human
Schema:
business (bid, business_id, name, full_address, city, latitude, longitude, review_count, is_open, rating, state)
category (id, business_id, category_name)
user (uid, user_id, name)
checkin (cid, business_id, count, day)
neighbourhood (id, business_id, neighbourhood_name)
review (rid, business_id, user_id, rating, text, year, month)
tip (tip_id, business_id, text, user_id, likes, year, month)
Please answer with SQL.
assistant
Sure, I understand.
human
Find all restaurant reviewed by Patrick in ' Dallas '
assistant
SELECT t1.name FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id JOIN review AS t3 ON t3.business_id = t1.business_id JOIN USER AS t4 ON t4.user_id = t3.user_id WHERE t1.city = 'Dallas' AND t2.category_name = 'restaurant' AND t4.name = 'Patrick';
human
Find all restaurant with Valet Service in Dallas Texas
assistant
SELECT t1.name FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id JOIN category AS t3 ON t3.business_id = t1.business_id WHERE t1.city = 'Dallas' AND t1.state = 'Texas' AND t2.category_name = 'Valet Service' AND t3.category_name = 'restaurant';
human
List all users who reviewed businesses that are restaurant .
assistant
SELECT t4.name FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id JOIN review AS t3 ON t3.business_id = t1.business_id JOIN USER AS t4 ON t4.user_id = t3.user_id WHERE t2.category_name = 'restaurant';
human
Find the users who have given tips on Pet Groomers
assistant
SELECT t4.name FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id JOIN tip AS t3 ON t3.business_id = t1.business_id JOIN USER AS t4 ON t4.user_id = t3.user_id WHERE t2.category_name = 'Pet Groomers';
human
Find all users who have written tips for ' Barrio Cafe ' in 2015
assistant
SELECT t3.name FROM tip AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id JOIN USER AS t3 ON t3.user_id = t2.user_id WHERE t1.name = 'Barrio Cafe' AND t2.year = 2015;
human
Find all users who have written tips about businesses in Dallas
assistant
SELECT t3.name FROM tip AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id JOIN USER AS t3 ON t3.user_id = t2.user_id WHERE t1.city = "Dallas" ;