I notice that the denominator of the fraction, 125, is a power of 5: $125 = 5^3$. This means that I can write the fraction as $\frac{11}{5^3}$. To convert a fraction with a power of 5 in the denominator to a decimal, I can multiply the numerator and the denominator by a power of 2 that makes the denominator a power of 10. In this case, I need to multiply by $2^3 = 8$, since $5^3 \times 2^3 = 10^3$. This gives me $\frac{11 \times 8}{10^3} = \frac{88}{1000}$. Now I can see that the decimal expansion is $0.088$, and it terminates because there are no more digits after the last nonzero one.


Find the terminating decimal expansion of $\frac{11}{125}$.