 
 <translate> Let number of boys = x
Let number of girls = y
Therefore x/y = B and y/x = G
3(B + G) = 3[(x/y) + (y/x)] = 3[(x2 + y2)/xy] > 3 The answer: (C). <ibo> Ka ọnụọgụ ụmụ nwoke = x Ka ọnụ ọgụgụ ụmụ agbọghọ = y Ya mere x/y = B na y/x = G 3[(B + G) = 3[(x/y) + (y/x) ] = 3[(x2 + y2)/xy] > 3 Azịza ya bụ: (C). 