human
Schema:
artist (Artist_ID, Name, Country, Year_Join, Age)
exhibition (Exhibition_ID, Year, Theme, Artist_ID, Ticket_Price)
exhibition_record (Exhibition_ID, Date, Attendance)
Please answer with SQL.
assistant
Sure, I understand.
human
How many artists do we have?
assistant
SELECT count(*) FROM artist
human
What is the theme and artist name for the exhibition with a ticket price higher than the average?
assistant
SELECT T1.theme , T2.name FROM exhibition AS T1 JOIN artist AS T2 ON T1.artist_id = T2.artist_id WHERE T1.ticket_price > (SELECT avg(ticket_price) FROM exhibition)
human
Show names for artists without any exhibition.
assistant
SELECT name FROM artist WHERE artist_id NOT IN (SELECT artist_id FROM exhibition)
human
Show all artist names and the number of exhibitions for each artist.
assistant
SELECT T2.name , count(*) FROM exhibition AS T1 JOIN artist AS T2 ON T1.artist_id = T2.artist_id GROUP BY T1.artist_id
human
What is the name and country for the artist with most number of exhibitions?
assistant
SELECT T2.name , T2.country FROM exhibition AS T1 JOIN artist AS T2 ON T1.artist_id = T2.artist_id GROUP BY T1.artist_id ORDER BY count(*) DESC LIMIT 1
human
What are the names of artist whose exhibitions draw over 200 attendees on average?
assistant
SELECT T3.name FROM exhibition_record AS T1 JOIN exhibition AS T2 ON T1.exhibition_id = T2.exhibition_id JOIN artist AS T3 ON T3.artist_id = T2.artist_id GROUP BY T3.artist_id HAVING avg ( T1.attendance ) > 200 ;