 
 <translate> Samantha, Aira, and Joe have 6 x 3 = 18 rubber bands altogether. If we let x be the number of bands that Aira had, then Samantha had x + 5. Since Aira had 1 fewer band than Joe, then Joe had x + 1. Since the total number of bands is 18, then the equation is x + (x + 5) + (x + 1) = 18. By simplifying the left side of the equation, we have 3x + 6 = 18. Putting all the constant terms on the right side gives 3x = 12. So the value of x is 12 / 3 = 4. Hence, Aira had 4 rubber bands. The answer: 4. <ibo> Samantha, Aira, na Joe nwere 6 x 3 = 18 rubber bands n'ozuzu. Ọ bụrụ na x bụ ọnụọgụgụ nke eriri nke Aira nwere, mgbe ahụ Samantha nwere x + 5. Ebe ọ bụ na Aira nwere 1 band ole na ole karịa Joe, mgbe ahụ Joe nwere x + 1. Ebe ọ bụ na ngụkọta ọnụ ọgụgụ nke eriri bụ 18, mgbe ahụ, nha anya bụ x + (x + 5) + (x + 1) = 18. Site n'ime ka akụkụ aka ekpe nke akụkụ ahụ dị mfe, anyị nwere 3x + 6 = 18. Ịtinye mkpụrụokwu niile n'akụkụ aka nri na-enye 3x = 12. Ya mere uru nke x bụ 12 / 3 = 4. N'ihi ya, Aira nwere eriri roba anọ. Azịza ya bụ: 4. 