human
Schema:
regions (REGION_ID, REGION_NAME)
countries (COUNTRY_ID, COUNTRY_NAME, REGION_ID)
departments (DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID)
jobs (JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY)
employees (EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID)
job_history (EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID)
locations (LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID)
Please answer with SQL.
assistant
Sure, I understand.
human
Display the first name and department name for each employee.
assistant
SELECT T1.first_name , T2.department_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id
human
display the department name and number of employees in each of the department.
assistant
SELECT department_name , COUNT(*) FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id GROUP BY department_name
human
display the department name and number of employees in each of the department.
assistant
SELECT T2.department_name , COUNT(*) FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id GROUP BY T2.department_name
human
get the details of employees who manage a department.
assistant
SELECT DISTINCT * FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id WHERE T1.employee_id = T2.manager_id
human
Find the ids of the departments where any manager is managing 4 or more employees.
assistant
SELECT DISTINCT department_id FROM employees GROUP BY department_id , manager_id HAVING COUNT(employee_id) >= 4
human
find the name of all departments that do actually have one or more employees assigned to them.
assistant
SELECT DISTINCT T2.department_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id ;