 
 <translate> Probability of getting red ball from bag1 and then red from bag 2 = 3/5*5/10 = 15/50
Probability of getting black ball from bag1 and then red from bag 2 = 2/5*4/10 = 8/50
Now comes the condition, hence apply conditional probability:
P(Red)/ P(Red + Black)
(15/50)/(15/50+8/50) = 15/50 /23/50 = 15/23.
Thus, the answer is (E). <ibo> Ihe puru ime ka bọọlụ na-acha ọbara ọbara si n'akpa 1 ma na-acha ọbara ọbara si n'akpa 2 = 3/5*5/10 = 15/50 Ohere nke inweta nwa bọọlụ si akpa 1 na mgbe ahụ na-acha uhie uhie si akpa 2 = 2/5*4/10 = 8/50 Ugbu a, ọnọdụ ahụ na-abịa, ya mere tinye ohere nke ọnọdụ: P ((Red) / P ((Red + Black) (15/50) / ((15/50+8/50) = 15/50 /23/50 = 15/23. N'ihi ya, azịza ya bụ (E). 