 <translate> Whenever you are asked to find the number of digits, try to bring the number in multiples of 10. This way, we can wasily calculate the umber of 0's through the powers of 10
50^8 × 8^3 × 11 = (5^2*2)^8*2^9*11 = 5^16*2^17*11 = 2*11*10^16 = 22*10^16
Hence we would have 16 trailing 0's and the three digits from 22
Total digits = 2 + 16 = 18 The final answer: (A). <yor> Nígbàkigbà tí wọ́n bá ní kó o sọ iye àwọn dígí tó wà nínú rẹ̀, gbìyànjú láti sọ iye náà ní ìlọ́po mẹ́wàá. Ní ọ̀nà yìí, a lè rọra ṣírò iye 0 tí ó wà ní ìlà 10 50^8 × 8^3 × 11 = (5^2*2) ^8*2^9*11 = 5^16*2^17*11 = 2*11*10^16 = 22*10^16 Nítorí náà a ó ní 16 tí ó ń tẹ̀lé 0 àti àwọn dígítì mẹ́ta láti 22 Àkópọ̀ gbogbo dígí tó wà nínú ìwé náà ni: 2 + 16 = 18 Ìdáhùn tó gbẹ̀yìn ni: (A). 