I need to find the product of all real x that make the ratios equal. I can start by cross-multiplying and simplifying the equation. If I cross-multiply, I get $(x+2)(7x+3) = (2x+2)(4x+3)$. Expanding the brackets, I get $7x^2 + 17x + 6 = 8x^2 + 14x + 6$. Subtracting $7x^2 + 17x + 6$ from both sides, I get $0 = x^2 - 3x$. Factoring out x, I get $0 = x(x-3)$. This means that either $x = 0$ or $x-3 = 0$. So the possible values of x are $x = 0$ or $x = 3$. To find the product of these values, I just multiply them together. I get $0 \times 3 = 0$. 
The ratio of $x+2$ to $2x+2$ is equal to the ratio of $4x+3$ to $7x+3$.  What is the product of all real x which satisfy this statement?