<prompt> Bala sebaka sa kgutlotharo ka dinomoro 3,4, 5,6, 7,8nan  <response>: Instruction in English: Compute the area of a triangle with the vertices 3,4, 5,6, 7,8 . Response in English: To find the area of a triangle with the given vertices, we can use the determinant formula. Let x1,y1, x2,y2, and x3,y3 be the coordinates of the three vertices of the triangle. The area of the triangle is given by the formula:Area abs x1y2-y3 x2y3-y1 x3y1-y2 2 Substituting the values of the given coordinates 3,4, 5,6, 7,8 into the formula, we getx1 3, y1 4, x2 5, y2 6, x3 7, y3 8Area abs 36-8 58-4 74-6 2 Area abs -6 20 -14 2 abs 0 0So, the area of the triangle with vertices 3,4, 5,6, 7,8 is 0 square units. This means that the three points are collinear and do not form a triangle. . Response in Sesotho: Ho fumana sebaka sa khutlo-tharo ka li-vertices tse fanoeng, re ka sebelisa foromo e khethollang. E re x1,y1, x2,y2, le x3,y3 e be likhokahanyo tsa lirotho tse tharo tsa khutlotharo. Sebaka sa kgutlotharo se fanoe ka foromo: Sebaka abs x1y2-y3 x2y3-y1 x3y1-y2 2 Ho fetola litekanyetso tsa lihlopha tse fanoeng. 3,4, 5,6, 7,8 ka foromo, re fumana x1 3, y1 4, x2 5, y2 6, x3 7, y3 8 Sebaka abs 36-8 58-4 74-6 2 Sebaka abs -6 20 -14 2 abs 0 0 Ka hona, sebaka sa khutlo-tharo e nang le li-vertices 3,4, 5,6, 7,8 ke 0 square units. Sena se bolela hore lintlha tse tharo ke li-collinear me ha li etse kgutlotharo. 