<prompt> Fumana boholo ba mosebetsi y x2 - 5x 6nan  <response>: Instruction in English: Find the maximum of the function y x2 - 5x 6 . Response in English: To find the maximum value of the function y x2 - 5x 6, we need to complete the square for the function:y x2 - 5x 6y x2 - 5x 6.25 6 - 6.25y x - 2.52 - 0.25Because the squared term, x - 2.52, is always non-negative i.e. it is either 0 or positive, the maximum value of the function occurs when this term is equal to zero.When x - 2.52 0, we have x 2.5.Substituting this value of x into the original equation, we find that the maximum value of the function isy 2.52 - 52.5 6 -0.25.Therefore, the maximum value of the function y x2 - 5x 6 is -0.25, and it occurs at x 2.5. . Response in Sesotho: Ho fumana boleng bo phahameng ba tsebetso y x2 - 5x 6, re hloka ho tlatsa sekoere bakeng sa mosebetsi: y x2 - 5x 6 y x2 - 5x 6.25 6 - 6.25 y x - 2.52 - 0.25 Hobane lereho la sekwere, x - 2.52, kamehla ha le mpe ke hore ke 0 kapa positive, boholo ba boleng ba tshebetso bo etsahala ha sena. lentsoe le lekana le zero. Ha x - 2.52 0, re na le x 2.5. Ho kenya boleng bona ba x ho equation ea pele, re fumana hore boholo ba boleng ba mosebetsi ke y 2.5 2 - 5 2.5 6 -0.25. Ka hona, boleng bo phahameng ba mosebetsi y x 2 - 5x 6 ke -0.25, me bo etsahala ho x 2.5. 