For the first term, $3\cdot 9$, I can use the multiplication table to find that this is equal to 27. For the second term, $4\cdot 10$, I can use the distributive property to write this as $4\cdot (5+5) = 4\cdot 5 + 4\cdot 5 = 20 + 20 = 40$. For the third term, $11\cdot 3$, I can use the distributive property again to write this as $10\cdot 3 + 1\cdot 3 = 30 + 3 = 33$. For the fourth term, $3\cdot 8$, I can use the multiplication table again to find that this is equal to 24. Now I have simplified the expression to $27+40+33+24$. To add these numbers, I can line them up by their place values and add from right to left, carrying over when needed. I get $27+40+33+24 = 124$. 
What is $3\cdot 9+4\cdot 10+11\cdot 3+3\cdot 8$?