To find the probability of winning at least once in four attempts, we can use the complementary probability. The complementary probability is the probability of an event not occurring, which is equal to 1 minus the probability of the event occurring.

In this case, the complementary probability would be the probability of losing all four games. If there's a 25% chance of winning, then there's a 75% chance of losing:

Probability of losing = 1 - Probability of winning
                                 = 1 - 0.25
                                 = 0.75

Now, let's calculate the probability of losing all four games:

Probability of losing all four games = (Probability of losing)^4
                                                       = (0.75)^4
                                                       ≈ 0.3164

Finally, to find the probability of winning at least once, we subtract the probability of losing all four games from 1:

Probability of winning at least once = 1 - Probability of losing all four games
                                                        = 1 - 0.3164
                                                        ≈ 0.6836

So, the probability of winning at least once in four attempts is approximately 0.6836 or 68.36%.
If you have a 25% chance of winning a game, what is the probability that you will win at least once in four attempts?