<prompt> Ngola algorithm e hlahisang palo e lekanang ea linomoro ho tloha ho 0 ho isa ho 100nan  <response>: Instruction in English: Write an algorithm that generates an array of even numbers from 0 to 100 . Response in English: Here is one possible algorithm that generates an array of even numbers from 0 to 100:1. Create an empty array, lets call it even_numbers.2. Set a variable called counter to 0.3. Create a loop that will run as long as the counter variable is less than or equal to 100.4. Inside the loop, check if the counter variable is even by using the modulo operator. If the result of counter modulo 2 is equal to 0, then the number is even.5. If the number is even, add it to the even_numbers array using the append method.6. Increment the counter variable by 1 at the end of each loop iteration.7. Once the loop finishes, the even_numbers array will contain all the even numbers from 0 to 100.Heres an example implementation of the algorithm in Python:even_numbers counter 0while counter 100: if counter 2 0: even_numbers.appendcounter counter 1printeven_numbers . Response in Sesotho: Mona ke algorithm e le ngoe e ka hlahisang palo e lekanang ho tloha ho 0 ho isa ho 100: 1. Etsa lethathamo le se nang letho, ha re le bitse even_numbers. 2. Beha phapang e bitsoang counter ho 0. 3. Etsa lupu e tla sebetsa hafeela phapang ea khaonta e le tlase kapa e lekana le 100. 4. Ka hara lupu, hlahloba hore na phapang ea khaonta e tšoana le ka ho sebelisa opareitara ea modulo. . Haeba sephetho sa counter modulo 2 se lekana le 0, joale palo e lekana. 5. Haeba nomoro e lekana, e kenye lenaneng la esita le_dinomoro o sebedisa mokgwa wa eketsa. 6. Eketsa phapang ea khaontareng ka 1 qetellong ea nako e ngoe le e ngoe ea loop. 7. Hang ha loop e felile, lenane la even_numbers le tla ba le linomoro tse lekanang ho tloha ho 0 ho isa ho 100. Mona ke mohlala oa tsebetsong ea algorithm ho Python: even_numbers counter 0 ha counter 100: haeba counter 2 0: even_numbers.appendcounter khaontara 1 khatisoleha_linomoro 