 
 <translate> Six persons can be arranged in a row in 6! ways. Treat the three persons to sit together as one unit then there four persons and they can be arranged in 4! ways. Again three persons can be arranged among them selves in 3! ways. Favourable outcomes = 3!4! Required probability = 3!4!/6! = 1/5 So the answer is (C). <hau> Mutum shida za a iya shirya a jere a cikin hanyoyi 6. Bi da mutane uku su zauna tare a matsayin daya naúrar sa'an nan akwai mutane hudu da kuma za su iya shirya a 4! hanyoyi. Har ila yau, mutane uku za a iya shirya a tsakanin su a cikin hanyoyi 3. Sakamakon sakamako = 3!4! Da ake bukata yiwuwa = 3!4!/6! = 1/5 Saboda haka amsar ita ce (C). 