<prompt> Etsa palo ea lipalo e emelang boemo bo fanoengJohn a ka qeta projeke ka lihora tse 3 mme Mary a ka qeta mosebetsi o tšoanang ka lihora tse 4.  <response>: Instruction in English: Create a mathematical equation that represents the given situation . Response in English: Lets let x represent the portion of the project that is completed. If John can finish a project in 3 hours, then in 1 hour he can finish x3 of the project. Similarly, if Mary can finish a project in 4 hours, then in 1 hour she can finish x4 of the project. Working together, John and Mary can finish the project in 1 hour by completing x3 x4 of the project. This can be simplified by finding a common denominator: 4x 3x12 x. So, together they can complete 712 of the project in 1 hour.The final equation would be: t 12 7, where t represents the time in hours it would take for John and Mary to complete the project together. . Response in Sesotho: Ha re lumelle x ho emela karolo ea morero o phethetsoeng. Haeba John a ka qeta morero ka lihora tse 3, joale ka hora e le 1 a ka qeta x3 ea morero. Ka mokhoa o tsoanang, haeba Mary a ka qeta morero ka lihora tse 4, joale ka hora e le ngoe a ka qeta x4 ea morero. Ka ho sebetsa moho, John le Mary ba ka qeta morero ka hora e le 1 ka ho qeta x3 x4 ea morero. Sena se ka nolofalloa ka ho fumana mofuta o tšoanang: 4x 3x12 x. Kahoo, hammoho ba ka qeta 712 ea morero ka hora e le ngoe. Equation ea ho qetela e tla ba: t 12 7, moo t e emelang nako ka lihora e neng e tla nka hore John le Mary ba phethe mosebetsi hammoho. 