<prompt> Ho latela lintlha tse latelang tsa data, equation ea mola ke efe?-2,5 2,-3  <response>: Instruction in English: Given the following data points, what is the equation of the line? . Response in English: The equation of the line can be written in the slope-intercept form, that is: y mx b, where m is the slope of the line and b is the y-intercept. To find the slope m, we can use the formula m y2 - y1x2 - x1, where x1, y1 and x2, y2 are two points on the line. Plugging in the values from the given points, -2,5 and 2,-3, we have:m -3 - 52 - -2 -84 -2Now that we have the slope, we can find the y-intercept b by plugging in one of the points in the equation y mx b, and solving for b. Lets use the point 2,-3-3 -22 b-3 -4 bb 1Therefore, the equation of the line is y -2x 1. . Response in Sesotho: Equation ea mola e ka ngoloa ka mokhoa oa ho thibela letsoapo, e leng: y mx b, moo m e leng letsoapo la mola le b ke y-intercept. Ho fumana moepa m, re ka sebelisa foromo m y2 - y1x2 - x1, moo x1, y1 le x2, y2 e leng lintlha tse peli moleng. Ho kenya litekanyetso ho tsoa lintlheng tse fanoeng, -2,5 le 2,-3, re na le: m -3 - 52 - -2 -84 - 2 Kaha joale re se re na le moepa, re ka fumana y-intercept b ka ho hokela e ngoe ea lintlha tsa equation y mx b, le ho rarolla bakeng sa b. Ha re sebeliseng ntlha 2,-3 -3 -2 2 b -3 -4 bb 1 Ka hona, equation ea mola ke y -2x 1. 