Below is the list of tables from the database along with their columns and datatype. Need to generate an accurate SQL query for the question.
Only use the columns present in the respective table. Only use the columns which are required to generate the SQL query. Only use table joins if required and not otherwise.

### Tables ###
TABLE: CREATE TABLE locations (city VARCHAR, location_id VARCHAR)
TABLE: CREATE TABLE employees (first_name VARCHAR, last_name VARCHAR, department_id VARCHAR)
TABLE: CREATE TABLE departments (department_id VARCHAR, location_id VARCHAR)

### Question ###
display those employees who contain a letter z to their first name and also display their last name, city.

### Accurate SQL ###

SELECT T1.first_name, T1.last_name, T3.city FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id JOIN locations AS T3 ON T2.location_id = T3.location_id WHERE T1.first_name LIKE '%z%'