human
Schema:
Rooms (RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor)
Reservations (Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids)
Please answer with SQL.
assistant
Sure, I understand.
human
List the name of all rooms sorted by their prices.
assistant
SELECT roomName FROM Rooms ORDER BY basePrice;
human
Find the first and last names of people who payed more than the rooms' base prices.
assistant
SELECT T1.firstname , T1.lastname FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId WHERE T1.Rate - T2.basePrice > 0
human
Find the names of all modern rooms with a base price below $160 and two beds.
assistant
SELECT roomName FROM Rooms WHERE basePrice < 160 AND beds = 2 AND decor = 'modern';
human
Find the number of rooms with price higher than 120 for different decor.
assistant
SELECT decor , count(*) FROM Rooms WHERE basePrice > 120 GROUP BY decor;
human
Find the name of rooms whose base price is between 120 and 150.
assistant
SELECT roomname FROM rooms WHERE baseprice BETWEEN 120 AND 150
human
Find all the rooms that have a price higher than 160 and can accommodate more than 2 people. Report room names and ids.
assistant
SELECT roomName , RoomId FROM Rooms WHERE basePrice > 160 AND maxOccupancy > 2 ;