<prompt> Ho latela khoutu ena ea C, tlhahiso e lebelletsoeng ke efe?kenyeletsa int main int i 1; bakeng sa i 1; ke 5; i haeba i2 0 printfdn, i; khefu; kgutlisetsa 0;  <response>: Instruction in English: Given this C code, what is the expected output? . Response in English: The expected output from this code is the printed number 2.This is because the code creates a for loop that iterates over the values of i from 1 to 5. When the value of i is even, the remainder of i when divided by 2 i.e., i2 is 0, so the if statement is satisfied. When i is equal to 2, this happens and the number 2 is printed. Once this happens, the break statement within the if statement is executed, and the control flow exits the for loop, so no other number is printed. Therefore, the final output is: 2 . Response in Sesotho: Sephetho se lebelletsoeng ho tsoa khoutu ena ke nomoro e hatisitsoeng 2. Sena ke hobane khoutu e theha loop e pheta-phetoang ho feta boleng ba i ho tloha ho 1 ho isa ho 5. Ha boleng ba i bo lekana, karolo e setseng ea i ha e arotsoe ka 2 ke hore, i 2 ke 0, kahoo haeba polelo e khotsofetse. Ha ke lekana le 2, sena se etsahala mme nomoro ea 2 ea hatisoa. Hang ha sena se etsahala, polelo ea khefu ka hare ho haeba polelo e etsoa, me phallo ea taolo e tsoa bakeng sa loop, kahoo ha ho nomoro e ngoe e hatisoang. Ka hona, tlhahiso ea ho qetela ke: 2 