<prompt> Etsa qeto ea nako ea inertia ea sebopeho se latelang.Sebopeho: Rectangle bophara 5 m le bolelele 7 m  <response>: Instruction in English: Determine the moment of inertia of the following shape. . Response in English: To calculate the moment of inertia of a rectangle with given width b and length h about an axis passing through its center of mass and perpendicular to its plane, we can use the formula:I b h3 12Substituting the given values of width and length into the formula, we get:I 5 73 12I 5 343 12I 1715 12I 142.91667 kg m2Hence, the moment of inertia of the given rectangle shape about an axis passing through its center of mass and perpendicular to its plane is approx. 142.92 kg m2. . Response in Sesotho: Ho bala nako ea inertia ea khutlonnetsepa e nang le bophara bo fanoeng b le bolelele h mabapi le axis e fetang bohareng ba boima le perpendicular ho sefofane sa eona, re ka sebelisa foromo: I b h3 12 Ho beha maemo a fanoeng a bophara le bolelele ho foromo, re fumana: I 5 73 12 I 5 343 12 I 1715 12 I 142.91667 kg m2 Ka hona, nako ea inertia ea sebopeho se fanoeng sa khutlonnetsepa e mabapi le axis e fetang bohareng ba boima le perpendicular ho sefofane sa eona ke hoo e ka bang. 142.92 likhilograma m2. 