human
Schema:
regions (REGION_ID, REGION_NAME)
countries (COUNTRY_ID, COUNTRY_NAME, REGION_ID)
departments (DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID)
jobs (JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY)
employees (EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID)
job_history (EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID)
locations (LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID)
Please answer with SQL.
assistant
Sure, I understand.
human
display the average salary of employees for each department who gets a commission percentage.
assistant
SELECT department_id , AVG(salary) FROM employees WHERE commission_pct != 'null' GROUP BY department_id
human
Display the first and last name, and salary for those employees whose first name is ending with the letter m.
assistant
SELECT first_name , last_name , salary FROM employees WHERE first_name LIKE '%m'
human
display all the information of employees whose salary is in the range of 8000 and 12000 and commission is not null or department number does not equal to 40.
assistant
SELECT * FROM employees WHERE salary BETWEEN 8000 AND 12000 AND commission_pct != 'null' OR department_id != 40
human
What is the full name ( first name and last name ) for those employees who gets more salary than the employee whose id is 163?
assistant
SELECT first_name , last_name FROM employees WHERE salary > (SELECT salary FROM employees WHERE employee_id = 163 )
human
List the full name (first and last name), and salary for those employees who earn below 6000.
assistant
SELECT first_name , last_name , salary FROM employees WHERE salary < 6000
human
What are the full name (first and last name) and salary for all employees who does not have any value for commission?
assistant
SELECT first_name , last_name , salary FROM employees WHERE commission_pct = "null" ;