 <translate> N'otu ụlọ, e nwere 4 - 1 = okpukpu 3 nke nwere ụlọ obibi 5 n'otu n'otu. Maazị Resty nwere ngụkọta nke ụlọ 3 x ụlọ 5 = ụlọ obibi 15 site n'okpukpu nke abụọ ruo nke anọ n'otu ụlọ. Ya mere, n'otu ụlọ, e nwere ngụkọta nke 15 + 2 = 17 ụlọ. Ya mere, Maazị Resty nwere ngụkọta nke ụlọ obibi 17 x 2 = 34 n'ụlọ ya abụọ. N'ihi ya, azịza ya bụ 34. <hau> A cikin wani gini, akwai 4 - 1 = 3 benaye wanda ke da gidaje 5 kowannensu. Mista Resty yana da jimillar hawa 3 x raka'a 5 = raka'a 15 daga hawa na 2 zuwa na 4 a cikin gini ɗaya. Saboda haka, a cikin wani gini, akwai jimillar 15 + 2 = 17 gidaje. Saboda haka, Mista Resty yana da jimillar 17 x 2 = 34 na gidaje a cikin gine-ginensa biyu. Saboda haka, amsar ita ce 34. 