<prompt> Fana ka mohlala oa mokhoa oa ho rarolla equation ena.2x 5 13  <response>: Instruction in English: Give an example of how to solve this equation. . Response in English: An example of how to solve the given equation, 2x 5 13, is demonstrated below:Step 1: Start by getting rid of the constant term 5 on the left side. To do this, subtract 5 from both sides of the equation so that you are keeping the equation balanced. 2x 5 13 2x 5 - 5 13 - 5 2x 8Step 2: Next, you need to isolate the variable x on the left side. To do this, divide both sides by the coefficient of x which is 2, to leave x by itself on the left side. 2x 8 2x2 82 x 4The solution to the equation 2x 5 13 is x 4. . Response in Sesotho: Mohlala oa mokhoa oa ho rarolla equation e fanoeng, 2x 5 13, e bontšitsoe ka tlase: Mohato oa 1: Qala ka ho tlosa lentsoe le sa khaotseng 5 ka lehlakoreng le letšehali. Ho etsa sena, tlosa 5 mahlakoreng ka bobeli a equation e le hore u boloke palo e leka-lekaneng. 2x 5 13 2x 5 - 5 13 - 5 2x 8 Mohato oa 2: Ka mora moo, o hloka ho khetholla phapang x ka lehlakoreng le letšehali. Ho etsa sena, arola mahlakore ka bobeli ka coefficient ea x e leng 2, ho siea x ka boeona ka lehlakoreng le letšehali. 2x 8 2x2 82 x 4 Tharollo ea equation 2x 5 13 ke x 4. 