To evaluate a logarithm, I need to find the exponent that I have to raise the base to, in order to get the argument of the log. So, I'm looking for the value of $x$ that satisfies $5^x = \frac{1}{625}$. I notice that $625$ is a power of $5$, namely $5^4$. So, I can rewrite the equation as $5^x = \frac{1}{5^4}$. To get the same base on both sides, I can use the exponent rule that says $\frac{1}{a^b} = a^{-b}$. So, I get $5^x = 5^{-4}$. Now, I can see that the exponents must be equal for the equation to hold, so $x = -4$. Therefore, the logarithm I want to find is $\log_5\frac{1}{625} = -4$. 
Evaluate $\log_5\frac{1}{625}$.