<prompt> Fumana karolo ea pele ea equation ena:fx x2 3x  <response>: Instruction in English: Find the first derivative of this equation: . Response in English: The first derivative of the function fx x2 3x is obtained using the power rule and the sum rule of differentiation.The power rule states that if fx xn, then fx nxn-1. Using this rule, we can find the derivative of the first term, x2, as follows:ddx x2 2x2-1 2xThe derivative of the second term, 3x, can be calculated using the constant multiple rule, which states that the derivative of a constant times a function is equal to the constant times the derivative of the function. In this case, the function is x and the derivative of x with respect to x is 1, so:ddx 3x 3 ddx x 3 1 3The sum rule of differentiation states that the derivative of a sum of two or more functions is equal to the sum of the derivatives of the individual functions. Applying this rule to the function fx x2 3x, we obtain:fx ddx x2 3x ddx x2 ddx 3x 2x 3Thus, the first derivative of the function fx x2 3x is fx 2x 3. . Response in Sesotho: Motsoako oa pele oa mosebetsi fx x2 3x o fumanoa ho sebelisoa molao oa matla le molao oa kakaretso oa phapang. Molao oa matla o bolela hore haeba fx xn, joale fx nxn-1. Ka ho sebelisa molao ona, re ka fumana motsoako oa lentsoe la pele, x2, ka tsela e latelang: ddx x2 2x2-1 2x Motsoako oa lentsoe la bobeli, 3x, e ka ba e baloang ho sebelisoa molao o sa fetoheng oa makhetlo a mangata, e bolelang hore karolo e tsoang ho nako e sa fetoheng ea tsebetso e lekana le linako tse sa fetoheng tse tsoang ho mosebetsi. Tabeng ena, mosebetsi ke x me motsoako oa x mabapi le x ke 1, kahoo: ddx 3x 3 ddx x 3 1 3 Molao oa kakaretso oa phapang o re hore motsoako oa kakaretso oa mesebetsi e meli kapa ho feta e lekana le kakaretso ea lihlahisoa tsa mesebetsi ka bomong. Ha re sebelisa molao ona mosebetsing fx x2 3x, re fumana: fx ddx x2 3x ddx x2 ddx 3x 2x 3 Kahoo, motsoako oa pele oa mosebetsi fx x2 3x ke fx 2x 3. 