human
Schema:
Addresses (address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details)
Products (product_id, product_details)
Customers (customer_id, payment_method, customer_name, date_became_customer, other_customer_details)
Customer_Addresses (customer_id, address_id, date_address_from, address_type, date_address_to)
Customer_Contact_Channels (customer_id, channel_code, active_from_date, active_to_date, contact_number)
Customer_Orders (order_id, customer_id, order_status, order_date, order_details)
Order_Items (order_id, product_id, order_quantity)
Please answer with SQL.
assistant
Sure, I understand.
human
Find the name of customers who did not pay with Cash.
assistant
SELECT customer_name FROM customers WHERE payment_method != 'Cash'
human
Find the name of all customers.
assistant
SELECT customer_name FROM customers
human
Find the name of customers who are living in Colorado?
assistant
SELECT t1.customer_name FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t3.state_province_county = 'Colorado'
human
Which city has the most customers living in?
assistant
SELECT t3.city FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id GROUP BY t3.city ORDER BY count(*) DESC LIMIT 1
human
Retrieve the list of all cities.
assistant
SELECT DISTINCT city FROM addresses
human
Find the list of cities that no customer is living in.
assistant
SELECT city FROM addresses WHERE city NOT IN ( SELECT DISTINCT t3.city FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id ) ;