<prompt> Fetola moenjiniere khoutu e latelang ho etsa hore tlhahiso e be odd.haeba x 2 0 hatisaesita  <response>: Instruction in English: Reverse engineer the following code to make the output odd. . Response in English: The code provided checks if the remainder of a variable x when divided by 2 is equal to zero. If it is, it prints the word even to the console. To reverse engineer this code and change the output to odd, we can change the condition inside the if statement so that it checks if the remainder is not equal to zero. Heres one way to do it:pythonif x 2 ! 0: printoddWhen the condition inside the if statement evaluates to True, meaning that the remainder of the variable x when divided by 2 is not 0, the code inside the if block will output odd. . Response in Sesotho: Khouto e fanoeng e lekola hore na karolo e setseng ea x ha e arotsoe ka 2 e lekana le lefela. Haeba ho joalo, e hatisa lentsoe esita ho console. Ho fetola moenjiniere khoutu ena le ho fetola tlhahiso ho odd, re ka fetola boemo ka hare ho polelo ea if e le hore e hlahlobe hore na se setseng ha se lekane le zero. Tsela e ngoe ea ho e etsa ke ena: python haeba x 2 ! 0: printodd Ha boemo bo ka hare ho polelo ea if bo lekola ho Nete, ho bolelang hore karolo e setseng e feto-fetohang x ha e arotsoe ka 2 ha se 0, khoutu e ka hare ho if block e tla hlahisa odd. 