 
<translate> Ka ọnụọgụ ụmụ nwoke = x Ka ọnụ ọgụgụ ụmụ agbọghọ = y Ya mere x/y = B na y/x = G 10 (B + G) = 10 (x/y) + (y/x) = 10 (x2 + y2) /xy) > 10 Ya mere azịza ikpeazụ bụ (E). <eng> Let number of boys = x
Let number of girls = y
Therefore x/y = B and y/x = G
10(B + G) = 10[(x/y) + (y/x)] = 10[(x2 + y2)/xy] > 10 So the final answer is (E). 