<prompt> Hlalosa se tla etsahala lekaleng le latelang la 3x28nan  <response>: Instruction in English: Describe what will happen in the following equation 3x28 . Response in English: In the given equation, 3x 2 8, the goal is to solve for the variable x. This can be done by isolating the variable on one side of the equation and placing the constants on the other side. Here is the step-by-step process to solve for x:1. Subtract 2 from both sides of the equation to eliminate the constant term on the left side: 3x 2 - 2 8 - 23x 62. Next, divide both sides of the equation by 3 to solve for x: 3x3 63x 2Thus, the solution to the equation 3x 2 8 is x 2. This means that when x is equal to 2, the equation is balanced, and both sides have the same value. It can be verified by substituting 2 back into the original equation: 32 2 86 2 88 8. . Response in Sesotho: Ho equation e fanoeng, 3x 2 8, sepheo ke ho rarolla phapang x. Sena se ka etsoa ka ho khetholla phapang ka lehlakoreng le leng la equation le ho beha li-constants ka lehlakoreng le leng. Mona ke mohato oa mohato oa ho rarolla bakeng sa x: 1. Tlosa 2 mahlakoreng ka bobeli a equation ho felisa lentsoe le sa khaotseng ka lehlakoreng le letšehali: 3x 2 - 2 8 - 2 3x 6 2. E latelang, arola mahlakore ka bobeli a equation ka 3 ho rarolla bakeng sa x: 3x3 63 x 2 Kahoo, tharollo ea equation 3x 2 8 ke x 2. Sena se bolela hore ha x e lekana le 2, equation e leka-lekane, me mahlakore ka bobeli a na le boleng bo tšoanang. E ka netefatsoa ka ho kenya 2 sebakeng sa equation ea mantlha: 32 2 8 6 2 8 8 8. 