<prompt> Fumana pherimitha ea kgutlotharo ABC moo A e leng ho 1,1, B ho 5,6 le C ho 9,2.A1,1, B5,6 le C9,2  <response>: Instruction in English: Determine the perimeter of triangle ABC where A is at 1,1, B at 5,6 and C at 9,2. . Response in English: To find the perimeter of triangle ABC, we need to find the length of each side and add them up. The length of a side can be found using the distance formula: the distance between two points x1, y1 and x2, y2 is given by the square root of x2-x12 y2-y12.Using this formula, we can find the lengths of the three sides of triangle ABC:AB 5-12 6-12 16 25 41BC 9-52 2-62 16 16 32CA 9-12 2-12 64 1 65Therefore, the perimeter of triangle ABC is AB BC CA 41 32 65 22.34. . Response in Sesotho: Ho fumana pherimitha ea kgutlotharo ABC, re hloka ho fumana bolelele ba lehlakore ka leng le ho li eketsa. Bolelele ba lehlakore bo ka fumanoa ho sebelisoa mokhoa oa sebaka: sebaka se pakeng tsa lintlha tse peli x1, y1 le x2 , y2 e fanoe ka motso oa lisekoere oa x2-x12 y 2-y12. Ka ho sebelisa foromo ena, re ka fumana bolelele ba mahlakore a mararo a kgutlotharo ABC: AB 5-12 6-12 16 25 41 BC 9-52 2-62 16 16 32 CA 9-12 2-12 64 1 65 Ka hona, pherimithara ya kgutlotharo ABC ke AB BC CA 41 32 65 22.34. 