<prompt> Fumana tekanyo eo ntho e hlapolotsoeng ka eona ha 500 mL ea 0.3 M tharollo e kenngoa ho 800 mL ea 0.1 M tharollo.nan  <response>: Instruction in English: Find the rate at which a substance is diluted when 500 mL of a 0.3 M solution is added to 800 mL of a 0.1 M solution. . Response in English: To find the rate at which a substance is diluted when 500 mL of a 0.3 M solution is added to 800 mL of a 0.1 M solution, we can use the formula for dilution, where M1V1 M2V2.Where:- M1 is initial molarity- V1 is the initial volume- M2 is the final molarity- V2 is the final volumeLets assume that the final volume is equal to the sum of the initial volumes of both solutions, that is V2 500 mL 800 mL 1300 mL.Substituting the values into the dilution equation, and rearranging to solve for M2 gives:M2 M1V1V2 The total moles of the solute in the two solutions is:Number of moles in solution 1 M1 V1 0.3 M 0.5 L 0.15 molNumber of moles in solution 2 M1 V1 0.1 M0.8 L 0.08 molMoles of solute total 0.15 mol 0.08 mol 0.23 molNow lets substitute into the formula above, M2 mol of soluteV2M2 0.23 mol1.3L 0.177 M approximatelySo, the rate at which a substance is diluted when 500 mL of a 0.3 M solution is added to 800 mL of a 0.1 M solution is approximately 0.177 M. . Response in Sesotho: Ho fumana sekhahla seo ntho e hlapolotsoeng ka eona ha 500 ml ea motsoako oa 0.3 M e kenngoa ho 800 ml ea motsoako oa 0.1 M, re ka sebelisa mokhoa oa ho hlapolla, moo M1V1 M2V2. Moo: - M1 ke molarity ea pele - V1 ke molumo oa pele - M2 ke molarity ea ho qetela - V2 ke molumo oa ho qetela A re nke hore molumo oa ho qetela o lekana le kakaretso ea meqolo ea pele ea tharollo ka bobeli, e leng V2 500 mL. 800 ml 1300 mL. Ho fetola boleng ho equation ea dilution, le ho hlophisa bocha ho rarolla bakeng sa M2 ho fana ka: M2 M1V1V2 Kakaretso ea moles oa solute litharollong tse peli ke: Palo ea moles ka tharollo 1 M1 V1 0.3 M 0.5 L 0.15 mol Palo ea li-moles ka tharollo 2 M1 V1 0.1 M 0.8 L 0.08 mol Li-moles tsa solute kakaretso 0.15 mol 0.08 mol 0.23 mol Joale ha re nkeng sebaka sa foromo e kaholimo, M2 mol of soluteV2 M2 0.23 mol1.3L 0.177 M hoo e ka bang Kahoo, sekhahla seo ntho e hlapolloang ka sona ha 500 mL ea 0.3 M tharollo e eketsoa. ho 800 ml ea tharollo ea 0.1 M e ka ba 0.177 M. 