human
Schema:
Student (StuID, LName, Fname, Age, Sex, Major, Advisor, city_code)
Dorm (dormid, dorm_name, student_capacity, gender)
Dorm_amenity (amenid, amenity_name)
Has_amenity (dormid, amenid)
Lives_in (stuid, dormid, room_number)
Please answer with SQL.
assistant
Sure, I understand.
human
Find the total capacity of all dorms.
assistant
SELECT sum(student_capacity) FROM dorm
human
Find the name of amenities Smith Hall dorm have.
assistant
SELECT T3.amenity_name FROM dorm AS T1 JOIN has_amenity AS T2 ON T1.dormid = T2.dormid JOIN dorm_amenity AS T3 ON T2.amenid = T3.amenid WHERE T1.dorm_name = 'Smith Hall'
human
Find the name and capacity of the dorm with least number of amenities.
assistant
SELECT T1.dorm_name , T1.student_capacity FROM dorm AS T1 JOIN has_amenity AS T2 ON T1.dormid = T2.dormid JOIN dorm_amenity AS T3 ON T2.amenid = T3.amenid GROUP BY T2.dormid ORDER BY count(*) LIMIT 1
human
Find the number of dorms that have some amenity.
assistant
SELECT count(DISTINCT dormid) FROM has_amenity
human
How many dorms are there?
assistant
SELECT count(*) FROM dorm
human
For each dorm, how many amenities does it have?
assistant
SELECT COUNT( * ) , T1.dormid FROM dorm AS T1 JOIN has_amenity AS T2 ON T1.dormid = T2.dormid WHERE T1.student_capacity > 100 GROUP BY T1.dormid ;