To solve for $x$, I want to isolate it on one side of the equation by using inverse operations. First, I notice that the fractions on both sides have different denominators, so it might be helpful to find a common denominator to simplify them. The least common denominator of 2, x, and 6 is 6x, so I can multiply both sides of the equation by 6x to clear the fractions. This gives me $6x \cdot \dfrac{1}{2} + 6x \cdot \dfrac{1}{x} = 6x \cdot \dfrac{5}{6}$. Simplifying the terms, I get $3x + 6 = 5x$. Now I have a linear equation in $x$, and I can use the properties of equality to solve it. I want to get all the $x$ terms on one side and all the constants on the other, so I can subtract $3x$ from both sides. This gives me $6 = 2x$. To find $x$, I can divide both sides by 2. This gives me $x = 3$. To check my answer, I can plug it back into the original equation and see if it makes it true. So I have $\dfrac{1}{2} + \dfrac{1}{3} = \dfrac{5}{6}$. To verify this, I can find a common denominator of 6 for the fractions on the left side. This gives me $\dfrac{3}{6} + \dfrac{2}{6} = \dfrac{5}{6}$. Since this is true, I know that $x = 3$ is the correct solution. 
Solve for $x$: $\dfrac{1}{2} + \dfrac{1}{x} = \dfrac{5}{6}$.