tensorflow_probability/python/distributions/internal/correlation_matrix_volumes_lib.py
def _psd_mask(x):
  """Computes whether each square matrix in the input is positive semi-definite.

  Args:
    x: A floating-point `Tensor` of shape `[B1, ..., Bn, M, M]`.

  Returns:
    mask: A floating-point `Tensor` of shape `[B1, ... Bn]`.  Each
      scalar is 1 if the corresponding matrix was PSD, otherwise 0.
  """
  # Allegedly
  # https://scicomp.stackexchange.com/questions/12979/testing-if-a-matrix-is-positive-semi-definite
  # it is more efficient to test for positive semi-definiteness by
  # trying to compute the Cholesky decomposition -- the matrix is PSD
  # if you succeed and not PSD if you fail.  However, TensorFlow's
  # Cholesky raises an exception if _any_ of the input matrices are
  # not PSD, from which I don't know how to extract _which ones_, so I
  # proceed by explicitly computing all the eigenvalues and checking
  # whether they are all positive or not.
  #
  # Also, as was discussed in the answer, it is somewhat dangerous to
  # treat SPD-ness as binary in floating-point arithmetic. Cholesky
  # factorization can complete and 'look' like everything is fine
  # (e.g., O(1) entries and a diagonal of all ones) but the matrix can
  # have an exponential condition number.
  eigenvalues, _ = tf.linalg.eigh(x)
  return tf.cast(
      tf.reduce_min(input_tensor=eigenvalues, axis=-1) >= 0, dtype=x.dtype)
def _psd_mask(x):
  # Allegedly
  # https://scicomp.stackexchange.com/questions/12979/testing-if-a-matrix-is-positive-semi-definite
  # it is more efficient to test for positive semi-definiteness by
  # trying to compute the Cholesky decomposition -- the matrix is PSD
  # if you succeed and not PSD if you fail.  However, TensorFlow's
  # Cholesky raises an exception if _any_ of the input matrices are
  # not PSD, from which I don't know how to extract _which ones_, so I
  # proceed by explicitly computing all the eigenvalues and checking
  # whether they are all positive or not.
  #
  # Also, as was discussed in the answer, it is somewhat dangerous to
  # treat SPD-ness as binary in floating-point arithmetic. Cholesky
  # factorization can complete and 'look' like everything is fine
  # (e.g., O(1) entries and a diagonal of all ones) but the matrix can
  # have an exponential condition number.
  eigenvalues, _ = tf.linalg.eigh(x)
  return tf.cast(
      tf.reduce_min(input_tensor=eigenvalues, axis=-1) >= 0, dtype=x.dtype)
def _psd_mask ( x ) : # Allegedly # https://scicomp.stackexchange.com/questions/12979/testing-if-a-matrix-is-positive-semi-definite # it is more efficient to test for positive semi-definiteness by # trying to compute the Cholesky decomposition -- the matrix is PSD # if you succeed and not PSD if you fail.  However, TensorFlow's # Cholesky raises an exception if _any_ of the input matrices are # not PSD, from which I don't know how to extract _which ones_, so I # proceed by explicitly computing all the eigenvalues and checking # whether they are all positive or not. # # Also, as was discussed in the answer, it is somewhat dangerous to # treat SPD-ness as binary in floating-point arithmetic. Cholesky # factorization can complete and 'look' like everything is fine # (e.g., O(1) entries and a diagonal of all ones) but the matrix can # have an exponential condition number. eigenvalues , _ = tf . linalg . eigh ( x ) return tf . cast ( tf . reduce_min ( input_tensor = eigenvalues , axis = - 1 ) >= 0 , dtype = x . dtype )
Computes whether each square matrix in the input is positive semi-definite.

  Args:
    x: A floating-point `Tensor` of shape `[B1, ..., Bn, M, M]`.

  Returns:
    mask: A floating-point `Tensor` of shape `[B1, ... Bn]`.  Each
      scalar is 1 if the corresponding matrix was PSD, otherwise 0.
Computes whether each square matrix in the input is positive semi - definite .