human
Schema:
Addresses (address_id, line_1_number_building, city, zip_postcode, state_province_county, country)
Staff (staff_id, staff_address_id, nickname, first_name, middle_name, last_name, date_of_birth, date_joined_staff, date_left_staff)
Vehicles (vehicle_id, vehicle_details)
Customers (customer_id, customer_address_id, customer_status_code, date_became_customer, date_of_birth, first_name, last_name, amount_outstanding, email_address, phone_number, cell_mobile_phone_number)
Customer_Payments (customer_id, datetime_payment, payment_method_code, amount_payment)
Lessons (lesson_id, customer_id, lesson_status_code, staff_id, vehicle_id, lesson_date, lesson_time, price)
Please answer with SQL.
assistant
Sure, I understand.
human
List lesson id of all lessons taught by staff with first name as Janessa
assistant
SELECT T1.lesson_id FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = 'Janessa';
human
Intersect that with last name Sawayn and nickname containing letter 's'.
assistant
SELECT T1.lesson_id FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn" AND nickname LIKE "%s%" ;