<prompt> Fumana equation ea lipalo bakeng sa mola o otlolohileng.nan  <response>: Instruction in English: Derive the mathematical equation for a straight line. . Response in English: A straight line is described by the linear equation of the form y mx b, where m is the slope of the line, and b is its y-intercept. The slope of a line is defined as the ratio of the rise the vertical change to the run the horizontal change between any two points of the line. The equation can be derived by finding the slope and y-intercept of the line.Lets assume that we have two points on the line with coordinates x1, y1 and x2, y2. The slope m of the line is given by:m y2 - y1 x2 - x1Once the value of m is calculated, the y-intercept b can be found by substituting the ,x and y values of any of the two points into the equation y mx b and solving for b. For example, using the point x1, y1 we get:b y1 - mx1The final equation of the line is, therefore:y mx b mx - x1 y1where m y2 - y1 x2 - x1 and b y1 - mx1. This is the equation of a straight line passing through the points x1, y1 and x2, y2. . Response in Sesotho: Mola o otlolohileng o hlalosoa ka mokhoa oa equation oa mola oa sebopeho y mx b, moo m e leng moepa oa mola, me b e le y-e khaoletsang. Moepa oa mola o hlalosoa e le karo-karolelano ea phahamiso phetoho e emeng ho run phetoho e tšekaletseng lipakeng tsa lintlha tse peli tsa mola. Equation e ka fumanoa ka ho fumana moepa le y-intercept ea mola. Ha re nke hore re na le lintlha tse peli moleng o nang le likhokahano x1, y1 le x2, y2. Moepa m oa mola o fanoe ke: m y2 - y1 x2 - x1 Hang ha boleng ba m bo baloa, khakanyo ea y b e ka fumanoa ka ho beha ,x le y lintlha tsa leha e le efe ea lintlha tse peli equation y mx b le ho rarolla bakeng sa b. Mohlala, ho sebelisa ntlha x1, y1 eo re e fumanang: b y1 - mx1 Tekano ea ho qetela ea mola ke: y mx b mx - x1 y1 moo m y2 - y1 x2 - x1 le b y1 - mx1. Ena ke equation ea mola o otlolohileng o fetang lintlheng x1, y1 le x2, y2. 