<prompt> Hlalosa matla a khoheli a pakeng tsa lintho tse peli tse nang le boima le sebaka.boima 20 kg le sebaka 2 limithara  <response>: Instruction in English: Describe the gravitational force between two objects with given mass and distance. . Response in English: The gravitational force between two objects is described by Isaac Newtons law of universal gravitation, which states that every point mass attracts every other point mass by a force acting along the line intersecting both points. The force is equal to the product of the two masses and inversely proportional to the square of the distance between their centers.Given the two objects have masses of 20 kg each and the distance between their centers is 2 meters, the gravitational force between them would be calculated as follows:F G m1 m2 d2where F is the gravitational force, G is the gravitational constant, m1 and m2 are the respective masses of the two objects, and d is the distance between their centers.The gravitational constant G is equal to 6.67430 × 10-11 Nm2kg2. Plugging in the given values into the equation, we get:F 6.67430 × 10-11 Nm2kg2 20 kg 20 kg 2 m2F 3.33715 × 10-9 NTherefore, the gravitational force between the two objects with masses of 20 kg each, separated by a distance of 2 meters, is approximately 3.33715 × 10-9 Newtons. . Response in Sesotho: Matla a khoheli a pakeng tsa lintho tse peli a hlalosoa ke molao oa Isaac Newton oa universal gravitation, o bolelang hore ntlha e ngoe le e ngoe ea boima e hohela ntlha e ngoe le e ngoe ea boima ka matla a sebetsang ho bapa le mola o haolang lintlha tseo ka bobeli. Matla a lekana le sehlahisoa sa matšoele a mabeli me a lekana ka tsela e fapaneng le sekwere sa sebaka se pakeng tsa litsi tsa bona. Kaha lintho tse peli li na le boima ba likhilograma tse 20 me sebaka se pakeng tsa litsi tsa tsona ke limithara tse peli, matla a khoheli pakeng tsa tsona a tla baloa ka tsela e latelang: F G m1 m2 d2 moo F e leng matla a khoheli. , G ke matla a khoheli, m1 le m2 ke bongata bo fapaneng ba lintho tse peli, me d ke sebaka se pakeng tsa litsi tsa tsona. Matla a khoheli a sa feleng a G a lekana le 6.67430 × 10-11 Nm2kg2. Ho kenya litekanyetso tse fanoeng ho equation, re fumana: F 6.67430 × 10-11 Nm2kg2 20 kg 20 kg 2 m2 F 3.33715 × 10 -9 N Ka hona, matla a khoheli pakeng tsa lintho tse peli tse nang le boima ba likhilograma tse 20 e ngoe le e ngoe, e arohaneng ka sebaka sa limithara tse 2, e ka ba 3.33715 × 10 -9 Newtons. 