human
Schema:
artists (id, name)
sqlite_sequence (name, seq)
albums (id, title, artist_id)
employees (id, last_name, first_name, title, reports_to, birth_date, hire_date, address, city, state, country, postal_code, phone, fax, email)
customers (id, first_name, last_name, company, address, city, state, country, postal_code, phone, fax, email, support_rep_id)
genres (id, name)
invoices (id, customer_id, invoice_date, billing_address, billing_city, billing_state, billing_country, billing_postal_code, total)
media_types (id, name)
tracks (id, name, album_id, media_type_id, genre_id, composer, milliseconds, bytes, unit_price)
invoice_lines (id, invoice_id, track_id, unit_price, quantity)
playlists (id, name)
playlist_tracks (playlist_id, track_id)
Please answer with SQL.
assistant
Sure, I understand.
human
List the name of all tracks in the playlists of Movies.
assistant
SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T3.id = T2.playlist_id WHERE T3.name = 'Movies';
human
List the name of all playlist.
assistant
SELECT name FROM playlists;
human
List the name of tracks belongs to genre Rock or media type is MPEG audio file.
assistant
SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id JOIN media_types AS T3 ON T3.id = T2.media_type_id WHERE T1.name = 'Rock' OR T3.name = 'MPEG audio file';
human
List the name of tracks belongs to genre Rock and whose media type is MPEG audio file.
assistant
SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id JOIN media_types AS T3 ON T3.id = T2.media_type_id WHERE T1.name = 'Rock' AND T3.name = 'MPEG audio file';
human
List all different genre types.
assistant
SELECT DISTINCT name FROM genres;
human
List all media types.
assistant
SELECT name FROM media_types ;