 <translate> (6n ^ 2 + 6n) = 6n ((n + 1), wanda ke rarraba ta duka 6 da 12, tunda n ((n + 1) koyaushe ma'aurata ne. Saboda haka, amsar ita ce (B). <ibo> (6n^2 + 6n) = 6n(n + 1), nke a na-ekewa site na 6 na 12, ebe ọ bụ na n(n+1) bụ mgbe niile. N'ihi ya, azịza ya bụ (B). 