<prompt> Equation e latelang e ka rarolloa joang?3x 4y 20  <response>: Instruction in English: How can the following equation be solved? . Response in English: The given equation 3x 4y 20 is a linear equation in two variables x and y. This equation represents a line in a 2-dimensional space. To get a unique solution from this equation, you need another linear equation in the same two variables. Then you can solve the 2 equations simultaneously for the values of x and y.However, if you only have this single equation, you can express one variable in terms of the other variable. Lets solve for y in terms of x, for example.3x 4y 20Subtracting 3x from both sides, we get:4y 20 - 3xDividing both sides by 4, we get:y 20 - 3x4So, if you know the value of x, you can find the value of y using the above equation. Similarly, you can solve for x in terms of y. . Response in Sesotho: Equation e fanoeng 3x 4y 20 ke palo e lekanang ka mefuta e meli ea x le y. Equation ena e emetse mola sebakeng sa 2-dimensional. Ho fumana tharollo e ikhethang ho tsoa ho equation ena, o hloka equation e ngoe ea mela ka mefuta e meli e tšoanang. Joale o ka rarolla lipalo tse 2 ka nako e le ngoe bakeng sa boleng ba x le y. Leha ho le joalo, haeba u e-na le equation ena e le ngoe feela, u ka hlalosa phapang e le ngoe ho latela phapang e ngoe. Ha re rarolle y ho latela x, mohlala. 3x 4y 20 Ho tlosa 3x mahlakoreng ka bobeli, re fumana: 4y 20 - 3x Ho arola mahlakore ka bobeli ka 4, re fumana: y 20 - 3x 4 Kahoo, haeba u tseba bohlokoa ba x, u ka fumana boleng ba y ho sebelisa equation e ka holimo. Ka mokhoa o tsoanang, o ka rarolla x ho latela y. 