<prompt> Boemo ba oxidation ea Sebabole ho Sodium Sulphate ke bofe?nan  <response>: Instruction in English: What is the oxidation state of Sulphur in Sodium Sulphate? . Response in English: The oxidation state of sulfur in sodium sulfate Na2SO4 is 6. To determine this, we can start by looking at the sulfate ion, SO42-, which has a charge of -2. Oxygen has an oxidation state of -2, so 4 oxygen atoms have an oxidation state of -8. Since the overall charge of the sulfate ion SO42- is -2, the oxidation state of sulfur must be 6 to balance out the -8 from the 4 oxygen atoms. . Response in Sesotho: Boemo ba oxidation ea sebabole ho sodium sulfate Na2SO4 ke 6. Ho fumana sena, re ka qala ka ho sheba ion sulfate, SO4 2-, e nang le tefiso ea -2. Oksijene e na le boemo ba oxidation ea -2, kahoo liathomo tse 4 tsa oksijene li na le boemo ba -8. Kaha tefiso e akaretsang ea ion ea sulfate SO42- ke -2, boemo ba oxidation ea sebabole e tlameha ho ba 6 ho leka-lekanya -8 ho tloha ho 4 liathomo tsa oksijene. 