human
Schema:
event (Event_ID, Date, Venue, Name, Event_Attendance)
journalist (journalist_ID, Name, Nationality, Age, Years_working)
news_report (journalist_ID, Event_ID, Work_Type)
Please answer with SQL.
assistant
Sure, I understand.
human
Show me all the journalist information for each journalist!
assistant
SELECT * FROM journalist;
human
What events have they each reported on.
assistant
SELECT * FROM news_report AS T1 JOIN event AS T2 ON T1.Event_ID = T2.Event_ID JOIN journalist AS T3 ON T1.journalist_ID = T3.journalist_ID ;