<prompt> Etsa algorithm e rarollang bothata bona.Ha u fuoa lethathamo la linomoro, khutlisetsa feela linomoro tse lekanang lethathamong leo.  <response>: Instruction in English: Create an algorithm that solves this problem. . Response in English: 1. Define a function that takes a list of integers as an argument.2. Create an empty list to store the even numbers.3. Iterate through each integer in the given list.4. Check if the current integer is divisible by 2. If it is, append it to the list of even numbers.5. Return the list of even numbers. Code implementation in Python:pythondef even_numbersnumbers: list - list: even_nums for num in numbers: if num 2 0: even_nums.appendnum return even_nums . Response in Sesotho: 1. Hlalosa tšebetso e nkang lenane la linomoro e le khang. 2. Etsa lenane le se nang letho ho boloka linomoro tse lekanang. 3. Pheta palo e ngoe le e ngoe lethathamong le fanoeng. 4. Hlahloba hore na palo e feletseng ea hona joale e aroloa ka 2. Haeba e le teng, e kenyelle lethathamong la linomoro tse lekanang. 5. Khutlisetsa lenane la linomoro tse lekanang. Tsebetsong ea khoutu ho Python: python def even_numberslinomoro: list - lethathamo: even_nums bakeng sa palo ka lipalo: haeba palo 2 0: even_nums.appendnum khutlisetsa even_nums 