human
Schema:
Apartment_Buildings (building_id, building_short_name, building_full_name, building_description, building_address, building_manager, building_phone)
Apartments (apt_id, building_id, apt_type_code, apt_number, bathroom_count, bedroom_count, room_count)
Apartment_Facilities (apt_id, facility_code)
Guests (guest_id, gender_code, guest_first_name, guest_last_name, date_of_birth)
Apartment_Bookings (apt_booking_id, apt_id, guest_id, booking_status_code, booking_start_date, booking_end_date)
View_Unit_Status (apt_id, apt_booking_id, status_date, available_yn)
Please answer with SQL.
assistant
Sure, I understand.
human
What is the average number of rooms of apartments with type code 'Studio'?
assistant
SELECT avg(room_count) FROM Apartments WHERE apt_type_code = 'Studio'
human
Show the most common apartment type code among apartments with more than 1 bathroom.
assistant
SELECT apt_type_code FROM Apartments WHERE bathroom_count > 1 GROUP BY apt_type_code ORDER BY count(*) DESC LIMIT 1
human
What is the average number of bedrooms of all apartments?
assistant
SELECT avg(bedroom_count) FROM Apartments
human
How many apartments do not have any facility?
assistant
SELECT count(*) FROM Apartments WHERE apt_id NOT IN (SELECT apt_id FROM Apartment_Facilities)
human
Show the addresses of the buildings that have apartments with more than 2 bathrooms.
assistant
SELECT T1.building_address FROM Apartment_Buildings AS T1 JOIN Apartments AS T2 ON T1.building_id = T2.building_id WHERE T2.bathroom_count > 2
human
Give me the minimum and maximum bathroom count among all the apartments.
assistant
SELECT MIN( bathroom_count ) , MAX( bathroom_count ) FROM Apartments ;