human
Schema:
Accounts (account_id, customer_id, account_name, other_account_details)
Customers (customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details)
Customers_Cards (card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details)
Financial_Transactions (transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details)
Please answer with SQL.
assistant
Sure, I understand.
human
Show ids, customer ids, card type codes, card numbers for all cards.
assistant
SELECT card_id , customer_id , card_type_code , card_number FROM Customers_cards
human
Show ids, first names, last names, and phones for all customers.
assistant
SELECT customer_id , customer_first_name , customer_last_name , customer_phone FROM Customers
human
Show all customer ids and the number of cards owned by each customer.
assistant
SELECT customer_id , count(*) FROM Customers_cards GROUP BY customer_id
human
Show id, first and last names for all customers with at least two cards.
assistant
SELECT T1.customer_id , T2.customer_first_name , T2.customer_last_name FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING count(*) >= 2
human
Show the first names and last names of customers without any account.
assistant
SELECT customer_first_name , customer_last_name FROM Customers EXCEPT SELECT T1.customer_first_name , T1.customer_last_name FROM Customers AS T1 JOIN Accounts AS T2 ON T1.customer_id = T2.customer_id
human
Show the customer ids and firstname without a credit card.
assistant
SELECT customer_id , customer_first_name FROM Customers EXCEPT SELECT T1.customer_id , T2.customer_first_name FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE card_type_code = "Credit" ;