 
 <translate> The question is: (y^n - b^n) is completely divisible by (y - b), when
Options:
(A) n is odd natural number
(B) n is even natural number
(C) n is any natural number
(D) n is prime
(E) None
Step-by-step reasoning process: For every natural number n, (y^n - b^n) is completely divisible by (y - b).
 <ibo> Ajụjụ a bụ: (y^n - b^n) bụ nke a ga-ekewa (y - b), mgbe Nhọrọ: (A) n bụ ọnụọgụgụ nkịtị (B) n bụ ọnụọgụgụ nkịtị (C) n bụ nọmba ọ bụla (D) n bụ isi (E) Ọ dịghị Nzọụkwụ site na usoro ntụgharị uche: Maka ọnụọgụ ọ bụla n, (y ^ n - b ^ n) na - ekewa (y - b) kpamkpam. 