<prompt> Bala molality ea tharollo.Tharollo e na le 5.0 moles ea ethylene glycol C2H6O2 e qhibilihisitsoeng ka 500ml ea metsi.  <response>: Instruction in English: Calculate the molality of a solution. . Response in English: First, we must convert the volume of water in the solution from milliliters to kilograms. Since the density of water at room temperature is approximately 1 gml, 500 ml of water is equivalent to 500 grams of water. This further converts to 0.5 kilograms of water.Molality is defined as the number of moles of solute per kilogram of solvent. In this case, the solute is ethylene glycol and the solvent is water.The solution has 5.0 moles of ethylene glycol dissolved in 0.5 kilograms of water. To calculate the molality, we divide the number of moles of solute by the mass of the solvent in kilograms:Molality moles of solutekilograms of solventMolality 5.0 moles0.5 kgMolality 10 molkgTherefore, the molality of this solution is 10 molkg. . Response in Sesotho: Ntlha ea pele, re tlameha ho fetola molumo oa metsi ka tharollo ho tloha ho milliliters ho ea ho likhilograma. Kaha boima ba metsi ka mocheso oa kamore ke hoo e ka bang 1 gml, 500 ml ea metsi e lekana le ligrama tse 500 tsa metsi. Sena se boetse se fetolela ho 0.5 likhilograma tsa metsi. Molality e hlalosoa e le palo ea moles ea solute ka kilogram ea solvent. Tabeng ena, solute ke ethylene glycol le solvent ke metsi. Tharollo e na le 5.0 moles ea ethylene glycol e qhibilihisitsoeng ka likhilograma tse 0.5 tsa metsi. Ho bala molality, re arola palo ea moles ea solute ka boima ba solvent ka likhilograma: Molality moles of solute kilogram ea solvent Molality 5.0 moles 0.5 kg Molality 10 mol kg Ka hona, molality ea tharollo ena ke 10 mol kg. 