human
Python program to find all lazy iterators.
assistant
Here is a Python program to find all lazy iterators

import re

def findall(pattern, string):
    """Returns a list of all matches for pattern in string."""
    return re.findall(pattern, string)

# Enter the string
string = "Hello, world!"

# Calling the function
print((findall("H", string)))

#Example Output
# ['H']

#Remember to inspect code for bugs.