<prompt> Etsa mohlala oa linomoro ho bontša Molao oa Boraro oa Newton.nan  <response>: Instruction in English: Create a numerical example to illustrate Newtons Third Law. . Response in English: Example:Imagine that two skaters, Skater A who weighs 60 kg and Skater B who weighs 50 kg, are facing each other on an ice rink. They place their hands against each others and push. According to Newtons Third Law of Motion, for every action, there is an equal and opposite reaction. This means that if Skater A pushes Skater B with a force of 10 N, then Skater B will also push back with a force of 10 N. In mathematical terms, we can write the forces as follows: FA on B -FB on A where FA on B represents the force exerted by Skater A on Skater B and FB on A represents the force exerted by Skater B on Skater A. In this scenario, we can say that Skater A applies a force of 10 N on Skater B, thus: FA on B 10 N Since forces have magnitude and direction, we need to assign a positive direction to one of the forces to determine the direction of the other force. Lets assume that pushing to the right is positive, and pushing to the left is negative. This means that Skater A is pushing Skater B to the right positive direction, and according to Newtons Third Law, Skater B is pushing Skater A to the left negative direction with the same magnitude of force. Using the equation above, we can determine the force exerted by Skater B on Skater A: FA on B -FB on A 10 N -FB on A FB on A -10 N Therefore, Skater A pushes Skater B with a force of 10 N to the right, and Skater B pushes Skater A with a force of 10 N to the left. . Response in Sesotho: Mohlala: Aku nahane hore batho ba babeli ba thellang ka ho thella, Skater A ea boima ba 60 kg le Skater B ea boima ba likhilograma tse 50, ba shebane holima leqhoeng. Ba beha matsoho khahlanong le e mong le ho sututsana. Ho ea ka Newtons Third Law of Motion, bakeng sa ketso e ngoe le e ngoe, ho na le karabelo e lekanang le e fapaneng. Sena se bolela hore haeba Skater A e sutumelletsa Skater B ka matla a 10 N, joale Skater B le eona e tla sutumelletsa morao ka matla a 10 N. Ka mantsoe a lipalo, re ka ngola matla ka tsela e latelang: F A ho B - FB ho A moo FA ho B e emelang matla a sebelisoang ke Skater A ho Skater B le FB ho A e emelang matla a sebelisoang ke Skater B ho Skater A. Boemong bona, re ka re Skater A e sebelisa matla a 10 N ho Skater B, ka hona: F A ho B 10 N Kaha matla a na le boholo le tataiso, re hloka ho fana ka tataiso e ntle ho e ngoe ea matla ho fumana hore na matla a mang a hokae. A re nke hore ho sutumelletsa ka ho le letona ke ntho e ntle, me ho sutumelletsa ka ho le letšehali ho fosahetse. Sena se bolela hore Skater A e sutumelletsa Skater B ho ea ka ho le letona tataiso e nepahetseng, me ho ea ka Molao oa Boraro oa Newton, Skater B e sutumelletsa Skater A ho ea ka ho le letšehali kaelo e fosahetseng ka matla a tšoanang a matla. Ka ho sebelisa equation e ka holimo, re ka tseba matla a sebelisoang ke Skater B ho Skater A: FA ho B -FB ho A 10 N -FB ho A FB ho A - 10 N Ka hona, Skater A e sutumelletsa Skater B ka matla a 10 N ho ea ka ho le letona, me Skater B e sutumelletsa Skater A ka matla a 10 N ho ea ka ho le letšehali. 