<prompt> Fumana theta lipakeng tsa li-vector tse peli 6i2j le -3i6jnan  <response>: Instruction in English: Find the theta between the two vectors 6i2j and -3i6j . Response in English: Sure! To find the angle between two vectors, we can use the formula θ arccosuv u v . Where arccos is the inverse cosine, uv represents the dot product between vectors u and v, and u is the magnitude of the vector u. Lets say vector u 6,2 and vector v-3,6, The dot product between u and v uv 6-3 26 -12.The magnitude of u is u sqrt62 22 sqrt364 sqrt402sqrt10.The magnitude of v is v sqrt-32 62 sqrt936 3sqrt5.Substituting these values into the formula, we get θ arccosuv u v arccos -122sqrt103sqrt5 arccos-1arccos-1 is equal to π radians, or 180 degrees.Therefore, the angle between the two vectors is 180 degrees. . Response in Sesotho: Ehlile! Ho fumana angle pakeng tsa li-vector tse peli, re ka sebelisa foromo θ arccosuv u v . Moo arccos e leng cosine e fapaneng, uv e emela sehlahisoa sa letheba lipakeng tsa li-vector u le v, le u ke boholo ba vector u. Ha re re vector u 6,2 le vector v-3,6, Sehlahisoa sa matheba pakeng tsa u le v uv 6-3 26 -12. Boholo ba hau ke u sqrt62 22 sqrt364 sqrt402sqrt10. Boholo ba v ke v sqrt-32 62 sqrt936 3sqrt5. Ha re kenya litekanyetso tsena molemong, re fumana θ arccosuv u v arccos -122sqrt103sqrt 5 arccos-1 arccos-1 e lekana le π radians, kapa likhato tse 180. Ka hona, angle pakeng tsa li-vector tse peli ke likhato tse 180. 