<prompt> Ka lintlha tse fanoeng tsa data, khetholla equation bakeng sa polynomial.Lintlha tsa lintlha: -2, 3, -1, 1, 3,-4, 4,-1  <response>: Instruction in English: With the given data points, identify the equation for the polynomial. . Response in English: A polynomial of degree n can be uniquely identified by providing n1 distinct points lying on it. Here, we are given four points, so let us assume that the polynomial is of degree 3.px ax3 bx2 cx dSubstituting -2,3 we get 3 -8a 4b - 2c d --- 1Substituting -1,1 we get 1 -a b - c d ---2Substituting 3,-4 we get -4 27a 9b 3c d --- 3Substituting 4,-1 we get -1 64a 16b 4c d --- 4Solving these equations simultaneously, we get a 2, b -1, c -11, and d 7Hence the equation for the polynomial is : px 2x3 - x2 - 11x 7. . Response in Sesotho: Polynomial of degree n e ka khetholloa ka mokhoa o ikhethileng ka ho fana ka n1 lintlha tse ikhethileng tse larileng ho eona. Mona, re fuoa lintlha tse nè, kahoo a re nke hore polynomial ke tekanyo ea 3. px ax3 bx2 cx d Substituting -2,3 re fumana 3 -8a 4b - 2c d --- 1 Ho nkela sebaka -1,1 re fumana 1 -a b - c d ---2 Ho fetola 3,-4 re fumana -4 27a 9b 3c d --- 3 Ho fetola 4,-1 re fumana -1 64a 16b 4c d --- 4 Ho rarolla lipalo tsena ka nako e le nngwe, re fumana a 2, b -1, c -11, le d 7 Kahoo equation bakeng sa polynomial ke: px 2x3 - x2 - 11x 7. 