human
Schema:
Ref_Document_Types (Document_Type_Code, Document_Type_Name, Document_Type_Description)
Ref_Budget_Codes (Budget_Type_Code, Budget_Type_Description)
Projects (Project_ID, Project_Details)
Documents (Document_ID, Document_Type_Code, Project_ID, Document_Date, Document_Name, Document_Description, Other_Details)
Statements (Statement_ID, Statement_Details)
Documents_with_Expenses (Document_ID, Budget_Type_Code, Document_Details)
Accounts (Account_ID, Statement_ID, Account_Details)
Please answer with SQL.
assistant
Sure, I understand.
human
Show the ids for projects with at least 2 documents.
assistant
SELECT project_id FROM Documents GROUP BY project_id HAVING count(*) >= 2
human
Show project ids and the number of documents in each project.
assistant
SELECT project_id , count(*) FROM Documents GROUP BY project_id
human
Show the document name and the document date for all documents on project with details 'Graph Database project'.
assistant
SELECT document_name , document_date FROM Documents AS T1 JOIN projects AS T2 ON T1.project_id = T2.project_id WHERE T2.project_details = 'Graph Database project'
human
Show the budget type code and description and the corresponding document id.
assistant
SELECT T2.budget_type_code , T2.budget_type_description , T1.document_id FROM Documents_with_expenses AS T1 JOIN Ref_budget_codes AS T2 ON T1.budget_type_code = T2.budget_type_code
human
What is the project id and detail for the project with at least two documents?
assistant
SELECT T1.project_id , T1.project_details FROM Projects AS T1 JOIN Documents AS T2 ON T1.project_id = T2.project_id GROUP BY T1.project_id HAVING count(*) > 2
human
Show the statement detail and the corresponding document name for the statement with detail 'Private Project'.
assistant
SELECT T1.statement_details , T2.document_name FROM Statements AS T1 JOIN Documents AS T2 ON T1.statement_id = T2.document_id WHERE T1.statement_details = "Private Project" ;