<prompt> Fumana sebaka le pherimitha ea khutlonnetsepa ka bolelele ba 6cm le bophara ba 4cm.nan  <response>: Instruction in English: Find the area and the perimeter of a rectangle with length 6cm and width 4cm. . Response in English: The area of a rectangle is found by multiplying its length by its width. In the case of this rectangle, the area is 6cm 4cm 24 square centimeters or cm2.The perimeter of a rectangle is found by adding the length of all four sides. Since a rectangle has two sides of equal length and two sides of equal width, the formula for finding the perimeter is 2 Length Width. Plugging in the values for this rectangle, the perimeter is 2 6cm 4cm 20 centimeters or cm.So the area of the rectangle is 24cm2 and the perimeter is 20cm. . Response in Sesotho: Sebaka sa khutlonnetsepa se fumanoa ka ho atisa bolelele ba sona ka bophara ba sona. Tabeng ea khutlonnetsepa ena, sebaka ke 6cm 4cm 24 square centimeters kapa cm2. Pherimithara ea khutlonnetsepa e fumanoa ka ho eketsa bolelele ba mahlakore ohle a mane. Kaha khutlonnetsepa e na le mahlakore a mabeli a bolelele bo lekanang le mahlakore a mabeli a bophara bo lekanang, mokhoa oa ho fumana pherimitha ke 2 Bolelele Bophara. Ho hokela litekanyetso tsa khutlonnetsepa ena, pherimitha e 2 6cm 4cm 20 centimeters kapa cm. Kahoo sebaka sa khutlonnetsepa ke 24cm2 le pherimithara ke 20cm. 