<prompt> Fana ka tharollo ea equation 2a3b20nan  <response>: Instruction in English: Provide a solution to the equation 2a3b20 . Response in English: The equation 2a 3b 20 has infinitely many solutions, as there are two variables and only one equation. However, I can provide you with possible values for a and b that satisfy the given equation.For example, one possible solution would be to let a 5, and then solve for b. Substituting the value of a into the given equation: 25 3b 2010 3b 203b 10b 103So one possible solution to the equation is a, b 5, 103. We can also find more solutions using the same method or by letting the value of b be any arbitrary number and then solving for a. . Response in Sesotho: Equation 2a 3b 20 e na le litharollo tse ngata haholo, kaha ho na le mefuta e meli le equation e le ngoe feela. Leha ho le joalo, nka u fa litekanyetso tse ka bang teng tsa a le b tse khotsofatsang palo e fanoeng. Ka mohlala, tharollo e le ngoe e ka ba ho lumella 5, ebe o rarolla bakeng sa b. Ho kenya boleng ba a ho equation e fanoeng: 25 3b 20 10 3b 20 3b 10 b 103 Kahoo tharollo e le ngoe ea equation ke a, b 5, 10 3. Hape re ka fumana litharollo tse ling re sebelisa mokhoa o tsoanang kapa ka ho lumella boleng ba b hore e be nomoro efe kapa efe e sa lekanyetsoang ebe re rarolla a. 