human
Schema:
Album (AlbumId, Title, ArtistId)
Artist (ArtistId, Name)
Customer (CustomerId, FirstName, LastName, Company, Address, City, State, Country, PostalCode, Phone, Fax, Email, SupportRepId)
Employee (EmployeeId, LastName, FirstName, Title, ReportsTo, BirthDate, HireDate, Address, City, State, Country, PostalCode, Phone, Fax, Email)
Genre (GenreId, Name)
Invoice (InvoiceId, CustomerId, InvoiceDate, BillingAddress, BillingCity, BillingState, BillingCountry, BillingPostalCode, Total)
InvoiceLine (InvoiceLineId, InvoiceId, TrackId, UnitPrice, Quantity)
MediaType (MediaTypeId, Name)
Playlist (PlaylistId, Name)
PlaylistTrack (PlaylistId, TrackId)
Track (TrackId, Name, AlbumId, MediaTypeId, GenreId, Composer, Milliseconds, Bytes, UnitPrice)
Please answer with SQL.
assistant
Sure, I understand.
human
List the phone numbers of all employees.
assistant
SELECT Phone FROM EMPLOYEE
human
What are the birth dates of employees living in Edmonton?
assistant
SELECT BirthDate FROM EMPLOYEE WHERE City = 'Edmonton'
human
What is the first name and last name employee helps the customer with first name Leonie?
assistant
SELECT T2.FirstName , T2.LastName FROM CUSTOMER AS T1 JOIN EMPLOYEE AS T2 ON T1.SupportRepId = T2.EmployeeId WHERE T1.FirstName = 'Leonie'
human
Find all the customer information in state NY.
assistant
SELECT * FROM CUSTOMER WHERE State = 'NY'
human
How many distinct cities does the employees live in?
assistant
SELECT COUNT(DISTINCT city) FROM EMPLOYEE
human
What city does the employee who helps the customer with postal code 70174 live in?
assistant
SELECT T2.City FROM CUSTOMER AS T1 JOIN EMPLOYEE AS T2 ON T1.SupportRepId = T2.EmployeeId WHERE T1.PostalCode = "70174" ;