 
<translate> (1 namiji + 1 mace) <unk> 1 aikin rana = 1/3 + 1/4 = 7/12 Aikin da namiji 1 da mace 1 suka yi a rana 1/4 = ((7/12) x (1/4)) = 7/48 Sauran aikin = 1 - 7/48 = 41/48 Aikin da yaro 1 yayi a cikin 1/4 rana = ((1/12) x (1/4)) = 1/48 Saboda haka, Yawan yara maza da ake buƙata = ((41/48) x 48) = 41 Amsar ƙarshe: (A). <eng> (1 man + 1 woman)’s 1 day work = 1/3 + 1/4 = 7/12
Work done by 1 man and 1 women in 1/4 day = ((7/12) x (1/4)) = 7/48
Remaining work = 1 - 7/48 = 41/48
Work done by 1 boy in 1/4 day = ((1/12) x (1/4)) = 1/48
Therefore, Number of boys required = ((41/48) x 48) = 41 Final answer: (A). 