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  license: cc-by-2.0
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  ---
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- # A Combinatorial Interpretation of Schubert Polynomial Structure Constants (Open Problem)
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-
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- ![Schubert polynomial task graphic](https://github.com/pnnl/ML4AlgComb/blob/master/schubert_polynomial_structure/fig-schubert-polynomials.png)
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-
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- Schubert polynomials \[1,2,3\] are a family of polynomials indexed by permutations of $S_n$. Developed to study the cohomology ring of the flag variety, they have deep connections to algebraic geometry, Lie theory, and representation theory. Despite their geometric origins, Schubert polynomials can be described combinatorially \[4,5\], making them a well-studied object in algebraic combinatorics. An important open problem in the study of Schubert polynomials is understanding their *structure constants*.
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-
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- When two Schubert polynomials $\mathfrak{S}\_{\alpha}$ and $\mathfrak{S}\_{\beta}$ (indexed by permutations $\alpha \in S_n$ and $\beta \in S_m$) are multiplied, their product can be written as a linear combination of Schubert polynomials
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- $\mathfrak{S}\_{\alpha} \mathfrak{S}\_{\beta} = \sum\_{\gamma} c^{\gamma}\_{\alpha \beta} \mathfrak{S}\_{\gamma}$. Where the sum runs over permutations in $S_{n+m}$.
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- The question is whether the $c^{\gamma}\_{\alpha \beta}$ (the *structure constants*) have a combinatorial interpretation. To give an example of what we mean by combinatorial interpretation, when Schur polynomials (which can be viewed as a specific case of Schubert polynomials) are multiplied together, the coefficients in the resulting product are equal to the number of semistandard tableaux satisfying certain properties.
 
 
 
 
 
 
 
 
 
 
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  ## Example
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- We multiply Schubert polynomials corresponding to permutations of $\\{1,2,3\\}$, $\alpha = 2 1 3$ and $\beta = 1 3 2$. Writing these in terms of indeterminants $x_1$, $x_2$, and $x_3$, we have $\mathfrak{S}\_{\alpha} = x_1 + x_2$ and $\mathfrak{S}\_{\beta} = x_1$. Multiplying these together we get
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- $\mathfrak{S}_{\alpha}\mathfrak{S}\_{\beta} = x_1^2 + x_1x_2$. As $\mathfrak{S}\_{2 3 1} = x\_1x\_2$ and $\mathfrak{S}\_{3 1 2} = x\_1^2$ we can write $\mathfrak{S}\_{\alpha}\mathfrak{S}\_{\beta} = \mathfrak{S}\_{2 3 1} + \mathfrak{S}\_{3 1 2}$. It follows that $c\_{\alpha,\beta}^{\gamma} = 1$ if $\gamma = 2 3 1$ or $\gamma = 3 1 2$ and otherwise $c\_{\alpha,\beta}^{\gamma} = 0$.
 
 
 
 
 
 
 
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  ## Dataset
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- Each instance in this dataset is a triple of permutations $(\alpha,\beta,\gamma)$, labeled by its coefficient $c^{\gamma}\_{\alpha \beta}$ in the expansion of the product $\mathfrak{S}\_{\alpha} \mathfrak{S}\_{\beta}$. The datasets are organized so that $\alpha$ and $\beta$ are always drawn from the symmetric group on $n$ elements (we provide datasets for $n = 3$, $4$, and $5$), but $\gamma$ may belong to a strictly larger symmetric group. Not all possible triples of permutations are included since the vast majority of these would be zero. The dataset consists of an approximately equal number of zero and nonzero coefficients (but they are not balanced between quantities of non-zero coefficients). We provide datasets for $n = 4, 5, 6$ [here](https://drive.google.com/file/d/15bERRWWue-3gKSir3hVhfejNTeZJgsl9/view?usp=sharing).
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-
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- Each line in the file corresponds to a structure constant so that
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- `([1,2,3,5,4],[1,2,3,5,4],[1,2,3,6,4,5];1)`
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- means that $c^{1 2 3 6 4 5}_{1 2 3 5 4,1 2 3 5 4} = 1$ or that in the expansion of the product $\mathfrak{S}\_{1 2 3 5 4} \mathfrak{S}\_{1 2 3 5 4}$, $\mathfrak{S}\_{1 2 3 6 4 5}$ has a coefficient of 1. To the point above, this instance is from $n = 5$ but note that the third permutation actually belongs to $S_6$.
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-
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- The datasets can be loaded by: (1) unzipping the file found [here](https://drive.google.com/file/d/15bERRWWue-3gKSir3hVhfejNTeZJgsl9/view?usp=sharing) in your chosen `directory`, (2) choosing a value for $n$ (4, 5, 6), and then (3) running the following commands (here we choose $n = 5$)
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-
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- ```
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- import numpy as np
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- import load_datasets
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-
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- folder = # provide the file path to the directory you chose here
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- X = load_datasets.get_dataset('schubert', n=5, folder = folder)
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- ```
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-
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- The basic statistics of the datasets are as follows
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-
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- ### Permutations of size $4$
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  All structure constants in this case are either 0 or 1 (so the classification problem is binary).
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@@ -45,7 +56,6 @@ All structure constants in this case are either 0 or 1 (so the classification pr
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  | Train | 851 | 833 | 1,684 |
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  | Test | 201 | 220 | 421 |
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- ### Permutations of size $5$
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  All structure constants in this case are either 0, 1, or 2.
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@@ -54,7 +64,6 @@ All structure constants in this case are either 0, 1, or 2.
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  | Train | 42,831 | 42,619 | 170 | 85,620 |
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  | Test | 10,681 | 10,680 | 44 | 21,405 |
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- ### Permutations of size $6$
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  All structure constants in this case are either 0, 1, 2, 3, 4, or 5.
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@@ -65,27 +74,30 @@ All structure constants in this case are either 0, 1, 2, 3, 4, or 5.
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  ## Data generation
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- The Sage notebook within this directory gives the code used to generate these datasets. The process involves:
 
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- - For a chosen $n$, compute the products $\mathfrak{S}\_{\alpha} \mathfrak{S}\_{\beta}$ for $\alpha,\beta \in S_n$.
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- - For each of these pairs, extract and add to the dataset all non-zero structure constants $c^{\gamma_1}\_{\alpha,\beta}, \dots, c^{\gamma_k}\_{\alpha,\beeta}$
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- - Furthermore, for each $c^{\gamma_i}\_{\alpha,\beta} \neq 0$, randomly permute $\gamma_i \mapsto \gamma_i'$ to find $c^{\gamma_i'}\_{\alpha,\beta} = 0$ and $c^{\gamma_i'}\_{\alpha,\beta}$ is not already in the dataset.
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  ## Task
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- **Math question:** Develop a better understanding of the structure constants of Schubert polynomials paying special attention to combinatorial interpretations by focusing on the triples of permutations that index them.
 
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- **ML task:** Train a model that, given three permutations $\alpha, \beta, \gamma$, can predict the associated structure constant $c^{\gamma}\_{\alpha,\beta}$.
 
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  ## Small model performance
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  | Size | Logistic regression | MLP | Transformer | Guessing majority class |
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  |----------|----------|-----------|------------|------------|
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- | $n= 4$ | $88.8\\%$ | $93.1\\% \pm 2.6\\%$ | $94.6\\% \pm 1.0\\%$| $52.3\\%$ |
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- | $n= 5$ | $90.6\\%$ | $97.5\\% \pm 0.2\\%$ | $96.2\\% \pm 1.1\\%$| $49.9\\%$ |
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- | $n= 6$ | $89.7\\%$ | $99.8\\% \pm 0.0\\%$ | $91.3\\% \pm 8.0\\%$| $50.1\\%$ |
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- The $\pm$ signs indicate 95% confidence intervals from random weight initialization and training.
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  ## References
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  license: cc-by-2.0
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  ---
4
 
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+ # A Combinatorial Interpretation of Schubert Polynomial Structure Constants
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+
7
+ Schubert polynomials [1,2,3] are a family of polynomials indexed by permutations of \\(S_n\\).
8
+ Developed to study the cohomology ring of the flag variety, they have deep connections to
9
+ algebraic geometry, Lie theory, and representation theory. Despite their geometric origins,
10
+ Schubert polynomials can be described combinatorially [4,5], making them a well-studied object
11
+ in algebraic combinatorics. An important open problem in the study of Schubert polynomials
12
+ is understanding their *structure constants*.
13
+
14
+ When two Schubert polynomials \\(\mathfrak{S}_{\alpha}\\) and \\(\mathfrak{S}_{\beta}\\)
15
+ (indexed by permutations \\(\alpha \in S_n\\) and \\(\beta \in S_m\\)) are multiplied,
16
+ their product can be written as a linear combination of Schubert polynomials
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+ \\(\mathfrak{S}_{\alpha} \mathfrak{S}_{\beta} = \sum_{\gamma} c^{\gamma}_{\alpha \beta} \mathfrak{S}_{\gamma}\\).
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+ Where the sum runs over permutations in \\(S_{n+m}\\). The question is whether the
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+ \\(c^{\gamma}_{\alpha \beta}\\) (the *structure constants*) have a combinatorial interpretation.
20
+ To give an example of what we mean by combinatorial interpretation, when Schur polynomials
21
+ (which can be viewed as a specific case of Schubert polynomials) are multiplied together,
22
+ the coefficients in the resulting product are equal to the number of semistandard tableaux
23
+ satisfying certain properties.
24
 
25
  ## Example
26
 
27
+ We multiply Schubert polynomials corresponding to permutations of \\(\{1,2,3\}\\),
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+ \\(\alpha = 2 1 3\\) and \\(\beta = 1 3 2\\). Writing these in terms of indeterminants
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+ \\(x_1\\), \\(x_2\\), and \\(x_3\\), we have \\(\mathfrak{S}_{\alpha} = x_1 + x_2\\)
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+ and \\(\mathfrak{S}_{\beta} = x_1\\). Multiplying these together we get
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+ \\(\mathfrak{S}_{\alpha}\mathfrak{S}_{\beta} = x_1^2 + x_1x_2\\). As
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+ \\(\mathfrak{S}_{2 3 1} = x_1x_2\\) and \\(\mathfrak{S}_{3 1 2} = x_1^2\\) we can write
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+ \\(\mathfrak{S}_{\alpha}\mathfrak{S}_{\beta} = \mathfrak{S}_{2 3 1} + \mathfrak{S}_{3 1 2}\\).
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+ It follows that \\(c_{\alpha,\beta}^{\gamma} = 1\\) if \\(\gamma = 2 3 1\\) or \\(\gamma = 3 1 2\\)
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+ and otherwise \\(c_{\alpha,\beta}^{\gamma} = 0\\).
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  ## Dataset
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+ Each instance in this dataset is a triple of permutations \\((\alpha,\beta,\gamma)\\),
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+ labeled by its coefficient \\(c^{\gamma}_{\alpha \beta}\\) in the expansion of the product
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+ \\(\mathfrak{S}_{\alpha} \mathfrak{S}_{\beta}\\). We call permutations \\(\alpha\\) and \\(\beta\\)
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+ *lower index permutations 1* and *2* respectively. We call \\(\gamma\)) the *upper index
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+ permutation*. The datasets are organized so that
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+ \\(\alpha\\) and \\(\beta\\) are always drawn from the symmetric group on \\(n\\) elements
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+ (we provide datasets for \\(n = 3\\), \\(4\\), and \\(5\\)), but \\(\gamma\\) may belong to a
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+ strictly larger symmetric group. Not all possible triples of permutations are included
46
+ since the vast majority of these would be zero. The dataset consists of an approximately
47
+ equal number of zero and nonzero coefficients (but they are not balanced between quantities
48
+ of non-zero coefficients).
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+
50
+ **Statistics**
 
 
 
 
 
 
51
 
52
  All structure constants in this case are either 0 or 1 (so the classification problem is binary).
53
 
 
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  | Train | 851 | 833 | 1,684 |
57
  | Test | 201 | 220 | 421 |
58
 
 
59
 
60
  All structure constants in this case are either 0, 1, or 2.
61
 
 
64
  | Train | 42,831 | 42,619 | 170 | 85,620 |
65
  | Test | 10,681 | 10,680 | 44 | 21,405 |
66
 
 
67
 
68
  All structure constants in this case are either 0, 1, 2, 3, 4, or 5.
69
 
 
74
 
75
  ## Data generation
76
 
77
+ The Sage notebook within this directory gives the code used to generate these datasets.
78
+ The process involves:
79
 
80
+ - For a chosen \\(n\\), compute the products \\(\mathfrak{S}_{\alpha} \mathfrak{S}_{\beta}\\) for \\(\alpha,\beta \in S_n\\).
81
+ - For each of these pairs, extract and add to the dataset all non-zero structure constants \\(c^{\gamma_1}_{\alpha,\beta}, \dots, c^{\gamma_k}_{\alpha,\beta}\\)
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+ - Furthermore, for each \\(c^{\gamma_i}_{\alpha,\beta} \neq 0\\), randomly permute \\(\gamma_i \mapsto \gamma_i'\\) to find \\(c^{\gamma_i'}_{\alpha,\beta} = 0\\) and \\(c^{\gamma_i'}_{\alpha,\beta}\\) is not already in the dataset.
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  ## Task
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+ **Math question:** Find a combinatorial interpretation of the structure constants \\(c_{\alpha,\beta}^\gamma\))
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+ based on properties of \\(\alpha\\), \\(\beta\\), and \\(\gamma\\).
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+ **Narrow ML task:** Train a model that, given three permutations \\(\alpha, \beta, \gamma\\), can
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+ predict the associated structure constant \\(c^{\gamma}_{\alpha,\beta}\\).
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92
  ## Small model performance
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94
  | Size | Logistic regression | MLP | Transformer | Guessing majority class |
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  |----------|----------|-----------|------------|------------|
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+ | \\(n= 4\\) | \\(88.8\%\\) | \\(93.1\% \pm 2.6\%\\) | \\(94.6\% \pm 1.0\%\\) | \\(52.3\%\\) |
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+ | \\(n= 5\\) | \\(90.6\%\\) | \\(97.5\% \pm 0.2\%\\) | \\(96.2\% \pm 1.1\%\\) | \\(49.9\%\\) |
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+ | \\(n= 6\\) | \\(89.7\%\\) | \\(99.8\% \pm 0.0\%\\) | \\(91.3\% \pm 8.0\%\\) | \\(50.1\%\\) |
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100
+ The \\(\pm\\) signs indicate 95% confidence intervals from random weight initialization and training.
101
 
102
  ## References
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