<prompt> Bapisa le ho bapisa lintlha tse peli tse fanoeng.Karolo ea 1: Thempereichara ke 82 degrees Fahrenheit ka ntle. Karolo ea 2: Mocheso ke likhato tse 28 tsa Celsius ka ntle.  <response>: Instruction in English: Compare and contrast the given two pieces of data. . Response in English: Piece 1 indicates that the temperature outside is 82 degrees Fahrenheit. Piece 2, on the other hand, reports the temperature outside as 28 degrees Celsius. The two pieces of data use different temperature scales: Fahrenheit and Celsius. When we convert 28 degrees Celsius to Fahrenheit using the formula F C × 95 32, we find that it is equal to 82.4 degrees Fahrenheit. This shows that the temperature being described in the two pieces of data is similar, but there is a slight difference of 0.4 degrees. So, both pieces of data are conveying that its relatively warm outside, but they use different units of measurement to do so. . Response in Sesotho: Karolo ea 1 e bontša hore mocheso ka ntle ke likhato tse 82 tsa Fahrenheit. Ka lehlakoreng le leng, karolo ea 2 e tlaleha mocheso ka ntle e le likhato tse 28 tsa Celsius. Likarolo tse peli tsa data li sebelisa sekala se fapaneng sa mocheso: Fahrenheit le Celsius. Ha re fetola likhato tse 28 tsa Celsius ho Fahrenheit re sebelisa foromo F C × 95 32, re fumana hore e lekana le likhato tse 82,4 tsa Fahrenheit. Sena se bontša hore mocheso o hlalosoang likarolong tse peli tsa data o tšoana, empa ho na le phapang e fokolang ea likhato tse 0,4. Kahoo, likarolo tsena ka bobeli tsa data li fana ka maikutlo a hore ho futhumetse kantle, empa li sebelisa litekanyo tse fapaneng ho etsa joalo. 