<prompt> Hlalosa tšebetso le tlhahiso ea khoutu e latelang:def fizz_buzzn: bakeng sa ke boemong 1, n1: haeba ke 3 0 le i 5 0: printFizzBuzz elif i 3 0: print Fizz elif i 5 0: hatisaBuzz e ngoe: hatisai  <response>: Instruction in English: Describe the function and output of the following code: . Response in English: The code defines a function named fizz_buzz that takes one integer input parameter n. The function uses a for loop to iterate from 1 to n inclusively, and for each integer in this range, checks if the integer is divisible by both 3 and 5, only 3, only 5, or neither. If the integer is divisible by both 3 and 5, the string FizzBuzz is printed. If the integer is divisible by only 3, the string Fizz is printed.If the integer is divisible by only 5, the string Buzz is printed.If the integer is not divisible by either 3 or 5, the integer itself is printed.For example, if n is equal to 15, the function outputs: 1 2 Fizz 4 Buzz Fizz 7 8 Fizz Buzz 11 Fizz 13 14 FizzBuzz There is no return statement in the function, so it does not return any value. . Response in Sesotho: Khoutu e hlalosa mosebetsi o bitsoang fizz_buzz o nkang paramethara e le ngoe ea n. Tsebetso e sebelisa a for loop ho pheta-pheta ho tloha ho 1 ho ea ho n ka kakaretso, me bakeng sa palo e ngoe le e ngoe lethathamong lena, e hlahloba hore na palo e ka aroloa ka bobeli 3 le 5, 3 feela, 5 feela, kapa che. Haeba palo e felletseng e aroloa ke 3 le 5, khoele ea FizzBuzz e tla hatisoa. Haeba palo e feletseng e aroloa ke 3 feela, khoele Fizz e hatisoa. Haeba palo kaofela e aroloa ka 5 feela, khoele Buzz e tla hatisoa. Haeba palo e feletseng e sa aroloe ka 3 kapa 5, palo e feletseng e tla hatisoa. Mohlala, haeba n e lekana le 15, tšebetso e hlahisa: 1 2 Fizz 4 Buzz Fizz 7 8 Fizz Buzz 11 Fizz 13 14 FizzBuzz Ha ho polelo ea kgutliso tšebetsong, kahoo ha e khutlise boleng bofe kapa bofe. 