human
Schema:
circuits (circuitId, circuitRef, name, location, country, lat, lng, alt, url)
races (raceId, year, round, circuitId, name, date, time, url)
drivers (driverId, driverRef, number, code, forename, surname, dob, nationality, url)
status (statusId, status)
seasons (year, url)
constructors (constructorId, constructorRef, name, nationality, url)
constructorStandings (constructorStandingsId, raceId, constructorId, points, position, positionText, wins)
results (resultId, raceId, driverId, constructorId, number, grid, position, positionText, positionOrder, points, laps, time, milliseconds, fastestLap, rank, fastestLapTime, fastestLapSpeed, statusId)
driverStandings (driverStandingsId, raceId, driverId, points, position, positionText, wins)
constructorResults (constructorResultsId, raceId, constructorId, points, status)
qualifying (qualifyId, raceId, driverId, constructorId, number, position, q1, q2, q3)
pitStops (raceId, driverId, stop, lap, time, duration, milliseconds)
lapTimes (raceId, driverId, lap, position, time, milliseconds)
Please answer with SQL.
assistant
Sure, I understand.
human
What are the names of all the constructors?
assistant
SELECT * FROM constructors;
human
Show the names of those who are Japanese.
assistant
SELECT name FROM constructors WHERE nationality = 'Japanese';
human
Among those, who have once earned more than 5 points?
assistant
SELECT T1.name FROM constructors AS T1 JOIN constructorstandings AS T2 ON T1.constructorid = T2.constructorid WHERE T1.nationality = "Japanese" AND T2.points > 5 ;