The diamond cubic crystal structure occurs for example diamond (carbon), tin, and most semiconductors. There are 8 atoms in the cubic unit cell.  We can consider the structure as a simple cubic with a basis of 8 atoms, at positions
But comparing this to the FCC above, we see that it is simpler to describe the structure as FCC with a basis of two atoms at (0, 0, 0) and (1/4, 1/4, 1/4).  For this basis,  Equation () becomes:
And then the structure factor for the diamond cubic structure is the product of this and the structure factor for FCC above, (only including the atomic form factor once)
with the result
* If h, k, ℓ are of mixed parity (odd and even values combined) the first (FCC) term is zero, so 
* If h, k, ℓ are all even or all odd then the first (FCC) term is 4
** if h+k+ℓ is odd then 
** if h+k+ℓ is even and exactly divisible by 4 () then 
** if h+k+ℓ is even but not exactly divisible by 4 () the second term is zero and 
These points are encapsulated by the following equations:
where  is an integer.