<prompt> Fumana bolelele ba maqhubu a leqhubu la molumo le maqhubu a 4.0×104.nan  <response>: Instruction in English: Find the wavelength of a sound wave with a frequency of 4.0×104. . Response in English: To find the wavelength of a sound wave, you need to know the speed of sound. The speed of sound depends on the medium it is traveling through and the temperature of that medium. Lets assume that the sound wave is traveling through air at a temperature of 20 degrees Celsius 68 degrees Fahrenheit. The speed of sound under these conditions is approximately 343 meters per second.The formula to calculate the wavelength of a sound wave is given by:Wavelength λ Speed of sound v Frequency fSubstituting the values into the formula, we get:Wavelength λ 343 ms 4.0 × 104 Hz 8.575 × 10-3 m 8.575 mmHence, the wavelength of a sound wave with a frequency of 4.0×104 Hz in air at 20 degrees Celsius is approximately 8.575 mm millimeters. . Response in Sesotho: Ho fumana bolelele ba maqhubu a leqhubu la molumo, o hloka ho tseba lebelo la molumo. Lebelo la molumo le itšetlehile ka mokhoa oo o tsamaeang ho oona le mocheso oa mochine oo. A re nke hore leqhubu la molumo le tsamaea moeeng ka mocheso oa likhato tse 20 tsa Celsius 68 degrees Fahrenheit. Lebelo la molumo tlasa maemo ana ke hoo e ka bang limithara tse 343 ka motsotsoana. Foromo ea ho bala bolelele ba maqhubu a molumo oa molumo o fanoa ke: Wavelength λ Lebelo la molumo v Frequency f Ho fetola boleng ka foromo, re fumana: Wavelength λ 343 ms 4.0 × 104 Hz 8.575 × 10 -3 m 8.575 mm Kahoo, bolelele ba maqhubu a molumo o nang le maqhubu a 4.0 × 104 Hz moeeng ka likhato tse 20 tsa Celsius ke hoo e ka bang 8.575 mm limilimithara. 