human
Schema:
Ref_Characteristic_Types (characteristic_type_code, characteristic_type_description)
Ref_Colors (color_code, color_description)
Ref_Product_Categories (product_category_code, product_category_description, unit_of_measure)
Characteristics (characteristic_id, characteristic_type_code, characteristic_data_type, characteristic_name, other_characteristic_details)
Products (product_id, color_code, product_category_code, product_name, typical_buying_price, typical_selling_price, product_description, other_product_details)
Product_Characteristics (product_id, characteristic_id, product_characteristic_value)
Please answer with SQL.
assistant
Sure, I understand.
human
How many characteristics does the product named 'sesame' have?
assistant
SELECT count(*) FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id = t2.product_id WHERE t1.product_name = 'sesame'
human
Count the products that have the color description 'white' or have the characteristic name 'hot'.
assistant
SELECT count(*) FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id = t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id = t3.characteristic_id JOIN ref_colors AS t4 ON t1.color_code = t4.color_code WHERE t4.color_description = 'white' OR t3.characteristic_name = 'hot'
human
Find the names of all the product characteristics.
assistant
SELECT DISTINCT characteristic_name FROM CHARACTERISTICS
human
What is the characteristic name used by most number of the products?
assistant
SELECT t3.characteristic_name FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id = t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id = t3.characteristic_id GROUP BY t3.characteristic_name ORDER BY count(*) DESC LIMIT 1
human
Which category does the product named 'flax' belong to?
assistant
SELECT product_category_code FROM products WHERE product_name = 'flax'
human
Count the number of characteristics of the 'flax' product.
assistant
SELECT COUNT( * ) FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id = t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id = t3.characteristic_id WHERE t1.product_name = "flax" ;