 
<translate> Ajụjụ bụ: E jiri ya tụnyere mmiri o ṅụrụ, Carla ṅụrụ okpukpu atọ nke soda o ṅụrụ ma e wepụ ounce isii. Ọ bụrụ na ọ ṅụrụ mmiri dị otu lita, mmiri ole ka ọ ṅụrụ? Mmetụta uche: Ka s bụrụ oke soda Carla ṅụrụ na w bụ oke mmiri ọ ṅụrụ. Anyị maara na s + w = 54 na s = 3w - 6. N'iji nke abụọ n'ime nke mbụ, anyị na-enweta 3w - 6 + w = 54. Na ijikọta okwu ndị yiri ya, anyị na-enweta 4w - 6 = 54. Na-agbakwunye 6 n'akụkụ abụọ, anyị na-enweta 4w = 60. Ịkewaa akụkụ abụọ site na 4, anyị na-enweta w = 15. <eng> The question is: Compared to the amount of water she drank, Carla drank three times as much soda minus 6 ounces. If she drank 54 ounces of liquid total, how much water did she drink?
Stream of consciousness: Let s be the amount of soda Carla drank and w be the amount of water she drank. We know that s + w = 54 and s = 3w - 6. Substituting the second equation into the first, we get 3w - 6 + w = 54. Combining like terms, we get 4w - 6 = 54. Adding 6 to both sides, we get 4w = 60. Dividing both sides by 4, we get w = 15.
 