 
<translate> Yiwuwar samun jan ball daga jakar1 sa'an nan kuma ja daga jakar 2 = 3/5 * 5/10 = 15/50 Yiwuwar samun baki ball daga jakar1 sa'an nan ja daga jakar 2 = 2/5 * 4 / 10 = 8/50 Yanzu ya zo da yanayin, sabili da haka amfani da yanayin yiwuwa: P ((Ja) / P ((Ja + Baƙi) (15/50) / ((15/50 +8/50) = 15/50 /23/50 = 15/23. Saboda haka, amsar ita ce (E). <eng> Probability of getting red ball from bag1 and then red from bag 2 = 3/5*5/10 = 15/50
Probability of getting black ball from bag1 and then red from bag 2 = 2/5*4/10 = 8/50
Now comes the condition, hence apply conditional probability:
P(Red)/ P(Red + Black)
(15/50)/(15/50+8/50) = 15/50 /23/50 = 15/23.
Thus, the answer is (E). 