human
Schema:
circuits (circuitId, circuitRef, name, location, country, lat, lng, alt, url)
races (raceId, year, round, circuitId, name, date, time, url)
drivers (driverId, driverRef, number, code, forename, surname, dob, nationality, url)
status (statusId, status)
seasons (year, url)
constructors (constructorId, constructorRef, name, nationality, url)
constructorStandings (constructorStandingsId, raceId, constructorId, points, position, positionText, wins)
results (resultId, raceId, driverId, constructorId, number, grid, position, positionText, positionOrder, points, laps, time, milliseconds, fastestLap, rank, fastestLapTime, fastestLapSpeed, statusId)
driverStandings (driverStandingsId, raceId, driverId, points, position, positionText, wins)
constructorResults (constructorResultsId, raceId, constructorId, points, status)
qualifying (qualifyId, raceId, driverId, constructorId, number, position, q1, q2, q3)
pitStops (raceId, driverId, stop, lap, time, duration, milliseconds)
lapTimes (raceId, driverId, lap, position, time, milliseconds)
Please answer with SQL.
assistant
Sure, I understand.
human
What are all the drivers?
assistant
SELECT * FROM drivers;
human
Which ones of them participated in the race Australian Grand Prix held in 2009?
assistant
SELECT COUNT( * ) FROM results AS T1 JOIN races AS T2 ON T1.raceid = T2.raceid WHERE T2.name = "Australian Grand Prix" AND YEAR = 2009 ;