I need to find the possible values of $x$ that satisfy the given equation. To do that, I can try to simplify the equation and solve for $x$. First, I can expand the left side using the distributive property: $x^2 + 2x - 3x - 6 = 14$. Then, I can combine like terms and subtract 14 from both sides: $x^2 - x - 20 = 0$. Now, I have a quadratic equation that I can try to factor. I look for two numbers that multiply to -20 and add to -1. I can see that -5 and 4 are such numbers, so I can write: $(x-5)(x+4) = 0$. Then, by the zero product property, I know that either $x-5 = 0$ or $x+4 = 0$. This gives me two possible values of $x$: $x = 5$ or $x = -4$. The question asks me to find the product of the possible values of $x$, so I just multiply them together: $5 \times -4 = -20$. 
If $(x+2)(x-3)=14$, find the product of the possible values of $x$.