 
 <translate> Whenever you are asked to find the number of digits, try to bring the number in multiples of 10. This way, we can wasily calculate the umber of 0's through the powers of 10
50^8 × 8^3 × 11 = (5^2*2)^8*2^9*11 = 5^16*2^17*11 = 2*11*10^16 = 22*10^16
Hence we would have 16 trailing 0's and the three digits from 22
Total digits = 2 + 16 = 18 The final answer: (A). <ibo> Mgbe ọ bụla a gwara gị ka ị chọpụta ọnụ ọgụgụ nke mkpụrụ akwụkwọ, gbalịa ịkpọpụta ọnụ ọgụgụ ahụ n'ụdị nke 10 mụbara. N'ụzọ dị otu a, anyị nwere ike ịgbakọ ọnụọgụgụ nke 0 site na ike nke 10. 50^8 × 8^3 × 11 = (5^2*2) ^8*2^9*11 = 5^16*2^17*11 = 2*11*10^16 = 22*10^16 N'ihi ya, anyị ga-enwe 16 trailing 0 si na atọ digits si 22 Nchịkọta nke nọmba = 2 + 16 = 18 Azịza ikpeazụ bụ: (A). 