 <translate> Total # of codes possible is 3*3*3 = 27. Oit of those 27 codes only the product of 333 will be odd, the remaining 26 will have either 2 or 4 in them, which ensures that their product will be even. Therefore the number of codes where the product of the digits is even = (total) - (restriction) = 27 - 1 = 26.
The answer: (B). <yor> Apapọ # ti awọn koodu ti o ṣee ṣe jẹ 3*3*3 = 27. Ninu awọn koodu 27 wọnyẹn nikan ni ọja ti 333 yoo jẹ alailẹgbẹ, awọn iyokù 26 yoo ni 2 tabi 4 ninu wọn, eyiti o rii daju pe ọja wọn yoo jẹ paapaa. Nítorí náà, iye àwọn kókó tí ìlọ́po àwọn dígítì jẹ́ ìlọ́po méjì = (gbogbo) - (ìkápá) = 27 - 1 = 26. Ìdáhùn: (B). 