<prompt> Fumana liphoso khoutu e latelang me u li lokise.haeba x y haeba x y y 0; tse ling x 0;  <response>: Instruction in English: Find the errors in the following code and fix them. . Response in English: There is a logical error in the code. The inner if condition x y can never be true because it is nested inside an outer if condition x y. Therefore, the inner condition x y will never be executed.Here is an example of how to fix this by adjusting the logic of the conditional statements:if x y y 0; else if x y x 0; else handle the case where x yIn this fixed version, the first if condition checks if x is greater than y. If that is true, y is set to 0. If x is not greater than y, the code moves on to the else if condition, which checks if x is less than y. If that is true, x is set to 0. Finally, if neither of those conditions is true, it is concluded that x is equal to y, and the code within the else block is executed to handle this case.Additionally, there should be proper indentation and formatting for the code for better readability. . Response in Sesotho: Ho na le phoso e utloahalang khoutung. E ka hare haeba boemo x y e ke ke ea e-ba nete hobane e lutse ka hare ho bokantle haeba boemo ba x y. Ka hona, boemo ba kahare x y bo ke ke ba phethisoa. Mona ke mohlala oa mokhoa oa ho lokisa sena ka ho lokisa logic ea lipolelo tsa maemo: haeba x y y 0; ho seng joalo haeba x 