human
Schema:
region (Region_ID, Region_name, Date, Label, Format, Catalogue)
party (Party_ID, Minister, Took_office, Left_office, Region_ID, Party_name)
member (Member_ID, Member_Name, Party_ID, In_office)
party_events (Event_ID, Event_Name, Party_ID, Member_in_charge_ID)
Please answer with SQL.
assistant
Sure, I understand.
human
Show member names that are not in the Progress Party.
assistant
SELECT T1.member_name FROM Member AS T1 JOIN party AS T2 ON T1.party_id = T2.party_id WHERE T2.Party_name != 'Progress Party'
human
What is the name of party with most number of members?
assistant
SELECT T2.party_name FROM Member AS T1 JOIN party AS T2 ON T1.party_id = T2.party_id GROUP BY T1.party_id ORDER BY count(*) DESC LIMIT 1
human
Show the member names which are in both the party with id 3 and the party with id 1.
assistant
SELECT member_name FROM member WHERE party_id = 3 INTERSECT SELECT member_name FROM member WHERE party_id = 1
human
Show names of parties that does not have any members.
assistant
SELECT party_name FROM party WHERE party_id NOT IN (SELECT party_id FROM Member)
human
Show all party names and the number of members in each party.
assistant
SELECT T2.party_name , count(*) FROM Member AS T1 JOIN party AS T2 ON T1.party_id = T2.party_id GROUP BY T1.party_id
human
List member names and their party names.
assistant
SELECT T1.member_name , T2.party_name FROM Member AS T1 JOIN party AS T2 ON T1.party_id = T2.party_id ;