to Samantha tana da x + 5. Tun da Aira yana da band 1 ƙasa da Joe, to Joe yana da x + 1. Tun da yawan adadin bands shine 18, to, daidaituwa shine x + (x + 5) + (x + 1) = 18. Ta hanyar sauƙaƙa gefen hagu na lissafi, muna da 3x + 6 = 18. Sanya dukkan lambobi masu daidaito a gefen dama yana bada 3x = 12. Don haka darajar x ita ce 12 / 3 = 4. Saboda haka, Aira yana da 4 rubber bands. Amsar ita ce: 4. <eng> Samantha, Aira, and Joe have 6 x 3 = 18 rubber bands altogether. If we let x be the number of bands that Aira had, then Samantha had x + 5. Since Aira had 1 fewer band than Joe, then Joe had x + 1. Since the total number of bands is 18, then the equation is x + (x + 5) + (x + 1) = 18. By simplifying the left side of the equation, we have 3x + 6 = 18. Putting all the constant terms on the right side gives 3x = 12. So the value of x is 12 / 3 = 4. Hence, Aira had 4 rubber bands. The answer: 4. 