 
 <translate> The required number of boxes is such that it leaves a remainder of 1 when divided by 3, 4, 5 or 6 and no remainder of 1 when divided by 3, 4, 5 or 6 and no remainder when divided by 7. Such a number is 301.
So, the answer is (B). <ibo> Ọnụ ọgụgụ igbe achọrọ bụ nke na ọ na-ahapụ ihe fọdụrụnụ nke 1 mgbe ekewara ya na 3, 4, 5 ma ọ bụ 6 na enweghị ihe fọdụrụnụ nke 1 mgbe ekewara ya na 3, 4, 5 ma ọ bụ 6 na enweghị ihe fọdụrụ mgbe ekewara ya na 7. Nọmba dị otú ahụ bụ 301. Azịza ya bụ (B). 