 
 <translate> The question is: A mother duck as 8 ducklings. The first 3 ducklings find 5 snails each. Another 3 ducklings find 9 snails each, and the remaining ducklings each find half the number of snails that mother duck finds. If mother duck finds tree times the total number of snails as the first 2 groups of ducklings, how many snails does the family of ducks have collectively?
Step-by-step reasoning process: The first 3 ducklings find 3 x 5 = 15 snails. The next 3 ducklings find 3 x 9 = 27 snails. They find a total of 15 + 27 = 42 snails. Mother duck finds 42 x 3 = 126 snails. The last group has 8 - 3 - 3 = 2 ducklings. They find 126 / 2 = 63 snails each. The family of ducks found a total of 42 + 126 + 63 + 63 = 294 snails.
 <hau> Tambayar ita ce: Uwar duck kamar ducklings 8. 'Ya'yan dabbobin 3 na farko sun sami gwangwani 5 kowannensu. Sauran 'yan duck 3 sun sami 9 da kowacce, kuma sauran ducklings kowannensu ya sami rabin adadin da mahaifiyar duck ta samu. Idan mahaifiyar duck ta sami bishiyar sau da yawa yawan snails kamar yadda ƙungiyoyi 2 na farko na ducklings, nawa snails ne dangin duck ke da shi? Tsarin tunani mataki-mataki: 'yan duck 3 na farko sun sami 3 x 5 = 15 snails. 'Ya'yan duckling 3 na gaba sun sami 3 x 9 = 27 snails. Sun sami jimillar 15 + 27 = 42 masu tsutsa. Uwar duck ta sami 42 x 3 = 126 snails. Ƙungiyar ƙarshe tana da 8 - 3 - 3 = 2 ducklings. Suna samun 126 / 2 = 63 da kowacce. Iyalin ducks sun sami jimlar 42 + 126 + 63 + 63 = 294 snails. 