 
<translate> Ajụjụ bụ: Olee otú ọtụtụ zeros na e nwere na njedebe nke ọnụ ọgụgụ N, ma ọ bụrụ na N = 100! + 200!? Nhọrọ: (A) 73 (B) 49 (C) 20 (D) 48 (E) 24 Mmetụta uche: Ọnụ ọgụgụ nke efu na njedebe nke 100! ga-adị obere karịa ọnụ ọgụgụ nke efu na njedebe nke 200! N'ihi ya, ọ ga-ezu iji gbakọọ ọnụ ọgụgụ nke zeros dị ná ngwụsị nke 100! Ọnụ ọgụgụ nke zeroes = [100/5] + [100/25] + [100/125] = 20 + 4 + 0 = 24 <eng> The question is: How many zeroes are there at the end of the number N, if N = 100! + 200! ?
Options:
(A) 73
(B) 49
(C) 20
(D) 48
(E) 24
Stream of consciousness: The number of zeroes at the end of 100! will be less than the number of zeroes at the end of 200!
Hence it would be sufficient to calculate the number of zeroes at the end of 100!
Number of zeroes = [100/5] + [100/25] + [100/125] = 20 + 4 + 0 = 24
 