<prompt> Hlalosa tsela eo rokete e tsamaeang ka eona ho latela lintlha tse latelang.Rokete e ile ea qalisoa ka ho otloloha ka lebelo la pele la 120 ms.  <response>: Instruction in English: Describe the trajectory of a rocket given the following information. . Response in English: The trajectory of a rocket launched vertically with an initial velocity of 120 ms can be described using the motion equations for uniformly accelerated linear motion. The initial velocity, denoted by v0, is 120 ms, and the acceleration, denoted by a, is equal to the gravitational acceleration of -9.81 ms2, which is directed downward. The velocity of the rocket at any moment of time t is given by the equation v v0 at, where v is the velocity at time t. With the values for v0 and a, we have v 120 ms - 9.81 ms2 t.The position y of the rocket at any moment of time t is given by the equation y y0 v0t 0.5at2. Assuming the rocket is launched from the ground, the initial position y0 of the rocket is zero. Using the values for v0, a, and y0, we have y 120 ms t - 0.5 9.81 ms2 t2.In conclusion, the trajectory of the rocket can be described as a parabolic path, where its velocity decreases as it gains altitude until reaching a maximum height, after which it starts falling back to the ground with increasing velocity. . Response in Sesotho: Tsela ea rokete e phahamisitsoeng ka ho otloloha ka lebelo la pele la 120 ms e ka hlalosoa ho sebelisoa li-equation tsa motsamao bakeng sa motsamao o potlakisang ka mokhoa o tšoanang. Lebelo la pele, le bontšitsoeng ke v0, ke 120 m s, me ho potlakisa, ho boleloang ke a, ho lekana le ho potlakisa ha khoheli -9.81 m s2, e lebisitsoeng ho ea tlaase. Lebelo la rokete ka nako efe kapa efe ea nako t e fanoa ke equation v v0 ho, moo v e leng lebelo ka nako t. Ka litekanyetso tsa v0 le a, re na le v 120 ms - 9.81 ms2 t. Boemo y ba rokete ka nako efe kapa efe ea nako t bo fanoa ke equation y y0 v0t 0.5at2. Ho nka hore rokete e qalisoa ho tloha fatše, boemo ba pele y0 ba rokete ke zero. Ho sebelisa litekanyetso tsa v0, a, le y0, re na le y 120 ms t - 0.5 9.81 ms2 t2. Qetellong, tsela ea rokete e ka hlalosoa e le tsela ea parabolic, moo lebelo la eona le fokotsehang ha e ntse e phahama ho fihlela e fihla bophahamong bo phahameng, ka mora moo e qala ho oela fatše ka lebelo le ntseng le eketseha. 