human
Schema:
actor (actor_id, first_name, last_name, last_update)
address (address_id, address, address2, district, city_id, postal_code, phone, last_update)
category (category_id, name, last_update)
city (city_id, city, country_id, last_update)
country (country_id, country, last_update)
customer (customer_id, store_id, first_name, last_name, email, address_id, active, create_date, last_update)
film (film_id, title, description, release_year, language_id, original_language_id, rental_duration, rental_rate, length, replacement_cost, rating, special_features, last_update)
film_actor (actor_id, film_id, last_update)
film_category (film_id, category_id, last_update)
film_text (film_id, title, description)
inventory (inventory_id, film_id, store_id, last_update)
language (language_id, name, last_update)
payment (payment_id, customer_id, staff_id, rental_id, amount, payment_date, last_update)
rental (rental_id, rental_date, inventory_id, customer_id, return_date, staff_id, last_update)
staff (staff_id, first_name, last_name, address_id, picture, email, store_id, active, username, password, last_update)
store (store_id, manager_staff_id, address_id, last_update)
Please answer with SQL.
assistant
Sure, I understand.
human
What is the largest payment amount?
assistant
SELECT amount FROM payment ORDER BY amount DESC LIMIT 1
human
Find all the payment dates for the payments with an amount larger than 10 and the payments handled by a staff person with the first name Elsa.
assistant
SELECT payment_date FROM payment WHERE amount > 10 UNION SELECT T1.payment_date FROM payment AS T1 JOIN staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = 'Elsa'
human
When did the first payment happen?
assistant
SELECT payment_date FROM payment ORDER BY payment_date ASC LIMIT 1
human
What is the total amount of all payments?
assistant
SELECT sum(amount) FROM payment
human
Which customer, who has made at least one payment, has spent the least money? List his or her first name, last name, and the id.
assistant
SELECT T1.first_name , T1.last_name , T1.customer_id FROM customer AS T1 JOIN payment AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY sum(amount) ASC LIMIT 1
human
Which staff handled least number of payments? List the full name and the id.
assistant
SELECT T1.first_name , T1.last_name , T1.staff_id FROM staff AS T1 JOIN payment AS T2 ON T1.staff_id = T2.staff_id GROUP BY T1.staff_id ORDER BY COUNT( * ) ASC LIMIT 1 ;