 
<translate> (6n^2 + 6n) = 6n(n + 1), nke a na-ekewa site na 6 na 12, ebe ọ bụ na n(n+1) bụ mgbe niile. N'ihi ya, azịza ya bụ (B). <eng> (6n^2 + 6n) = 6n(n + 1), which is divisible by both 6 and 12, since n(n+1) is always even.
Thus, the answer is (B). 