human
Schema:
circuits (circuitId, circuitRef, name, location, country, lat, lng, alt, url)
races (raceId, year, round, circuitId, name, date, time, url)
drivers (driverId, driverRef, number, code, forename, surname, dob, nationality, url)
status (statusId, status)
seasons (year, url)
constructors (constructorId, constructorRef, name, nationality, url)
constructorStandings (constructorStandingsId, raceId, constructorId, points, position, positionText, wins)
results (resultId, raceId, driverId, constructorId, number, grid, position, positionText, positionOrder, points, laps, time, milliseconds, fastestLap, rank, fastestLapTime, fastestLapSpeed, statusId)
driverStandings (driverStandingsId, raceId, driverId, points, position, positionText, wins)
constructorResults (constructorResultsId, raceId, constructorId, points, status)
qualifying (qualifyId, raceId, driverId, constructorId, number, position, q1, q2, q3)
pitStops (raceId, driverId, stop, lap, time, duration, milliseconds)
lapTimes (raceId, driverId, lap, position, time, milliseconds)
Please answer with SQL.
assistant
Sure, I understand.
human
What are all the drivers?
assistant
SELECT * FROM drivers;
human
Which ones of them had the first position in terms of laptime at least twice?
assistant
SELECT * FROM drivers AS T1 JOIN laptimes AS T2 ON T1.driverid = T2.driverid WHERE POSITION = "1" GROUP BY T1.driverid HAVING COUNT( * ) >= 2 ;