<prompt> Fumana equation ea mola o fetang 2, 4 me o pota-potile mola -x y 3nan  <response>: Instruction in English: Find the equation of the line which passes through 2, 4 and is perpendicular to the line -x y 3 . Response in English: To find the equation of the line that passes through the point 2, 4 and is perpendicular to the line -x y 3, we can start by finding the slope of the given line. We can do this by writing the equation -x y 3 in slope-intercept form y mx b, where m is the slope of the line. Solving for y, we get:-x y 3y x 3The slope of the line -x y 3 is 1. Since the line we want to find is perpendicular to this line, its slope will be the negative reciprocal of this slope, which is -1.Now that we know the slope of the line we want to find, we can use the point-slope form of the equation of a line to find its equation. The point slope form is given by: y - y1 mx - x1, where m is the slope of the line, and x1, y1 is a point on the line. In our case, the slope of the line is -1 and the point on the line is 2, 4, so the equation of the line is:y - 4 -1x - 2y - 4 -x 2y -x 6Thus, the equation of the line that passes through the point 2, 4 and is perpendicular to the line -x y 3 is y -x 6. . Response in Sesotho: Ho fumana equation ea mola o fetang ntlha 2, 4 me e le perpendicular ho mola -x y 3, re ka qala ka ho fumana letsoapo la mola o fanoeng. Re ka etsa sena ka ho ngola equation -x y 3 ka mokhoa oa ho thibela letsoapo y mx b, moo m e leng letsoapo la mola. Ho rarolla y, re fumana: -x y 3 y x 3 Moepa oa mola -x y 3 ke 1. Kaha mola oo re batlang ho o fumana o lebeletsoe ho latela mola ona, moepa oa oona e tla ba oona. phetisetso e mpe ea moepa ona, e leng -1. Kaha joale re tseba moepa oa mola oo re batlang ho o fumana, re ka sebelisa mokhoa oa ntlha-moepa oa equation ea mola ho fumana equation ea eona. Foromo ea letsoapo la ntlha e fanoa ke: y - y1 mx - x1, moo m e leng moepa oa mola, le x1, y1 ke ntlha ea mola. Tabeng ea rona, letsoapo la mola ke -1 le ntlha ea mola ke 2, 4, kahoo equation ea mola ke: y - 4 -1x - 2 y - 4 -x. 2 y -x 6 Kahoo, equation ea mola o fetang ntlha 2, 4 me o pota-potile mola -x y 3 ke y -x 6. 