human
Schema:
circuits (circuitId, circuitRef, name, location, country, lat, lng, alt, url)
races (raceId, year, round, circuitId, name, date, time, url)
drivers (driverId, driverRef, number, code, forename, surname, dob, nationality, url)
status (statusId, status)
seasons (year, url)
constructors (constructorId, constructorRef, name, nationality, url)
constructorStandings (constructorStandingsId, raceId, constructorId, points, position, positionText, wins)
results (resultId, raceId, driverId, constructorId, number, grid, position, positionText, positionOrder, points, laps, time, milliseconds, fastestLap, rank, fastestLapTime, fastestLapSpeed, statusId)
driverStandings (driverStandingsId, raceId, driverId, points, position, positionText, wins)
constructorResults (constructorResultsId, raceId, constructorId, points, status)
qualifying (qualifyId, raceId, driverId, constructorId, number, position, q1, q2, q3)
pitStops (raceId, driverId, stop, lap, time, duration, milliseconds)
lapTimes (raceId, driverId, lap, position, time, milliseconds)
Please answer with SQL.
assistant
Sure, I understand.
human
Hello, how many drivers are there in total?
assistant
SELECT COUNT( * ) FROM drivers;
human
Perfect, how many drivers had 11 pit stops and participated in more than 5 total races?
assistant
SELECT COUNT( * ) FROM ( SELECT T1.surname , T1.driverid FROM drivers AS T1 JOIN pitstops AS T2 ON T1.driverid = T2.driverid GROUP BY T1.driverid HAVING COUNT( * ) = 11 INTERSECT SELECT T1.surname , T1.driverid FROM drivers AS T1 JOIN results AS T2 ON T1.driverid = T2.driverid GROUP BY T1.driverid HAVING COUNT( * ) > 5 ) ;