human
Schema:
Activity (actid, activity_name)
Participates_in (stuid, actid)
Faculty_Participates_in (FacID, actid)
Student (StuID, LName, Fname, Age, Sex, Major, Advisor, city_code)
Faculty (FacID, Lname, Fname, Rank, Sex, Phone, Room, Building)
Please answer with SQL.
assistant
Sure, I understand.
human
What is the name of the activity that has the most faculty members involved in?
assistant
SELECT T1.activity_name FROM Activity AS T1 JOIN Faculty_participates_in AS T2 ON T1.actID = T2.actID GROUP BY T1.actID ORDER BY count(*) DESC LIMIT 1
human
Show first name and last name for all the students advised by Michael Goodrich.
assistant
SELECT T2.fname , T2.lname FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID = T2.advisor WHERE T1.fname = 'Michael' AND T1.lname = 'Goodrich'
human
Show the rank, first name, and last name for all the faculty.
assistant
SELECT rank , Fname , Lname FROM Faculty
human
Show the faculty id of each faculty member, along with the number of students he or she advises.
assistant
SELECT T1.FacID , count(*) FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID = T2.advisor GROUP BY T1.FacID
human
What is the first and last name of the faculty participating in the most activities?
assistant
SELECT T1.fname , T1.lname FROM Faculty AS T1 JOIN Faculty_participates_in AS T2 ON T1.facID = T2.facID GROUP BY T1.FacID ORDER BY count(*) DESC LIMIT 1
human
Give me the the first and last name of the faculty who advises the most students.
assistant
SELECT T1.fname , T1.lname FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID = T2.advisor GROUP BY T1.FacID ORDER BY COUNT( * ) DESC LIMIT 1 ;