<prompt> Etsa equation ea selikalikoe se nang le radius ea 5 le setsi sa eona ho 1, -2.nan  <response>: Instruction in English: Formulate the equation of a circle that has a radius of 5 with its center at 1, -2. . Response in English: The standard form equation of a circle is given by x - h2 y - k2 r2, where h, k are the coordinates of the center of the circle and r is the radius. Given the center of the circle 1, -2 and a radius of 5, we can plug these values into the equation to get:x - 12 y 22 52Simplifying this equation gives us:x - 12 y 22 25. . Response in Sesotho: Mokhoa o tloaelehileng oa equation oa selikalikoe o fanoa ke x - h2 y - k2 r2, moo h, k e leng lihokahanyo tsa bohareng ba selikalikoe le r ke radius. . Ha ho fanoe ka setsi sa selikalikoe 1, -2 le radius ea 5, re ka kopanya litekanyetso tsena ho equation ho fumana: x - 12 y 22 52 Ho nolofatsa sena. equation e re fa: x - 12 y 22 25. 