<prompt> Rala algorithm ho bapisa mantsoe a likhoele tse peli le ho fumana ho tšoana ho teng lipakeng tsa ona.Mohala oa 1: lesela la mokotla Mohala oa 2: pakete ea masela  <response>: Instruction in English: Design an algorithm to compare the words in two strings and determine the similarity between them. . Response in English: One possible algorithm to compare the similarity between two strings, based on their words, is as follows:1. Create a function, string_similaritystring1, string2, that receives as input two strings to compare.2. In the function, start by defining a variable, similarity_score and set its initial value to zero.3. Next, split each string into separate words using the split method. This will result in two lists containing the words of each string.4. Determine the total number of words in both strings by adding the lengths of the two lists. This value will be used later to calculate the similarity score.5. Use a loop to iterate over the list of words in String 1.6. For each word, use the in keyword to check if the word is present in the list of words for String 2. - If the word is found, increment the similarity_score by 1, and remove the word from the list of words for String 2 to prevent counting the same word multiple times.7. Once the loop is complete, calculate the final similarity_score by dividing the current value by the total number of words in both strings, and multiplying the result by 100 to obtain a percentage.8. Return the final similarity_score.For the given input, the function will return a similarity score of 66.67, indicating that two out of the three unique words are present in both strings.pythondef string_similaritystring1, string2: similarity_score 0 string1_words string1.split string2_words string2.split total_words lenstring1_words lenstring2_words for word in string1_words: if word in string2_words: similarity_score 1 string2_words.removeword similarity_score similarity_score total_words 100 return similarity_scorestring_similaritybackpack fabric, fabric pack Output: 66.67 . Response in Sesotho: Algorithm e ngoe e ka khonehang ea ho bapisa ho tšoana lipakeng tsa likhoele tse peli, ho ipapisitsoe le mantsoe a tsona, ke ka tsela e latelang: 1. Etsa mosebetsi, khoele_e tsoanangkhoele1, khoele2, e amohelang likhoele tse peli ho bapisa. 2. Boemong ba tshebetso, qala ka ho hlalosa phapang, tshwano_score mme o behe boleng ba yona ba ho qala ho zero. 3. Ka mora moo, arola khoele ka ngoe ka mantsoe a arohaneng u sebelisa mokhoa oa split. Sena se tla fella ka manane a mabeli a nang le mantsoe a khoele ka ngoe. 4. Fumana kakaretso ea mantsoe a likhoele ka bobeli ka ho kenyelletsa bolelele ba manane a mabeli. Boleng bona bo tla sebelisoa hamorao ho bala lintlha tse tšoanang. 5. Sebelisa lupu ho pheta-pheta lethathamo la mantsoe a Mohala oa 1. 6. Bakeng sa lentsoe ka leng, sebelisa in lentsoe la sehlooho ho hlahloba hore na lentsoe le teng lethathamong la mantsoe a Mohala oa 2. - Haeba lentsoe le fumanoa. , eketsa tsoana_ea lintlha ka 1, me u tlose lentsoe lethathamong la mantsoe a Mohala oa 2 ho thibela ho bala lentsoe le le leng ka makhetlo a mangata. 7. Hang ha luphu e phethiloe, bala se tšoanang_score ea ho qetela ka ho arola boleng ba hona joale ka kakaretso ea mantsoe a likhoele ka bobeli, me u atise sephetho ka 100 ho fumana peresente. 8. Khutlisetsa ho qetela tšoana_lintlha. Bakeng sa tlhahiso e fanoeng, tšebetso e tla khutlisa lintlha tse tšoanang tsa 66.67, e leng se bontšang hore mantsoe a mabeli ho a mararo a ikhethang a teng likhoeleng tseo ka bobeli. python def string_similaritylikhoele1, khoele2: similarity_score 0 string1_words string1.split string2_words string2.split total_words lenlikhoele1_words lenlikhoele2_mantsoe bakeng sa lentsoe le khoeleng1:_mantsoe a 2: similar_score 1 string2_words.removelentsoe similarity_score tsoantso_ea_mantsoe kakaretso_mantsoe 100 khutlisa tšoanang_score string_similaritylesela la mokotla, pack ea lesela Sephetho: 66.67 