<prompt> ka rarolla equation ee joang: 4x 5y 28nan  <response>: Instruction in English: How would you solve this equation: 4x 5y 28 . Response in English: The equation 4x 5y 28 is a linear equation with two variables x and y. There are multiple solutions for this equation since it represents a straight line in the xy-plane. To solve for y in terms of x, we can rearrange the equation and isolate the variable y: First, we can subtract 4x from both sides to get: 5y -4x 28 Next, we can divide both sides by 5 to get the value of y in terms of x: y -45x 285 This is the slope-intercept form of the equation of the line, where the slope is -45 and the y-intercept is 285. So, for any given value of x, we can find the corresponding value of y using this equation. Alternatively, if we have the value of y, we can solve for the corresponding value of x. For example, if x 2, then y -452 285 205 4. So one solution to the equation is x, y 2, 4. Similarly, if y 0, then 0 -45x 285, which implies that x 28554 7. Thus, another solution to the equation is x, y 7, 0. . Response in Sesotho: Equation 4x 5y 28 ke palo e lekanang le mefuta e meli ea x le y. Ho na le litharollo tse ngata bakeng sa equation ena kaha e emela mola o otlolohileng ho xy-plane. Ho rarolla y ho latela x, re ka hlophisa equation hape mme ra arola phapang y: Taba ea pele, re ka tlosa 4x mahlakoreng ka bobeli ho fumana: 5y -4x 28 E latelang, re ka arola mahlakore ka bobeli ka 5 ho fumana boleng ba y ho latela x: y -45x 285 Ona ke mokhoa oa ho thibela letsoapo oa equation ea mola, moo moepa e leng -45 le y-intercept. ke 285. Kahoo, bakeng sa boleng bofe kapa bofe ba x, re ka fumana boleng bo lumellanang ba y re sebelisa equation ena. Ntle le moo, haeba re na le boleng ba y, re ka rarolla bakeng sa boleng bo tsamaellanang ba x. Ka mohlala, haeba x 2, joale y -45 2 285 205 4. Kahoo tharollo e le ngoe ea equation ke x, y 2, 4 . Ka ho tšoanang, haeba y 0, joale 0 -45x 285, e leng se bolelang hore x 28554 7. Kahoo, tharollo e ngoe ea equation ke x, y 7, 0. 