 
<translate> Ọ bụrụ na Rover nwere ntụpọ 46, mgbe ahụ ọkara ntụpọ dịka Rover nwere bụ 46 / 2 = 23 ntụpọ. Ọ bụrụ na Cisco nwere 5 na-erughị ọkara ọtụtụ ntụpọ dị ka Rover nwere, mgbe ahụ Cisco nwere 23 - 5 = 18 ntụpọ. Ọ bụrụ na Granger nwere okpukpu ise karịa Cisco, mgbe ahụ Rover nwere 18 * 5 = 90 ntụpọ. Ya mere, ngụkọta ọnụ ọgụgụ nke ntụpọ nke Rover na Cisco nwere bụ 90 + 18 = 108 ntụpọ. Ya mere, azịza ya bụ 108. <eng> If Rover has 46 spots, then half as many spots as Rover has is 46 / 2 = 23 spots. If Cisco has 5 less than half as many spots as Rover has, then Cisco has 23 - 5 = 18 spots. If Granger has five times as many spots as Cisco, then Rover has 18 * 5 = 90 spots. Thus, the total combined number of spots that Rover and Cisco have is 90 + 18 = 108 spots. So, the answer is 108. 