 <translate> Ka X bụrụ afọ ole Cooper dị. Ya mere, Dante dị afọ X * 2 na Maria dị afọ X * 2 + 1. Nchịkọta nke afọ ndụ Cooper, Dante, na Maria bụ X + (X * 2) + (X * 2 + 1) = 31. Na ijikọta okwu ndị yiri ya, anyị na-enweta X * 5 + 1 = 31. Anyị wepụ otu n'akụkụ abụọ, anyị na-enweta X * 5 = 30. N'ịkewa akụkụ abụọ site na 5, anyị na-enweta X = 6 afọ. Azịza ya bụ: 6. <hau> Bari X ya zama shekarun Cooper. Don haka Dante yana da shekaru X * 2 kuma Maria tana da shekaru X * 2 + 1. Jimlar shekarun Cooper, Dante, da Maria shine X + (X * 2) + (X * 2 + 1) = 31. Idan muka haɗa abubuwa iri ɗaya, za mu sami X*5+1=31. Idan muka cire guda daga bangarorin biyu, za mu samu X * 5 = 30. Idan muka raba bangarorin biyu da 5, sai mu samu cewa x = 6 shekara. Amsar ita ce: 6. 