This problem involves complex numbers and their absolute values, also known as moduli. I recall that the absolute value of a complex number $a+bi$ is the same as the magnitude of the vector from the origin to the point $(a,b)$ on the complex plane. I also recall that the magnitude of a vector can be found using the Pythagorean theorem, so $|a+bi|=\sqrt{a^2+b^2}$. To find the absolute value of a product of complex numbers, I can use the fact that $|zw|=|z||w|$ for any complex numbers $z$ and $w$. Therefore, I can write $|(4\sqrt{2}-4i)(\sqrt{3}+3i)|=|(4\sqrt{2}-4i)||(\sqrt{3}+3i)|$. Now I just need to find the absolute values of the two factors separately. For the first factor, I have $|4\sqrt{2}-4i|=\sqrt{(4\sqrt{2})^2+(-4)^2}$. I can simplify this by squaring the terms inside the parentheses: $|4\sqrt{2}-4i|=\sqrt{32+16}$. Adding these, I get $|4\sqrt{2}-4i|=\sqrt{48}$. I can simplify this further by factoring out a perfect square: $|4\sqrt{2}-4i|=\sqrt{16\cdot 3}$. Taking the square root of 16, I get $|4\sqrt{2}-4i|=4\sqrt{3}$. For the second factor, I have $|\sqrt{3}+3i|=\sqrt{(\sqrt{3})^2+(3)^2}$. I can simplify this by squaring the terms inside the parentheses: $|\sqrt{3}+3i|=\sqrt{3+9}$. Adding these, I get $|\sqrt{3}+3i|=\sqrt{12}$. I can simplify this further by factoring out a perfect square: $|\sqrt{3}+3i|=\sqrt{4\cdot 3}$. Taking the square root of 4, I get $|\sqrt{3}+3i|=2\sqrt{3}$. Now I have both absolute values, and I can multiply them to get the final answer. I have $|(4\sqrt{2}-4i)(\sqrt{3}+3i)|=|(4\sqrt{2}-4i)||(\sqrt{3}+3i)|=4\sqrt{3}\cdot 2\sqrt{3}$. I can multiply the constants and the square roots separately: $|(4\sqrt{2}-4i)(\sqrt{3}+3i)|=4\cdot 2\cdot \sqrt{3}\cdot \sqrt{3}$. I can simplify this by multiplying 4 and 2, and squaring the square root of 3: $|(4\sqrt{2}-4i)(\sqrt{3}+3i)|=8\cdot 3$. I can multiply 8 and 3 to get the final answer: $|(4\sqrt{2}-4i)(\sqrt{3}+3i)|=24$. 
Evaluate $|(4\sqrt{2}-4i)(\sqrt{3}+3i)|$