human
stackoverflow dtype of a column.
assistant
Here is a Python code to create a stackoverflow dtype of a column

import pandas as pd

def get_dtype(column):
    """
    Return the dtype of a column.
    """
    return column.dtype

# Enter the column
column = pd.Series([1, 2, 3])

# Calling the function
print((get_dtype(column)))

#Example Output
# int64

#Remember to inspect code for bugs.