 
 <translate> Question: Antony, Ben, and Charles each try independently to win a carnival game. If their individual probabilities for success are 1/5, 3/8, and 2/7, respectively, what is the probability that exactly two of the three players will win but one will lose?
Options:
(A) 3/140
(B) 1/28
(C) 7/40
(D) 3/35
(E) 5/40
Stream-of-consciousness: P = P(A wins, B wins, C loses) + P(A wins, B loses, C wins) + P(A loses, B wins, C wins) = 1/5*3/8*5/7 + 1/5*5/8*2/7 + 4/5*3/8*2/7 = 7/40. <hau> Tambaya: Antony, Ben, da Charles kowannensu ya yi ƙoƙari ya ci nasara a wasan carnival. Idan yiwuwar su na yin nasara su ne 1/5, 3/8, da 2/7, daidai, menene yiwuwar cewa daidai biyu daga cikin 'yan wasan uku za su ci nasara amma ɗaya zai yi hasara? Zaɓuɓɓuka: (A) 3/140 (A) 3/140 (B) 1/28 (C) 7/40 (D) 3/35 (E) 5/40 Hanyoyin hankali: P = P ((A ya ci nasara, B ya ci nasara, C ya yi asara) + P ((A ya ci nasara, B ya yi asara, C ya ci nasara) + P ((A ya yi asara, B ya ci nasara, C ya ci nasara) = 1/5*3/8*5/7 + 1/5*5/8*2/7 + 4/5*3/8*2/7 = 7/40. 