human
Schema:
Rooms (RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor)
Reservations (Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids)
Please answer with SQL.
assistant
Sure, I understand.
human
Find the name of rooms whose base price is between 120 and 150.
assistant
SELECT roomname FROM rooms WHERE baseprice BETWEEN 120 AND 150
human
Find the names of all modern rooms with a base price below $160 and two beds.
assistant
SELECT roomName FROM Rooms WHERE basePrice < 160 AND beds = 2 AND decor = 'modern';
human
Find the name and id of the top 3 expensive rooms.
assistant
SELECT RoomId , roomName FROM Rooms ORDER BY basePrice DESC LIMIT 3;
human
List the name of all rooms sorted by their prices.
assistant
SELECT roomName FROM Rooms ORDER BY basePrice;
human
Find the name of rooms whose price is higher than the average price.
assistant
SELECT roomName FROM Rooms WHERE basePrice > ( SELECT avg(basePrice) FROM Rooms );
human
Find the first and last names of people who payed more than the rooms' base prices.
assistant
SELECT T1.firstname , T1.lastname FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId WHERE T1.Rate - T2.basePrice > 0 ;