So first, we need to find the probability of one student being absent while the other is present. Yes. So the probability of the first student being absent is 1/30 and the probability of the second student being present is 29/30. And the probability of one student being present is $29/30$. But we need to multiply them together because they both need to happen. But we need to do that for both students, so we multiply by two to get $58/900$. And to express that as a percent, we divide by 9 and multiply by 100 to get $6.44$. Round that to the nearest tenth to get $6.4$.


In Ms. Smith's class, each student averages one day absent out of thirty. What is the probability that out of any two students chosen at random, one student will be absent while the other is present? Express your answer as a percent rounded to the nearest tenth.