v:Permutation notation#Wolfram
(1234524135)=(1243){\displaystyle {\begin{pmatrix}1&amp;2&amp;3&amp;4&amp;5\\2&amp;4&amp;1&amp;3&amp;5\end{pmatrix}}=(1243)} as a permutation matrix in Wolfram Alpha
http://www.wolframalpha.com/input/?i=permutation+(1+2+4+3)(5)
Compare: 

This image in itself can be interpreted in two different ways. The Wolfram page assigns it to the permutation above, which makes it a passive permutation.
But it could also be interpreted as an active permutation, which would be (1234531425)=(1342){\displaystyle {\begin{pmatrix}1&amp;2&amp;3&amp;4&amp;5\\3&amp;1&amp;4&amp;2&amp;5\end{pmatrix}}=(1342)}.
The latter would actually be more usual.
Own work
WatchduckYou can name the author as "T. Piesk", "Tilman Piesk" or "Watchduck".