<prompt> Sisinya tsela e betere ea ho rarolla bothata bona.Ho fanoe ka equation e latelang: 2x 3y 5  <response>: Instruction in English: Suggest a better way of solving this problem. . Response in English: One of the most efficient ways to solve this linear equation with two variables is to use the substitution method. Here are the steps to follow: 1. First, isolate one of the variables in the equation. For example, we can solve for y in terms of x: - 2x 3y 5 - 3y 5 - 2x - y 5 - 2x32. Now that y is expressed in terms of x, you can choose a value for x and solve for the corresponding y-value. For instance, lets pick x 1: - y 5 - 213 13. So one possible solution to this equation is x,y 1,1. You can repeat this process and plug in different values for x to find more solutions. Its important to note that a linear equation with two variables has infinitely many solutions, so you can keep finding new solutions by plugging in different x-values. . Response in Sesotho: E ngoe ea litsela tse sebetsang ka ho fetisisa tsa ho rarolla equation ena ea mela e nang le mefuta e meli ke ho sebelisa mokhoa oa ho fetola. Mehato e lokelang ho lateloa ke ena: 1. Pele, arola e ngoe ea liphapang pakeng tsa equation. Mohlala, re ka rarolla y ho latela x: - 2x 3y 5 - 3y 5 - 2x - y 5 - 2x3 2. Kaha joale y e se e hlahisoa ho latela x, u ka khetha boleng ba x le tharollo bakeng sa boleng bo tsamaellanang ba y. Mohlala, ha re khethe x 1: - y 5 - 213 1 3. Kahoo tharollo e le ngoe ea equation ena ke x,y 1,1. O ka pheta tsebetso ena mme oa hokela litekanyetso tse fapaneng bakeng sa x ho fumana litharollo tse ling. Ho bohlokoa ho hlokomela hore equation ea mela e nang le mefuta e meli e na le litharollo tse ngata haholo, kahoo o ka lula o fumana litharollo tse ncha ka ho hokela ho x-boleng bo fapaneng. 