 
<translate> Jimlar # na lambobin da za a iya samu shine 3*3*3 = 27. Daga cikin waɗannan lambobin 27 kawai samfurin 333 zai zama m, sauran 26 za su sami 2 ko 4 a cikinsu, wanda ke tabbatar da cewa samfurin su zai zama ma. Saboda haka adadin lambobin inda samfurin lambobi ya kasance daidai = (gaba ɗaya) - (iyakancewa) = 27 - 1 = 26. Amsar ita ce: (B). <eng> Total # of codes possible is 3*3*3 = 27. Oit of those 27 codes only the product of 333 will be odd, the remaining 26 will have either 2 or 4 in them, which ensures that their product will be even. Therefore the number of codes where the product of the digits is even = (total) - (restriction) = 27 - 1 = 26.
The answer: (B). 