<prompt> Fumana equation ea lehlaseli le fetang 1, 3 le perpendicular moleng y 4x 9.nan  <response>: Instruction in English: Find the equation of the ray passing through 1, 3 and perpendicular to the line y 4x 9. . Response in English: A line that is perpendicular to another line has a slope that is the negative reciprocal of the original lines slope. The given line has a slope of 4, so the slope of the line that is perpendicular to it would be -14. Using the point-slope form of a line, we can find that the equation of the line that passes through 1, 3 with a slope of -14 is:y - y1 mx - x1y - 3 -14x - -1y - 3 -14x 1y - 3 -14x - 14y -14x - 14 3y -14x 114. This is the equation of the line perpendicular to y 4x 9 and passing through the point -1, 3. Since we are looking for the equation of the ray, we must establish in which direction it extends. A ray extends infinitely in one direction given by its second point. Since no second point is provided, it is implied that this ray extends in the direction of the positive x-axis. . Response in Sesotho: Mothalo o shebaneng le mola o mong o na le moepa oo e leng moepa o mobe oa moepa oa pele. Mohala o fanoeng o na le moepa oa 4, kahoo moepa oa mola o ka bang ka ho toba ho oona e ka ba -14. Ka ho sebelisa sebopeho sa moepa oa ntlha, re ka fumana hore equation ea mola o fetang 1, 3 o nang le moepa oa -14 ke: y - y1 mx - x1 y - 3 -14x - -1 y - 3 -14x 1 y - 3 -14x - 14 y -14x - 14 3 y -14x 114. Ena ke equation ea mola perpendicular ho y 4x 9 le ho feta ntlha -1, 3. Kaha re batla equation ea ray, re tlameha ho fumana hore na e fetela ka nqa efe. Lehlaseli le fetela ka ho sa feleng ka lehlakoreng le leng le fanoeng ke ntlha ea lona ea bobeli. Kaha ha ho ntlha ea bobeli e fanoeng, ho boleloa hore lehlaseli lena le fetela ka lehlakoreng la x-axis e nepahetseng. 