<prompt> Bakeng sa equation ea quadratic e ka tlase, rarolla bakeng sa x.2x2 7x - 5 0  <response>: Instruction in English: For the quadratic equation below, solve for x. . Response in English: The quadratic equation, 2x2 7x - 5 0, can be solved using the quadratic formula. The quadratic formula states that for an equation in the form of ax2 bx c 0, the solutions for x can be found using the formula: x -b b2-4ac 2a. In this equation, a 2, b 7, and c -5. Plugging these values into the quadratic formula, we get:x -7 72-42-5 22x -7 49 40 4x -7 89 4Therefore, the two solutions for x are:x -7 89 4 0.64x -7 - 89 4 -3.89So, the quadratic equation 2x2 7x - 5 0 has two possible solutions for x, approximately equal to 0.64 and -3.89. . Response in Sesotho: quadratic equation, 2x2 7x - 5 0, e ka rarolloa ka mokhoa oa quadratic. Foromo ea quadratic e bolela hore bakeng sa equation ka mokhoa oa selepe2 bx c 0, tharollo ea x e ka fumanoa ho sebelisoa foromo: x -b b2-4ac 2a. Tekanong ena, a 2, b 7, le c -5. Ho kenya litekanyetso tsena ka mokhoa oa quadratic, re fumana: x -7 72-42-5 22 x -7 49 40 4 x -7 89 4 Ka hona, litharollo tse peli tsa x ke: x -7 89 4 0.64 x -7 - 89 4 -3.89 Kahoo, quadratic equation 2x2 7x - 5 0 e na le mekhoa e meli e ka khonehang bakeng sa x, e batlang e lekana le 0.64 le -3.89. 