To find $f(g(-5))$, I need to first plug in $-5$ into the function $g(x)$ and simplify. Then I need to plug in the result into the function $f(x)$ and simplify again. So, let me start with $g(-5) = 5(-5) + 2(-5)^2$. This equals $-25 + 50 = 25$. So, $g(-5) = 25$. Now, I can plug this into $f(x) = 3 - \!\sqrt{x}$ and get $f(g(-5)) = f(25)$. This equals $3 - \!\sqrt{25}$. And I know that $\sqrt{25} = 5$, so this equals $3 - 5 = -2$. Therefore, $f(g(-5)) = -2$. 
If $f(x) = 3-\!\sqrt{x}$ and $g(x) = 5x +2x^2$, what is $f(g(-5))$?