human
Schema:
Rooms (RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor)
Reservations (Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids)
Please answer with SQL.
assistant
Sure, I understand.
human
Find the first and last names of people who payed more than the rooms' base prices.
assistant
SELECT T1.firstname , T1.lastname FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId WHERE T1.Rate - T2.basePrice > 0
human
List the name of all rooms sorted by their prices.
assistant
SELECT roomName FROM Rooms ORDER BY basePrice;
human
Find the names of all modern rooms with a base price below $160 and two beds.
assistant
SELECT roomName FROM Rooms WHERE basePrice < 160 AND beds = 2 AND decor = 'modern';
human
Find the name and id of the top 3 expensive rooms.
assistant
SELECT RoomId , roomName FROM Rooms ORDER BY basePrice DESC LIMIT 3;
human
Which room has cheapest base price? List the room's name and the base price.
assistant
SELECT roomName , basePrice FROM Rooms ORDER BY basePrice ASC LIMIT 1;
human
What are the name of rooms that cost more than the average.
assistant
SELECT roomName FROM Rooms WHERE basePrice > ( SELECT avg ( basePrice ) FROM Rooms ) ;