 
 <translate> We need a number that is a multiple of 7 that will give a remainder of 1 when divided by 2, 3, 4, 5, and 6. The least common multiple of these numbers is 60. So, we need a multiple of 7 that is 1 greater than a multiple of 60. The answer: (B). <ibo> Anyị chọrọ nọmba nke bụ́ ọtụtụ nke 7 nke ga-eme ka ihe fọdụrụnụ bụrụ 1 mgbe e kewara ya na 2, 3, 4, 5, na 6. Nke kacha nta n'ime ọnụ ọgụgụ ndị a bụ 60. Ya mere, anyị chọrọ a ọtụtụ nke 7 na bụ 1 ukwuu karịa a ọtụtụ nke 60. Azịza ya bụ: (B). 