 
<translate> (6n ^ 2 + 6n) = 6n ((n + 1), wanda ke rarraba ta duka 6 da 12, tunda n ((n + 1) koyaushe ma'aurata ne. Saboda haka, amsar ita ce (B). <eng> (6n^2 + 6n) = 6n(n + 1), which is divisible by both 6 and 12, since n(n+1) is always even.
Thus, the answer is (B). 