 <translate> The question is: How many zeroes are there at the end of the number N, if N = 100! + 200! ?
Options:
(A) 73
(B) 49
(C) 20
(D) 48
(E) 24
Stream of consciousness: The number of zeroes at the end of 100! will be less than the number of zeroes at the end of 200!
Hence it would be sufficient to calculate the number of zeroes at the end of 100!
Number of zeroes = [100/5] + [100/25] + [100/125] = 20 + 4 + 0 = 24
 <yor> Ìbéèrè náà ni pé: Mélòó ni òfo tó wà ní òpin N, bí N = 100! + 200!? Àwọn àyè: (A) 73 (B) 49 (C) ogún (D) 48 (E) 24 Ìṣàn ìmọ̀lára: Nọ́mbà àwọn zérò ní òpin 100! yóò kéré ju iye zérò ní òpin 200! Nítorí náà, ó máa tó láti ṣírò iye zérò tó wà lẹ́yìn ọgọ́rùn-ún! Nọmba awọn odo = [100/5] + [100/25] + [100/125] = 20 + 4 + 0 = 24 