human
Schema:
Student (StuID, LName, Fname, Age, Sex, Major, Advisor, city_code)
Video_Games (GameID, GName, GType)
Plays_Games (StuID, GameID, Hours_Played)
SportsInfo (StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship)
Please answer with SQL.
assistant
Sure, I understand.
human
Show last names for all student who are on scholarship.
assistant
SELECT T2.Lname FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T1.onscholarship = 'Y'
human
Show student ids who are on scholarship and have major 600.
assistant
SELECT StuID FROM Student WHERE major = 600 INTERSECT SELECT StuID FROM Sportsinfo WHERE onscholarship = 'Y'
human
Show ids for all students who live in CHI.
assistant
SELECT StuID FROM Student WHERE city_code = 'CHI'
human
List ids for all student who are on scholarship.
assistant
SELECT StuID FROM Sportsinfo WHERE onscholarship = 'Y'
human
Show all advisors who have at least two students.
assistant
SELECT advisor FROM Student GROUP BY advisor HAVING count(*) >= 2
human
Show ids for all students who have advisor 1121.
assistant
SELECT StuID FROM Student WHERE Advisor = 1121 ;