human
Schema:
regions (REGION_ID, REGION_NAME)
countries (COUNTRY_ID, COUNTRY_NAME, REGION_ID)
departments (DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID)
jobs (JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY)
employees (EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID)
job_history (EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID)
locations (LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID)
Please answer with SQL.
assistant
Sure, I understand.
human
What is the first name and job id for all employees in the Finance department?
assistant
SELECT T1.first_name , T1.job_id FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id WHERE T2.department_name = 'Finance'
human
What is the full name ( first name and last name ) for those employees who gets more salary than the employee whose id is 163?
assistant
SELECT first_name , last_name FROM employees WHERE salary > (SELECT salary FROM employees WHERE employee_id = 163 )
human
when is the hire date for those employees whose first name does not containing the letter M?
assistant
SELECT hire_date FROM employees WHERE first_name NOT LIKE '%M%'
human
display the full name (first and last), hire date, salary, and department number for those employees whose first name does not containing the letter M and make the result set in ascending order by department number.
assistant
SELECT first_name , last_name , hire_date , salary , department_id FROM employees WHERE first_name NOT LIKE '%M%' ORDER BY department_id
human
Display the first and last name, and salary for those employees whose first name is ending with the letter m.
assistant
SELECT first_name , last_name , salary FROM employees WHERE first_name LIKE '%m'
human
What are the full name, hire date, salary, and department id for employees without the letter M in their first name?
assistant
SELECT first_name , last_name , hire_date , salary , department_id FROM employees WHERE first_name NOT LIKE "%M%" ;