<prompt> Fumana equation ea mola o fetang lintlheng 4,7 le 6,11.nan  <response>: Instruction in English: Find the equation of the line that passes through the points 4,7 and 6,11. . Response in English: We can find the equation of a line that passes through two points by finding its slope and y-intercept.First, lets find the slope of the line using the formula: m y2-y1x2-x1, where x1,y1 and x2,y2 are the given points. Substituting the values of the points, we have:m 11-76-4m 42m 2Now that we have the slope, we can use the point-slope form of a line to find the equation. The point-slope form of a line is given by: y - y1 mx-x1, where m is the slope and x1,y1 is one of the given points.Substituting the values for m and x1,y1 in the equation, we have:y - 7 2x - 4y - 7 2x - 8y 2x - 8 7y 2x - 1Thus, the equation of the line that passes through the points 4,7 and 6,11 is y 2x - 1. . Response in Sesotho: Re ka fumana equation ea mola o fetang lintlheng tse peli ka ho fumana moepa le y-intercept. Taba ea pele, a re fumaneng moepa oa mola re sebelisa foromo: m y2-y1x2-x1, moo x1,y1 le x2,y2 e leng lintlha tse fanoeng. Ho fetola boleng ba lintlha, re na le: m 11-76-4 m 42 m 2 Kaha joale re na le moepa, re ka sebelisa mokhoa oa moepa oa mola ho ea. fumana equation. Mokhoa oa ntlha-moepa oa mola o fanoa ke: y - y1 mx-x1, moo m e leng letsoapo le x1,y1 ke e ngoe ea lintlha tse fanoeng. Ho fetola boleng ba m le x1,y1 ho equation, re na le: y - 7 2x - 4 y - 7 2x - 8 y 2x - 8 7 y 2x - 1 Kahoo, equation ea mola o fetang lintlheng 4,7 le 6,11 ke y 2x - 1. 