<prompt> Fumana boleng bo tlase bakeng sa tšebetso e latelang6x2 - 4x - 8  <response>: Instruction in English: Find the lowest value for the following function . Response in English: The function 6x2 - 4x - 8 is a quadratic equation that can be written in the form of ax2 bx c, where a 6, b -4 and c -8. To find the lowest value, also known as the minimum value, we can use a formula derived from completing the square: the minimum value of ax2 bx c is c - b2 4a. Plugging in the values for a, b and c, we get:minimum value -8 - -42 4 6Solving this we get:minimum value -8 - 1624minimum value -8 - 23Hence, the minimum value of the quadratic function 6x2 - 4x - 8 is -263 or approximately -8.667. . Response in Sesotho: Mosebetsi 6x2 - 4x - 8 ke quadratic equation e ka ngoloang ka mokhoa oa selepe2 bx c, moo a 6, b -4 le c -8. Ho fumana boleng bo tlaase ka ho fetisisa, bo tsejoang hape e le bonyane ba boleng, re ka sebelisa foromo e nkiloeng ho tlatsa sekwere: boleng bo tlase ba ax2 bx c ke c - b2 4a. Ho kenya litekanyetso tsa a, b le c, re fumana: bonyane ba boleng -8 - -4 2 4 6 Ho rarolla sena re fumana: boleng ba bonyane -8 - 1624 bonyane ba boleng - 8 - 23 Kahoo, boleng ba bonyane ba mosebetsi oa quadratic 6x2 - 4x - 8 ke -263 kapa hoo e ka bang -8.667. 