human
Ten stalls have 20 cows each. Mr. Sylas buys 40 cows and divides them equally, putting an equal number of the new cows into each of the twenty stalls. How many cows are in 8 of the stalls?
assistant
How many cows does each stall get? ** When Mr. Sylas puts an equal number of the cows he bought into the stalls, each stall gets 40/10 = <<40/10=4>>4 new cows.
How many cows are in 8 of the stalls? ** Each of the stalls gets four cows, meaning a total of 8*4 = <<8*4=32>>32 cows are placed into eight of the stalls.
How many cows were in 8 of the stalls? ** Since each stall had 20 cows before Mr. Sylas added four into each of the stalls, the total number of cows in eight of the stalls was 8*20= <<8*20=160>>160 cows.
How many cows are in 8 of the stalls? ** There are 160+32 = <<160+32=192>>192 cows in eight stalls after Mr. Sylas adds four into each of the stalls.
#### 192