ผู้ตอบถูกที่สุดตามเปอร์เซ็นต์ที่ยอมรับ ไม่จำเป็นต้องใช้ตารางทั้งหมด
Top Answerers by Accepted Percentage.It is not neccessary to use all the tables.
 ReviewRejectionReasons:  Id [ number]  Name [ text]  Description [ text]  PostTypeId [ number] 
SELECT A.OwnerUserId AS "user_link", (CAST(COUNT(A.Id) AS FLOAT) / (SELECT COUNT(*) FROM Posts WHERE OwnerUserId = A.OwnerUserId AND PostTypeId = 2) * 100) AS AcceptedPercent FROM Posts AS A INNER JOIN Posts AS Q ON Q.AcceptedAnswerId = A.Id WHERE A.PostTypeId = 2 AND (SELECT COUNT(*) FROM Posts WHERE PostTypeId = 2 AND OwnerUserId = A.OwnerUserId) > 100 GROUP BY A.OwnerUserId ORDER BY 'acceptedpercent' DESC LIMIT @N