human
Schema:
Activity (actid, activity_name)
Participates_in (stuid, actid)
Faculty_Participates_in (FacID, actid)
Student (StuID, LName, Fname, Age, Sex, Major, Advisor, city_code)
Faculty (FacID, Lname, Fname, Rank, Sex, Phone, Room, Building)
Please answer with SQL.
assistant
Sure, I understand.
human
Show ids for all the male faculty.
assistant
SELECT FacID FROM Faculty WHERE Sex = 'M'
human
Show the number of male and female assistant professors.
assistant
SELECT sex , count(*) FROM Faculty WHERE rank = 'AsstProf' GROUP BY sex
human
Show the faculty id of each faculty member, along with the number of students he or she advises.
assistant
SELECT T1.FacID , count(*) FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID = T2.advisor GROUP BY T1.FacID
human
Show all the ranks and the number of male and female faculty for each rank.
assistant
SELECT rank , sex , count(*) FROM Faculty GROUP BY rank , sex
human
Show the rank, first name, and last name for all the faculty.
assistant
SELECT rank , Fname , Lname FROM Faculty
human
Show the first name, last name, and phone number for all female faculty members.
assistant
SELECT Fname , Lname , phone FROM Faculty WHERE Sex = "F" ;