human
Schema:
item (i_id, title)
review (a_id, u_id, i_id, rating, rank)
useracct (u_id, name)
trust (source_u_id, target_u_id, trust)
Please answer with SQL.
assistant
Sure, I understand.
human
What is the user id of Helen
assistant
SELECT u_id FROM useracct WHERE name = 'Helen';
human
What is Helen rating?
assistant
SELECT T2.rating FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id WHERE T1.name = 'Helen';
human
And what is helen rank
assistant
SELECT T2.rank FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id WHERE T1.name = 'Helen';
human
What is helen item id
assistant
SELECT T2.i_id FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id WHERE T1.name = 'Helen';
human
How about her a id
assistant
SELECT T2.a_id FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id WHERE T1.name = 'Helen';
human
Who gave the most reviews
assistant
SELECT T1.name FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id GROUP BY T2.u_id ORDER BY COUNT( * ) DESC LIMIT 1;
human
How many review did he have
assistant
SELECT COUNT( * ) FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id GROUP BY T2.u_id ORDER BY COUNT( * ) DESC LIMIT 1;
human
Yes what is mark rank?
assistant
SELECT T2.rank FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id WHERE T1.name = 'Mark';
human
What is matk user id
assistant
SELECT u_id FROM useracct WHERE name = 'Mark';
human
What is his a id
assistant
SELECT T2.a_id FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id WHERE T1.name = "Mark" ;