<prompt> Fumana tharollo ea equation ax3 bx2 cx d 0a 1, b -3, c -3, d -1  <response>: Instruction in English: Find the solution to the equation ax3 bx2 cx d 0 . Response in English: The given equation is x3 - 3x2 - 3x -1 0. One way to solve this cubic equation is by using the Rational Root Theorem which states that any possible rational root of a polynomial equation must be a factor of the constant term divided by a factor of the leading coefficient.In this case, the possible rational roots are 1. By testing each of these values, we find that x -1 is a root of the polynomial.We can use long division or synthetic division to divide the cubic polynomial by x1 and find that the result is x2 - 4x 1.Now, we have the equation x1x2 - 4x 1 0. To find the other two roots, we solve the quadratic equation x2 - 4x 1 0. Using the quadratic formula, we find that the other two roots are 4 16-42 2 3.So, the roots of the equation x3 - 3x2 - 3x -1 0 are -1, 2 3, and 2 -3. . Response in Sesotho: Equation e fanoeng ke x3 - 3x2 - 3x -1 0. Tsela e ngoe ea ho rarolla tekano ena ea li-cubic equation ke ka ho sebelisa Rational Root Theorem e bolelang hore motso leha e le ofe o ka khonehang oa polynomial equation e tlameha ho ba ntlha ea kamehla. lentsoe le arotsoeng ka ntlha ea coefficient e etellang pele. Tabeng ena, metso e ka khonehang e utloahalang ke 1. Ka ho hlahloba e ngoe le e ngoe ea litekanyetso tsena, re fumana hore x -1 ke motso oa polynomial. Re ka sebelisa karohano e telele kapa karohano ea maiketsetso ho arola cubic polynomial ka x1 mme ra fumana hore sephetho ke x2 - 4x 1. Joale, re na le equation x1x2 - 4x 1 0. Ho fumana metso e meng e meli, re rarolla quadratic equation x2 - 4x 1 0. Re sebelisa mokhoa oa quadratic, re fumana hore metso e meng e meli ke 4 16-4 2 2 3. Kahoo, metso ea equation x3 - 3x2 - 3x -1 0 ke -1, 2 3, le 2 -3. 