<prompt> Etsa algorithm ho rarolla bothata bo latelang: Ho latela palo e kholo ea palo e kholo, fumana lipara tsohle tseo kakaretso ea tsona e arolang ka 3.nan  <response>: Instruction in English: Make an algorithm to solve the following problem: Given an array of positive integers, find all the pairs whose sum is divisible by 3. . Response in English: Here is an algorithm to solve the problem:1. Initialize an empty list result to store the pairs whose sum is divisible by 3.2. Loop over the array from index i 0 to i length of array - 2: - Loop over the array from index j i 1 to j length of array - 1: - Calculate the sum of array elements at index i and j: sum arrayi arrayj - Check if this sum is divisible by 3 by calculating sum 3: - If sum 3 equals to 0, then append arrayi and arrayj as a tuple to the result list3. Return the result list . Response in Sesotho: Mona ke algorithm ho rarolla bothata: 1. Qala lenane le se nang letho sephetho ho boloka lipara tseo kakaretso ea tsona e aroloang ka 3. 2. Lula ka holima sehlopha ho tloha ho index i 0 ho ea i bolelele ba lethathamo - 2: - Lula ka holima lethathamo ho tloha ho index j i 1 ho j bolelele ba lethathamo - 1: - Bala kakaretso ea likarolo ho index i le j: sum array i arrayj - Sheba hore na kakaretso ena e aroloa ka 3 ka ho bala palo 3: - Haeba palo 3 e lekana le 0, joale hlomathisa lethathamoi le tlhophisoj joalo ka tuple lenaneng la sephetho 3. Khutlisetsa lenane la sephetho 