human
Schema:
Rooms (RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor)
Reservations (Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids)
Please answer with SQL.
assistant
Sure, I understand.
human
Find the names of rooms that have been reserved for more than 60 times.
assistant
SELECT T2.roomName FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T1.Room HAVING count(*) > 60
human
Find the number of rooms that do not have any reservation.
assistant
SELECT count(*) FROM rooms WHERE roomid NOT IN (SELECT DISTINCT room FROM reservations)
human
Find the number of rooms with a king bed.
assistant
SELECT count(*) FROM Rooms WHERE bedType = 'King';
human
Find the number of rooms for each bed type.
assistant
SELECT bedType , count(*) FROM Rooms GROUP BY bedType;
human
What is the total number of people who could stay in the modern rooms in this inn?
assistant
SELECT sum(maxOccupancy) FROM Rooms WHERE decor = 'modern';
human
How many rooms are there?
assistant
SELECT COUNT( * ) FROM Rooms ;