<prompt> Assuming ideal conditions, determine the maximum speed of a locomotive given it has a mass of 25 tons, a power rating of 3,000 kW and friction force of 1,500 kN.mass 25 tons, power rating 3000 kW, friction force 1,500 kN  <response>: Under ideal conditions, we can use the formula for power of a locomotive to determine its maximum speed. The power can be defined as force multiplied by velocity or P F x v. This means, we can determine the velocity maximum speed if we know the power and the force i.e. v P F.Given the power rating of the locomotive is 3000 kW and the friction force it must overcome is 1,500 kN, we can calculate the maximum speed as follows:v P F 3000 kW 1500 kN 2 msTherefore, the maximum speed of the locomotive, given its power rating and friction force, is 2 meters per second ms. 